Big O definition: The Big O definitions for “f 1 (n)” and “f 2 (n)” are shown below: The function “f 1 (n)” is O(g 1 (n) if positive numbers “c 1 ” and “N 1 ” exists such that f 1 ( n ) ≤ c 1 g 1 ( n ) for all n ≥ N 1 . The function “f 2 (n)” is O(g 2 (n) if positive numbers “c 2 ” and “N 2 ” exists such that f 2 ( n ) ≤ c 2 g 2 ( n ) for all n ≥ N 2 .

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Answer 1

Question

Chapter 2, Problem 2E

Program Plan Intro

Big O definition:

The Big O definitions for “f₁(n)” and “f₂(n)” are shown below:

The function “f₁(n)” is O(g₁(n) if positive numbers “c₁” and “N₁” exists such that f1(n)≤c1g1(n) for all n≥N1.

The function “f₂(n)” is O(g₂(n) if positive numbers “c₂” and “N₂” exists such that f2(n)≤c2g2(n) for all n≥N2.

Explanation of Solution

(b) O(g1(n)+g2(n)) is O(g2(n))

Let g1(n)≤g2(n) and c=max(c1,c2).

Multiply both sides of equation by constant “c” to obtain cg1(n)≤cg2(n)

Explanation of Solution

(c) f1(n).f2(n) is O(g1(n).g2(n))

The product rule, f1(n).f2(n) is O(g1(n)

Explanation of Solution

(d) O(cg(n)) is O(g(n))

The statement O(cg(n)) is O(g(n)) means that any function “f” which is O(cg) is also O(g)

Explanation of Solution

(e) “c” is O(1)

A constant “c” is O(1) if positive numbers “c₁” and “N” exists such that c≤c1.1 for all n≥N

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Answer 2

Question

Chapter 2, Problem 2E

Program Plan Intro

Big O definition:

The Big O definitions for “f₁(n)” and “f₂(n)” are shown below:

The function “f₁(n)” is O(g₁(n) if positive numbers “c₁” and “N₁” exists such that f1(n)≤c1g1(n) for all n≥N1.

The function “f₂(n)” is O(g₂(n) if positive numbers “c₂” and “N₂” exists such that f2(n)≤c2g2(n) for all n≥N2.

Explanation of Solution

(b) O(g1(n)+g2(n)) is O(g2(n))

Let g1(n)≤g2(n) and c=max(c1,c2).

Multiply both sides of equation by constant “c” to obtain cg1(n)≤cg2(n)

Explanation of Solution

(c) f1(n).f2(n) is O(g1(n).g2(n))

The product rule, f1(n).f2(n) is O(g1(n)

Explanation of Solution

(d) O(cg(n)) is O(g(n))

The statement O(cg(n)) is O(g(n)) means that any function “f” which is O(cg) is also O(g)

Explanation of Solution

(e) “c” is O(1)

A constant “c” is O(1) if positive numbers “c₁” and “N” exists such that c≤c1.1 for all n≥N

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Answer 3

Question

Chapter 2, Problem 2E

Program Plan Intro

Big O definition:

The Big O definitions for “f₁(n)” and “f₂(n)” are shown below:

The function “f₁(n)” is O(g₁(n) if positive numbers “c₁” and “N₁” exists such that f1(n)≤c1g1(n) for all n≥N1.

The function “f₂(n)” is O(g₂(n) if positive numbers “c₂” and “N₂” exists such that f2(n)≤c2g2(n) for all n≥N2.

Explanation of Solution

(b) O(g1(n)+g2(n)) is O(g2(n))

Let g1(n)≤g2(n) and c=max(c1,c2).

Multiply both sides of equation by constant “c” to obtain cg1(n)≤cg2(n)

Explanation of Solution

(c) f1(n).f2(n) is O(g1(n).g2(n))

The product rule, f1(n).f2(n) is O(g1(n)

Explanation of Solution

(d) O(cg(n)) is O(g(n))

The statement O(cg(n)) is O(g(n)) means that any function “f” which is O(cg) is also O(g)

Explanation of Solution

(e) “c” is O(1)

A constant “c” is O(1) if positive numbers “c₁” and “N” exists such that c≤c1.1 for all n≥N

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Answer 4

Question

Chapter 2, Problem 2E

Program Plan Intro

Big O definition:

The Big O definitions for “f₁(n)” and “f₂(n)” are shown below:

The function “f₁(n)” is O(g₁(n) if positive numbers “c₁” and “N₁” exists such that f1(n)≤c1g1(n) for all n≥N1.

The function “f₂(n)” is O(g₂(n) if positive numbers “c₂” and “N₂” exists such that f2(n)≤c2g2(n) for all n≥N2.

Explanation of Solution

(b) O(g1(n)+g2(n)) is O(g2(n))

Let g1(n)≤g2(n) and c=max(c1,c2).

Multiply both sides of equation by constant “c” to obtain cg1(n)≤cg2(n)

Explanation of Solution

(c) f1(n).f2(n) is O(g1(n).g2(n))

The product rule, f1(n).f2(n) is O(g1(n)

Explanation of Solution

(d) O(cg(n)) is O(g(n))

The statement O(cg(n)) is O(g(n)) means that any function “f” which is O(cg) is also O(g)

Explanation of Solution

(e) “c” is O(1)

A constant “c” is O(1) if positive numbers “c₁” and “N” exists such that c≤c1.1 for all n≥N

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Answer 5

Chapter 2, Problem 2E

Program Plan Intro

Big O definition:

The Big O definitions for “f₁(n)” and “f₂(n)” are shown below:

The function “f₁(n)” is O(g₁(n) if positive numbers “c₁” and “N₁” exists such that f1(n)≤c1g1(n) for all n≥N1.

The function “f₂(n)” is O(g₂(n) if positive numbers “c₂” and “N₂” exists such that f2(n)≤c2g2(n) for all n≥N2.

Explanation of Solution

(b) O(g1(n)+g2(n)) is O(g2(n))

Let g1(n)≤g2(n) and c=max(c1,c2).

Multiply both sides of equation by constant “c” to obtain cg1(n)≤cg2(n)

Explanation of Solution

(c) f1(n).f2(n) is O(g1(n).g2(n))

The product rule, f1(n).f2(n) is O(g1(n)

Explanation of Solution

(d) O(cg(n)) is O(g(n))

The statement O(cg(n)) is O(g(n)) means that any function “f” which is O(cg) is also O(g)

Explanation of Solution

(e) “c” is O(1)

A constant “c” is O(1) if positive numbers “c₁” and “N” exists such that c≤c1.1 for all n≥N

Answer 6

Chapter 2, Problem 2E

Program Plan Intro

Big O definition:

The Big O definitions for “f₁(n)” and “f₂(n)” are shown below:

The function “f₁(n)” is O(g₁(n) if positive numbers “c₁” and “N₁” exists such that f1(n)≤c1g1(n) for all n≥N1.

The function “f₂(n)” is O(g₂(n) if positive numbers “c₂” and “N₂” exists such that f2(n)≤c2g2(n) for all n≥N2.

Answer 7

Chapter 2, Problem 2E

Program Plan Intro

Big O definition:

The Big O definitions for “f₁(n)” and “f₂(n)” are shown below:

The function “f₁(n)” is O(g₁(n) if positive numbers “c₁” and “N₁” exists such that f1(n)≤c1g1(n) for all n≥N1.

The function “f₂(n)” is O(g₂(n) if positive numbers “c₂” and “N₂” exists such that f2(n)≤c2g2(n) for all n≥N2.

Answer 8

Explanation of Solution

(b) O(g1(n)+g2(n)) is O(g2(n))

Let g1(n)≤g2(n) and c=max(c1,c2).

Multiply both sides of equation by constant “c” to obtain cg1(n)≤cg2(n)

Answer 9

Explanation of Solution

(b) O(g1(n)+g2(n)) is O(g2(n))

Let g1(n)≤g2(n) and c=max(c1,c2).

Multiply both sides of equation by constant “c” to obtain cg1(n)≤cg2(n)

Answer 10

Explanation of Solution

(c) f1(n).f2(n) is O(g1(n).g2(n))

The product rule, f1(n).f2(n) is O(g1(n)

Answer 11

Explanation of Solution

(c) f1(n).f2(n) is O(g1(n).g2(n))

The product rule, f1(n).f2(n) is O(g1(n)

Answer 12

Explanation of Solution

(d) O(cg(n)) is O(g(n))

The statement O(cg(n)) is O(g(n)) means that any function “f” which is O(cg) is also O(g)

Answer 13

Explanation of Solution

(d) O(cg(n)) is O(g(n))

The statement O(cg(n)) is O(g(n)) means that any function “f” which is O(cg) is also O(g)

Answer 14

Explanation of Solution

(e) “c” is O(1)

A constant “c” is O(1) if positive numbers “c₁” and “N” exists such that c≤c1.1 for all n≥N

Answer 15

Explanation of Solution

(e) “c” is O(1)

A constant “c” is O(1) if positive numbers “c₁” and “N” exists such that c≤c1.1 for all n≥N

Answer 16

Expert Solution & Answer

Answer 17

Expert Solution & Answer

Answer 18

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Answer 19

Ch. 2 - Prob. 1E Ch. 2 - Prob. 2E Ch. 2 - Prob. 3E Ch. 2 - Prob. 4E Ch. 2 - Prob. 5E Ch. 2 - Prob. 6E Ch. 2 - Prob. 7E Ch. 2 - Prob. 8E Ch. 2 - Prob. 9E Ch. 2 - Prob. 10E

Solution Summary: The author explains the Big O notation, which is represented by the capital letter "O" not zero. It simply describes how fast the function grows or declines.

Concept explainers

Explanation of Solution

(b) O(g1(n)+g2(n)) is O(g2(n))

Let g1(n)≤g2(n) and c=max(c1,c2).

Multiply both sides of equation by constant “c” to obtain cg1(n)≤cg2(n)

Explanation of Solution

(c) f1(n).f2(n) is O(g1(n).g2(n))

The product rule, f1(n).f2(n) is O(g1(n)

Explanation of Solution

(d) O(cg(n)) is O(g(n))

The statement O(cg(n)) is O(g(n)) means that any function “f” which is O(cg) is also O(g)

Explanation of Solution

(e) “c” is O(1)

A constant “c” is O(1) if positive numbers “c₁” and “N” exists such that c≤c1.1 for all n≥N

Want to see the full answer?

Chapter 2 Solutions

Solution Summary: The author explains the Big O notation, which is represented by the capital letter "O" not zero. It simply describes how fast the function grows or declines.

Concept explainers

Explanation of Solution

(b) O(g1(n)+g2(n)) is O(g2(n)) Let g1(n)≤g2(n) and c=max(c1,c2). Multiply both sides of equation by constant “c” to obtain cg1(n)≤cg2(n)

Explanation of Solution

(c) f1(n).f2(n) is O(g1(n).g2(n)) The product rule, f1(n).f2(n) is O(g1(n)

Explanation of Solution

(d) O(cg(n)) is O(g(n)) The statement O(cg(n)) is O(g(n)) means that any function “f” which is O(cg) is also O(g)

Explanation of Solution

(e) “c” is O(1) A constant “c” is O(1) if positive numbers “c1” and “N” exists such that c≤c1.1 for all n≥N

Want to see the full answer?

Chapter 2 Solutions

(b) O(g1(n)+g2(n)) is O(g2(n))

Let g1(n)≤g2(n) and c=max(c1,c2).

Multiply both sides of equation by constant “c” to obtain cg1(n)≤cg2(n)

(c) f1(n).f2(n) is O(g1(n).g2(n))

The product rule, f1(n).f2(n) is O(g1(n)

(d) O(cg(n)) is O(g(n))

The statement O(cg(n)) is O(g(n)) means that any function “f” which is O(cg) is also O(g)

(e) “c” is O(1)

A constant “c” is O(1) if positive numbers “c₁” and “N” exists such that c≤c1.1 for all n≥N