Chapter 2, Problem 2.8YT

Interpretation Introduction

Interpretation:

The volume of pellets in cubic millimeters for given mass and density, is to be calculated.

Concept Introduction:

Dimensional analysis is useful in the conversion of one unit to another.

To convert a quantity $a{u}_1$ from one unit to another, that is, $u_1\to u_2$, first write a conversion factor, $\frac{u_2}{u_1}$, then multiply the conversion factor with the given quantity $a{u}_1$ and cancel the units to get the quantity in the desired unit.

$a\cancel{u_1}\times \frac{u_2}{\cancel{u_1}}=a{u}_2$

The expression for density $\left(d\right)$ is as follows:

$d=\frac{m}{V}$

Here, $d$ is density, $m$ is the mass and $V$ is the volume.