When cyclohexane is substituted by an ethynyl group, the energy difference between axial and equatorial conformations is only 1 .7kJ(0 .41kcal)/mol . The conformational equilibrium for methyl cyclohexane with that of ethynyl cyclohexane has to be compared and the difference between the two structures has to be accounted. Concept Introduction: The difference in strain energy between the axial and equatorial conformations can be calculated by the ratio at equilibrium using the equation of the Gibb’s free energy ( ΔG 0 ). The equation can be given as ΔG 0 = -RT ln K eq The terms in the above equation are explained as ΔG 0 = Gibb’s free energy at equilibrium R = Universal gas constant T = Temperature (in Kelvins) K eq = Equilibrium constant The universal gas constant value is 8 .314 J .K -1 .mol -1 or 1 .987 cal .K -1 .mol -1 . The value of temperature in kelvin is 0 0 C = 273K .

Question

Indicate the names of these compounds (if they exist). 0: HỌC—NH CH3CH2-CH2

Answer 1

Question

Chapter 2, Problem 2.46P

Interpretation Introduction

Interpretation:

When cyclohexane is substituted by an ethynyl group, the energy difference between axial and equatorial conformations is only $1.7kJ(0.41kcal)/mol$ . The conformational equilibrium for methyl cyclohexane with that of ethynyl cyclohexane has to be compared and the difference between the two structures has to be accounted.

Concept Introduction:

The difference in strain energy between the axial and equatorial conformations can be calculated by the ratio at equilibrium using the equation of the Gibb’s free energy ( $ΔG0$ ). The equation can be given as

$ΔG0= -RT ln Keq$

The terms in the above equation are explained as

$ΔG0$ = Gibb’s free energy at equilibrium

$R$ = Universal gas constant

$T$ = Temperature (in Kelvins)

$Keq$ = Equilibrium constant

The universal gas constant value is $8.314 J.K-1.mol-1 or 1.987 cal.K-1.mol-1$ . The value of temperature in kelvin is $00C = 273K$ .

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Indicate the names of these compounds (if they exist). 0: HỌC—NH CH3CH2-CH2

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The conjugate base of alkanes is called alkides. Correct?.

Answer 2

Question

Chapter 2, Problem 2.46P

Interpretation Introduction

Interpretation:

When cyclohexane is substituted by an ethynyl group, the energy difference between axial and equatorial conformations is only $1.7kJ(0.41kcal)/mol$ . The conformational equilibrium for methyl cyclohexane with that of ethynyl cyclohexane has to be compared and the difference between the two structures has to be accounted.

Concept Introduction:

The difference in strain energy between the axial and equatorial conformations can be calculated by the ratio at equilibrium using the equation of the Gibb’s free energy ( $ΔG0$ ). The equation can be given as

$ΔG0= -RT ln Keq$

The terms in the above equation are explained as

$ΔG0$ = Gibb’s free energy at equilibrium

$R$ = Universal gas constant

$T$ = Temperature (in Kelvins)

$Keq$ = Equilibrium constant

The universal gas constant value is $8.314 J.K-1.mol-1 or 1.987 cal.K-1.mol-1$ . The value of temperature in kelvin is $00C = 273K$ .

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Answer 3

Question

Chapter 2, Problem 2.46P

Interpretation Introduction

Interpretation:

When cyclohexane is substituted by an ethynyl group, the energy difference between axial and equatorial conformations is only $1.7kJ(0.41kcal)/mol$ . The conformational equilibrium for methyl cyclohexane with that of ethynyl cyclohexane has to be compared and the difference between the two structures has to be accounted.

Concept Introduction:

The difference in strain energy between the axial and equatorial conformations can be calculated by the ratio at equilibrium using the equation of the Gibb’s free energy ( $ΔG0$ ). The equation can be given as

$ΔG0= -RT ln Keq$

The terms in the above equation are explained as

$ΔG0$ = Gibb’s free energy at equilibrium

$R$ = Universal gas constant

$T$ = Temperature (in Kelvins)

$Keq$ = Equilibrium constant

The universal gas constant value is $8.314 J.K-1.mol-1 or 1.987 cal.K-1.mol-1$ . The value of temperature in kelvin is $00C = 273K$ .

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Answer 4

Question

Chapter 2, Problem 2.46P

Interpretation Introduction

Interpretation:

When cyclohexane is substituted by an ethynyl group, the energy difference between axial and equatorial conformations is only $1.7kJ(0.41kcal)/mol$ . The conformational equilibrium for methyl cyclohexane with that of ethynyl cyclohexane has to be compared and the difference between the two structures has to be accounted.

Concept Introduction:

The difference in strain energy between the axial and equatorial conformations can be calculated by the ratio at equilibrium using the equation of the Gibb’s free energy ( $ΔG0$ ). The equation can be given as

$ΔG0= -RT ln Keq$

The terms in the above equation are explained as

$ΔG0$ = Gibb’s free energy at equilibrium

$R$ = Universal gas constant

$T$ = Temperature (in Kelvins)

$Keq$ = Equilibrium constant

The universal gas constant value is $8.314 J.K-1.mol-1 or 1.987 cal.K-1.mol-1$ . The value of temperature in kelvin is $00C = 273K$ .

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Answer 5

Chapter 2, Problem 2.46P

Interpretation Introduction

Interpretation:

When cyclohexane is substituted by an ethynyl group, the energy difference between axial and equatorial conformations is only $1.7kJ(0.41kcal)/mol$ . The conformational equilibrium for methyl cyclohexane with that of ethynyl cyclohexane has to be compared and the difference between the two structures has to be accounted.

Concept Introduction:

The difference in strain energy between the axial and equatorial conformations can be calculated by the ratio at equilibrium using the equation of the Gibb’s free energy ( $ΔG0$ ). The equation can be given as

$ΔG0= -RT ln Keq$

The terms in the above equation are explained as

$ΔG0$ = Gibb’s free energy at equilibrium

$R$ = Universal gas constant

$T$ = Temperature (in Kelvins)

$Keq$ = Equilibrium constant

The universal gas constant value is $8.314 J.K-1.mol-1 or 1.987 cal.K-1.mol-1$ . The value of temperature in kelvin is $00C = 273K$ .

Answer 6

Chapter 2, Problem 2.46P

Interpretation Introduction

Interpretation:

When cyclohexane is substituted by an ethynyl group, the energy difference between axial and equatorial conformations is only $1.7kJ(0.41kcal)/mol$ . The conformational equilibrium for methyl cyclohexane with that of ethynyl cyclohexane has to be compared and the difference between the two structures has to be accounted.

Concept Introduction:

The difference in strain energy between the axial and equatorial conformations can be calculated by the ratio at equilibrium using the equation of the Gibb’s free energy ( $ΔG0$ ). The equation can be given as

$ΔG0= -RT ln Keq$

The terms in the above equation are explained as

$ΔG0$ = Gibb’s free energy at equilibrium

$R$ = Universal gas constant

$T$ = Temperature (in Kelvins)

$Keq$ = Equilibrium constant

The universal gas constant value is $8.314 J.K-1.mol-1 or 1.987 cal.K-1.mol-1$ . The value of temperature in kelvin is $00C = 273K$ .

Answer 7

Chapter 2, Problem 2.46P

Interpretation Introduction

Interpretation:

When cyclohexane is substituted by an ethynyl group, the energy difference between axial and equatorial conformations is only $1.7kJ(0.41kcal)/mol$ . The conformational equilibrium for methyl cyclohexane with that of ethynyl cyclohexane has to be compared and the difference between the two structures has to be accounted.

Concept Introduction:

The difference in strain energy between the axial and equatorial conformations can be calculated by the ratio at equilibrium using the equation of the Gibb’s free energy ( $ΔG0$ ). The equation can be given as

$ΔG0= -RT ln Keq$

The terms in the above equation are explained as

$ΔG0$ = Gibb’s free energy at equilibrium

$R$ = Universal gas constant

$T$ = Temperature (in Kelvins)

$Keq$ = Equilibrium constant

The universal gas constant value is $8.314 J.K-1.mol-1 or 1.987 cal.K-1.mol-1$ . The value of temperature in kelvin is $00C = 273K$ .

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Ch. 2.2 - Do the line-angle formulas in each pair represent...Ch. 2.2 - Draw line-angle formulas for the three...Ch. 2.3 - Write IUPAC names for these alkanes.Ch. 2.4 - Combine the proper prefix, infix, and suffix and...Ch. 2.4 - Write the molecular formula, IUPAC name, and...Ch. 2.4 - Write molecular formulas for each bicycloalkane,...Ch. 2.4 - Prob. 2.7P Ch. 2.5 - For 1,2-dichloroethane: (a) Draw Newman...Ch. 2.5 - Following is a chair conformation of cyclohexane...Ch. 2.5 - Draw the alternative chair conformation for the...

Solution Summary: The author explains that when cyclohexane is substituted by an ethynyl group, the energy difference between axial and

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