Welding: Principles and Applications (MindTap Course List)
8th Edition
ISBN: 9781305494695
Author: Larry Jeffus
Publisher: Cengage Learning
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Chapter 2, Problem 26R
Describe an acceptable storage area for a cylinder of fuel gas.
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Chapter 2 Solutions
Welding: Principles and Applications (MindTap Course List)
Ch. 2 - What is the key to preventing accidents in a...Ch. 2 - Who is ultimately responsible for the welder’s...Ch. 2 - Describe the three classifications of burns.Ch. 2 - What emergency steps should be taken to treat...Ch. 2 - List the three types of light that may be present...Ch. 2 - Which type of light is the most likely to cause...Ch. 2 - What can be done on the job site to reduce the...Ch. 2 - What is the name of the eye burn that can occur in...Ch. 2 - In what two ways can ultraviolet light burn the...Ch. 2 - Why is it important to seek medical treatment for...
Ch. 2 - What fabric(s) are the best choice to wear as...Ch. 2 - Describe the ideal work shirt, pants, boots, and...Ch. 2 - Why is it unsafe to carry butane lighters or...Ch. 2 - What special protective items can be worn to...Ch. 2 - Why must eye protection be worn at all times in...Ch. 2 - What types of injuries can occur to the ears...Ch. 2 - What types of protection are available to protect...Ch. 2 - What types of information should be covered in a...Ch. 2 - Name two types of respirators and describe how...Ch. 2 - List the materials that can give off dangerous...Ch. 2 - Why must metal that has been used before be...Ch. 2 - Under what conditions can natural ventilation be...Ch. 2 - Name two advantages of recycling scrap metal.Ch. 2 - When must forced ventilation be used?Ch. 2 - Who must be provided with safety data sheets...Ch. 2 - Describe an acceptable storage area for a cylinder...Ch. 2 - How must high-pressure gas cylinders be stored so...Ch. 2 - What should be done with a leaking cylinder if the...Ch. 2 - Why is it important for acetylene cylinders to not...Ch. 2 - What is hot work?Ch. 2 - How far away should highly combustible materials...Ch. 2 - When is a fire watch needed?Ch. 2 - List the four types of fire extinguishers and the...Ch. 2 - Why is it important to have a planned maintenance...Ch. 2 - Why is it important to keep a welding area clean?Ch. 2 - What should you do if you have to leave a piece of...Ch. 2 - Why must a mushroomed chisel or hammer be...Ch. 2 - What causes most electric shock in the welding...Ch. 2 - According to the Welding Safety Checklist in...Ch. 2 - What can happen if too much power is being carried...Ch. 2 - Why must equipment be turned off and unplugged...Ch. 2 - According to Table 2-2, what gauge wire size would...Ch. 2 - What is a GFCI?Ch. 2 - List five safety tips for safe extension cord use.Ch. 2 - List 10 safety rules for the safe use of portable...Ch. 2 - Why is it important to not weld when everything is...Ch. 2 - List two types of grinders used by welders.Ch. 2 - How close to the grinding stone face should the...Ch. 2 - Name metal cutting machines used in the welding...Ch. 2 - Describe how a person should safely lift a heavy...Ch. 2 - List the things that should be inspected on a...Ch. 2 - List and explain five ladder use safety rules.
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- determine the direction and magnitude of angular velocity ω3 of link CD in the four-bar linkage using the relative velocity graphical methodarrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forward
- The evaporator of a vapor compression refrigeration cycle utilizing R-123 as the refrigerant isbeing used to chill water. The evaporator is a shell and tube heat exchanger with the water flowingthrough the tubes. The water enters the heat exchanger at a temperature of 54°F. The approachtemperature difference of the evaporator is 3°R. The evaporating pressure of the refrigeration cycleis 4.8 psia and the condensing pressure is 75 psia. The refrigerant is flowing through the cycle witha flow rate of 18,000 lbm/hr. The R-123 leaves the evaporator as a saturated vapor and leaves thecondenser as a saturated liquid. Determine the following:a. The outlet temperature of the chilled waterb. The volumetric flow rate of the chilled water (gpm)c. The UA product of the evaporator (Btu/h-°F)d. The heat transfer rate between the refrigerant and the water (tons)arrow_forward(Read image) (Answer given)arrow_forwardProblem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forward
- Problem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forwardProblem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forwardThe flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forward
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