(a)
Interpretation:
The formulas for
Concept introduction:
The general rules for writing the common names of compounds of metals that form more than one ion are:
1) The root name of the metal is followed by the suffix
2)The root name of the metal is followed by the suffix
For writing the systematic name of the compound, a roman numeral within parentheses is written immediately after the name of the metal ion to indicate the charge on it.
(b)
Interpretation:
The formulas for lithium nitride, lithium nitrite, and lithium nitrate are to be determined.
Concept introduction:
The general rules for naming ionic compounds are as follows:
1) In ionic compounds, the cations are named before the anions.
2) In binary ionic compounds, the name of the cation is the same as the name of the metal. The name of the anion includes the root name of the non-metal and a suffix
3) In polyatomic ions in which a non-metal is bonded to one or more oxygen atoms. In two oxoanions in the family, the ion with fewer oxygen atoms has the non-metal root name and a suffix
(c)
Interpretation:
The formulas for strontium hydride and strontium hydroxide are to be determined.
Concept introduction:
The general rules for naming ionic compounds are as follows:
1) In ionic compounds, the cations are named before the anions.
2) In binary ionic compounds, the name of the cation is the same as the name of the metal. The name of the anion includes the root name of the non-metal and a suffix
(d)
Interpretation:
The formulas for magnesium oxide and
Concept introduction:
The general rules for writing the common names of compounds of metals that form more than one ion are:
1) The root name of the metal is followed by the suffix
2)The root name of the metal is followed by the suffix
For writing the systematic name of the compound, a roman numeral within parentheses is written immediately after the name of the metal ion to indicate the charge on it.
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Chapter 2 Solutions
CHEMISTRY:MOLEC NAT PRINT COMPANION
- Could you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but (color-coded) and step by step so I can understand it better? Thank you! I want to see what they are doingarrow_forwardCan you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.arrow_forward
- Part 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answerarrow_forwardPart 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet. water and benzene. What is the formal concentration of butanoic acid in each phase when 0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene 100 mL of a) at pit 5.00 b) at pH 9.00arrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 Group of answer choices 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forward
- Calculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 choices: 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
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