Chapter 2, Problem 2.9P

Interpretation Introduction

Interpretation: The change in height/depth of different fluids needs to be calculated at the atmospheric pressure conditions.

Concept introduction: The change in pressure of fluid for any particular depth is given as,

  $\begin{array}{l}{\text{P-P}}_{\text{atm}}\text{=}\text{ρgh}\\ \text{h}\text{=}\frac{{\text{P-P}}_{\text{atm}}}{\text{ρg}}\mathrm{.......}(1)\end{array}$

  $\begin{array}{l}\text{P}\text{-}{\text{P}}_{\text{atm}}\text{= Change in pressure}\\ \text{ρ}\text{=}\text{Density}\text{of}\text{fluid}\\ \text{h}\text{=}\text{Depth}\text{change}\\ \text{g}\text{=}\text{Acceleration}\text{due}\text{to}\text{gravity}\text{=}\text{9}\text{.8}{\text{m/s}}^{\text{2}}\end{array}$