(a)
Interpretation:
The given statement concerning 2-butene has to be identified as true or false.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
(b)
Interpretation:
The given statement concerning 2-butene has to be identified as true or false.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes are linear chain unsaturated hydrocarbons and cycloalkenes are cyclic carbon chain unsaturated hydrocarbons. They both occur naturally.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
(c)
Interpretation:
The given statement concerning 2-butene has to be identified as true or false.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes are linear chain unsaturated hydrocarbons and cycloalkenes are cyclic carbon chain unsaturated hydrocarbons. They both occur naturally.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
(d)
Interpretation:
The given statement concerning 2-butene has to be identified as true or false.
Concept Introduction:
Organic compounds are represented shortly by the molecular formula and structural formula. Each and every compound has its own molecular formula. Compounds can have same molecular formula but not same structural formula.
Alkenes are linear chain unsaturated hydrocarbons and cycloalkenes are cyclic carbon chain unsaturated hydrocarbons. They both occur naturally.
Alkenes and cycloalkenes are hydrocarbons. They are nonpolar molecules. Water is a polar molecule. Therefore, alkenes and cycloalkenes do not get solubilized in water. In other words, alkenes and cycloalkenes are insoluble in water.
Regarding density, alkenes and cycloalkenes have density lower than water. When alkenes and cycloalkenes are mixed with water, two layers are formed which is a result of insolubility. Alkenes and cycloalkenes are present on top of water layer which is due to lesser density.
Boiling point of alkenes and cycloalkenes increase with an increase in carbon‑chain length or the ring size. The continuous chain alkenes which contain two to four carbon atoms are gases at room temperature. The continuous chain alkenes that contain five to seventeen carbon atoms and one double bond are liquids at room temperature.
When branching happens in the carbon chain, it lowers the boiling point of alkenes. In simple words, unbranched alkenes have more boiling point than branched alkenes with the same number of carbon atoms.
Cycloalkenes have more boiling point compared to noncyclic alkenes with the same number of carbon atoms. This is due to the more rigid and more symmetrical structures that occur in cyclic systems. Cyclopropene and cyclobutene are relatively unstable compound and gets converted into other hydrocarbons.
Trending nowThis is a popular solution!
Chapter 2 Solutions
Organic And Biological Chemistry
- Don't used hand raitingarrow_forwardDon't used Ai solutionarrow_forwardSaved v Question: I've done both of the graphs and generated an equation from excel, I just need help explaining A-B. Below is just the information I used to get the graphs obtain the graph please help. Prepare two graphs, the first with the percent transmission on the vertical axis and concentration on the horizontal axis and the second with absorption on the vertical axis and concentration on the horizontal axis. Solution # Unknown Concentration (mol/L) Transmittance Absorption 9.88x101 635 0.17 1.98x101 47% 0.33 2.95x101 31% 0.51 3.95x10 21% 0.68 4.94x10 14% 24% 0.85 0.62 A.) Give an equation that relates either the % transmission or the absorption to the concentration. Explain how you arrived at your equation. B.) What is the relationship between the percent transmission and the absorption? C.) Determine the concentration of the ironlll) salicylate in the unknown directly from the graph and from the best fit trend-line (least squares analysis) of the graph that yielded a straight…arrow_forward
- Don't used Ai solutionarrow_forwardCalculate the differences between energy levels in J, Einstein's coefficients of estimated absorption and spontaneous emission and life time media for typical electronic transmissions (vnm = 1015 s-1) and vibrations (vnm = 1013 s-1) . Assume that the dipolar transition moments for these transactions are in the order of 1 D.Data: 1D = 3.33564x10-30 C m; epsilon0 = 8.85419x10-12 C2m-1J-1arrow_forwardDon't used Ai solutionarrow_forward
- Please correct answer and don't used hand raitingarrow_forwardIn an induced absorption process:a) the population of the fundamental state is diminishingb) the population of the excited state decreasesc) the non-radiating component is the predominant oned) the emission radiation is consistentarrow_forwardhow a - Cyanostilbenes are made? provide 3 different methods for their synthesisarrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
- World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning