Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN: 9781305960060
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
Question
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Chapter 2, Problem 2.49E
Interpretation Introduction

(a)

Interpretation:

The statements corresponding to the given formula that are equivalent to Statements 1-6 is to be stated.

Concept introduction:

The chemical formula of a compound represents the type of elements present in that compound. The subscript corresponding to that element represents the number of atoms of that element present in one molecule of that compound.

Expert Solution
Check Mark

Answer to Problem 2.49E

The statements corresponding to CO2 that are equivalent to Statements 1-6 are as follows:

1. There are 2C atoms and 4O atoms present in 2 molecules of CO2.

2. There are 10C atoms and 20O atoms present in 10 molecules of CO2.

3. There are 100C atoms and 200O atoms present in 100 molecules of CO2.

4. There are 6.02×1023C atoms and 12.04×1023O atoms present in 6.02×1023 molecules of CO2.

5. There are 1molC atoms and 2molesO atoms present in 1molCO2.

6. There is 12.01gC and 32.00gO is present in 44.01g of CO2.

Explanation of Solution

For the given compound carbon dioxide (CO2), the statements equivalent to Statements 1-6 are,

According to statement 1, the 2 molecules of carbon dioxide (CO2), contain 2C atoms and 4O atoms.

According to statement 2, the 10 molecules of carbon dioxide (CO2), contain 10C atoms and 20O atoms.

According to statement 3, the 100 molecules of carbon dioxide (CO2), contain 100C atoms and 200O atoms.

According to statement 4, the 6.02×1023 molecules of carbon dioxide (CO2), contain 6.02×1023C atoms and 12.04×1023O atoms.

According to statement 5, one mole of carbon dioxide (CO2), contain 1molC atoms and 2molesO atoms.

According to statement 6, the 44.01g amount of carbon dioxide (CO2), contain 12.01gC and 32.00gO.

Conclusion

The statements corresponding to CO2 that are equivalent to Statements 1-6 are as follows:

1. There are 2C atoms and 4O atoms present in 2 molecules of CO2.

2. There are 10C atoms and 20O atoms present in 10 molecules of CO2.

3. There are 100C atoms and 200O atoms present in 100 molecules of CO2.

4. There are 6.02×1023C atoms and 12.04×1023O atoms present in 6.02×1023 molecules of CO2.

5. There are 1molC atoms and 2molesO atoms present in 1molCO2.

6. The 44.01g amount of carbon dioxide (CO2), contain 12.01gC and 32.00gO.

Interpretation Introduction

(b)

Interpretation:

The statements corresponding to the given formula that is equivalent to Statements 1-6 is to be stated.

Concept introduction:

The chemical formula of a compound represents the type of elements present in that compound. The subscript corresponding to that element represents the number of atoms of that element present in one molecule of that compound.

Expert Solution
Check Mark

Answer to Problem 2.49E

The statements corresponding to C2H6 that are equivalent to Statements 1-6 are as follows:

1. There are 4C atoms and 12H atoms present in 2 molecules of C2H6.

2. There are 20C atoms and 60H atoms present in 10 molecules of C2H6.

3. There are 200C atoms and 600H atoms present in 100 molecules of C2H6.

4. There are 12.04×1023C atoms and 36.12×1023H atoms present in 6.02×1023 molecules of C2H6.

5. There are 2molC atoms and 6molesH atoms present in 1molC2H6.

6. There is 24.02gC and 6.00gH is present in 30.02g of C2H6.

Explanation of Solution

The statements corresponding to C2H6 that are equivalent to Statements 1-6 are as follows:

1. The 2 molecules of ethane (C2H6), contain 4C atoms and 12H atoms.

2. The 10 molecules of ethane (C2H6), contain 20C atoms and 60H atoms.

3. The 100 molecules of ethane (C2H6), contain 200C atoms and 600H atoms.

4. The 6.02×1023 molecules of ethane (C2H6), contain 12.04×1023C atoms and 36.12×1023H atoms.

5. One mole of ethane (C2H6), contain 2molC atoms and 6molesH atoms.

6. The 30.02g amount of ethane (C2H6), contain 24.02gC and 6.00gH.

Conclusion

The statements corresponding to C2H6 that are equivalent to Statements 1-6 are as follows:

1. There are 4C atoms and 12H atoms present in 2 molecules of C2H6.

2. There are 20C atoms and 60H atoms present in 10 molecules of C2H6.

3. There are 200C atoms and 600H atoms present in 100 molecules of C2H6.

4. There are 12.04×1023C atoms and 36.12×1023H atoms present in 6.02×1023 molecules of C2H6.

5. There are 2molC atoms and 6molesH atoms present in 1molC2H6.

6. There is 24.02gC and 6.00gH is present in 30.02g of C2H6.

Interpretation Introduction

(c)

Interpretation:

The statements corresponding to the given formula that is equivalent to Statements 1-6 is to be stated.

Concept introduction:

The chemical formula of a compound represents the type of elements present in that compound. The subscript corresponding to that element represents the number of atoms of that element present in one molecule of that compound.

Expert Solution
Check Mark

Answer to Problem 2.49E

The statements corresponding to C6H12O6 that are equivalent to Statements 1-6 are as follows:

1. There are 12C atoms, 24H atoms and 12O atoms present in 2 molecules of C6H12O6.

2. There are 60C atoms, 120H atoms and 60O atoms present in 10 molecules of C6H12O6.

3. There are 600C atoms, 1200H atoms and 600O atoms present in 100 molecules of C6H12O6.

4. There are 36.12×1023C atoms, 72.24×1023H atoms and 12.04×1023O atoms present in 6.02×1023 molecules of C6H12O6.

5. There are 6molC atoms, 12molesH atoms and 6molesO atoms present in 1molC6H12O6.

6. There is 72.06gC, 12gH and 96.00gO present in 180.06g of C6H12O6.

Explanation of Solution

The statements corresponding to C6H12O6 that are equivalent to Statements 1-6 are as follows:

1. The 2 molecules of glucose (C6H12O6), contain 12C atom, 24H atoms and 12O atoms.

2. The 10 molecules of glucose (C6H12O6), contain 60C atom, 120H atoms and 60O atoms.

3. The 100 molecules of glucose (C6H12O6), contain 600C atom, 1200H atoms and 600O atoms.

4. The 6.02×1023 molecules of glucose (C6H12O6), contain 36.12×1023C atom, 72.24×1023H atoms and 12.04×1023O atoms.

5. One mole of glucose (C6H12O6), contain 6molC atoms, 12molesH atoms and 6molesO atoms.

6. The 180.06g amount of glucose (C6H12O6), contain 72.06gC, 12gH and 96.00gO.

Conclusion

The statements corresponding to C6H12O6 that are equivalent to Statements 1-6 are as follows:

1. There are 12C atoms, 12H atoms and 12O atoms present in 2 molecules of C6H12O6.

2. There are 60C atoms, 120H atoms and 60O atoms present in 10 molecules of C6H12O6.

3. There are 600C atoms, 1200H atoms and 600O atoms present in 100 molecules of C6H12O6.

4. There are 36.12×1023C atoms, 72.24×1023H atoms and 12.04×1023O atoms present in 6.02×1023 molecules of C6H12O6.

5. There are 6molC atoms, 12molesH atoms and 6molesO atoms present in 1molC6H12O6.

6. There is 72.06gC, 12gH and 96.00gO present in 180.06g of C6H12O6.

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Chapter 2 Solutions

Chemistry for Today: General, Organic, and Biochemistry

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