FUND OF ENG THERMODYN(LLF)+WILEYPLUS
9th Edition
ISBN: 9781119391777
Author: MORAN
Publisher: WILEY
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Chapter 2, Problem 2.26CU
To determine
The
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A converging elbow (see the figure below) turns water through an angle of 135° in a vertical plane. The flow cross section diameter is
400 mm at the elbow inlet, section (1), and 200 mm at the elbow outlet, section (2). The elbow flow passage volume is 0.2 m³ between
sections (1) and (2). The water volume flowrate is 0.1 m³/s and the elbow inlet and outlet pressures are 140 kPa and 90 kPa. The elbow
mass is 11 kg. Calculate the (a) horizontal (x direction) and (b) vertical (z direction) anchoring forces required to hold the elbow in
place.
D₂-
Section
(1)-
D₁ = 400 mm
135°
200 mm
Section (2)
(a) Fx= i
20809.96
N
(b) Fz= i
-120265
N
2: A rectangular aluminum block is loaded uniformly in three directions. The loadings are as follows:a 50 kN total resulting compressive load in the x-direction, a 200 kPa uniformly distributed tensile load in they-direction, and a 0.03 MN total resulting tensile load in the z-direction. The block has the following dimensions:L = 1 m, b = 20 cm, h = 350 mm. Use E = 70 GPa and ν = 0.25.Determine the strain in the x and y axes respectively. For the strain in the y-direction to be equal to 0, how much uniformly distributed load inthe surface of y-direction should be added? (+ for tensile, - for compressive)
Answers:
5 -1.122 x10-5 / 3 decimals
6 5.102 x10-6 / 3 decimals
7 -0.357 MPa / 3 decimals
A spherical balloon with a diameter of 9 m is filled with water vapour at 200˚C and 200 kPa. Determine the mass of water in the balloon. The R value for water is 0.4615 kJ/kg∙K.
Chapter 2 Solutions
FUND OF ENG THERMODYN(LLF)+WILEYPLUS
Ch. 2 - Prob. 2.1ECh. 2 - Prob. 2.2ECh. 2 - Prob. 2.3ECh. 2 - Prob. 2.4ECh. 2 - Prob. 2.5ECh. 2 - Prob. 2.6ECh. 2 - Prob. 2.7ECh. 2 - Prob. 2.8ECh. 2 - Prob. 2.9ECh. 2 - Prob. 2.10E
Ch. 2 - Prob. 2.11ECh. 2 - Prob. 2.12ECh. 2 - Prob. 2.13ECh. 2 - Prob. 2.14ECh. 2 - Prob. 2.15ECh. 2 - Prob. 2.16ECh. 2 - Prob. 2.17ECh. 2 - Prob. 2.1CUCh. 2 - Prob. 2.2CUCh. 2 - Prob. 2.3CUCh. 2 - Prob. 2.4CUCh. 2 - Prob. 2.5CUCh. 2 - Prob. 2.6CUCh. 2 - Prob. 2.7CUCh. 2 - Prob. 2.8CUCh. 2 - Prob. 2.9CUCh. 2 - Prob. 2.10CUCh. 2 - Prob. 2.11CUCh. 2 - Prob. 2.12CUCh. 2 - Prob. 2.13CUCh. 2 - Prob. 2.14CUCh. 2 - Prob. 2.15CUCh. 2 - Prob. 2.16CUCh. 2 - Prob. 2.17CUCh. 2 - Prob. 2.18CUCh. 2 - Prob. 2.19CUCh. 2 - Prob. 2.20CUCh. 2 - Prob. 2.21CUCh. 2 - Prob. 2.22CUCh. 2 - Prob. 2.23CUCh. 2 - Prob. 2.24CUCh. 2 - Prob. 2.25CUCh. 2 - Prob. 2.26CUCh. 2 - Prob. 2.27CUCh. 2 - Prob. 2.28CUCh. 2 - Prob. 2.29CUCh. 2 - Prob. 2.30CUCh. 2 - Prob. 2.31CUCh. 2 - Prob. 2.32CUCh. 2 - Prob. 2.33CUCh. 2 - Prob. 2.34CUCh. 2 - Prob. 2.35CUCh. 2 - Prob. 2.36CUCh. 2 - Prob. 2.37CUCh. 2 - Prob. 2.38CUCh. 2 - Prob. 2.39CUCh. 2 - Prob. 2.40CUCh. 2 - Prob. 2.41CUCh. 2 - Prob. 2.42CUCh. 2 - Prob. 2.43CUCh. 2 - Prob. 2.44CUCh. 2 - Prob. 2.45CUCh. 2 - Prob. 2.46CUCh. 2 - Prob. 2.47CUCh. 2 - Prob. 2.48CUCh. 2 - Prob. 2.49CUCh. 2 - Prob. 2.50CUCh. 2 - Prob. 2.51CUCh. 2 - Prob. 2.52CUCh. 2 - Prob. 2.53CUCh. 2 - Prob. 2.54CUCh. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10PCh. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. 2.29PCh. 2 - Prob. 2.30PCh. 2 - Prob. 2.31PCh. 2 - Prob. 2.32PCh. 2 - Prob. 2.33PCh. 2 - Prob. 2.34PCh. 2 - Prob. 2.35PCh. 2 - Prob. 2.36PCh. 2 - Prob. 2.37PCh. 2 - Prob. 2.38PCh. 2 - Prob. 2.39PCh. 2 - Prob. 2.40PCh. 2 - Prob. 2.41PCh. 2 - Prob. 2.42PCh. 2 - Prob. 2.43PCh. 2 - Prob. 2.44PCh. 2 - Prob. 2.45PCh. 2 - Prob. 2.46PCh. 2 - Prob. 2.47PCh. 2 - Prob. 2.48PCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71P
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- Correct answers are written below. Detailed and correct solution only with fbd. I will upvote. 1: A 3 m alloy shaft fixed at one end has a torsional shearing stress capacity of 55 MPa. Due to improper fabrication, its cross-sectionalarea has become irregularly shaped. Its effective polar moment of inertia has become 2 x10-7 m4, and the maximum torque stress acts at 7.5 cm fromthe center of the shaft.[1]: If the shaft is to be replaced by a properly manufactured solid circular shaft that has a maximumshearing stress capacity of 70 MN/m2, what is the minimum diameter required so it can withstand the sameload? [2]: Calculate the thickness of a hollow circular shaft with the same outside diameter calculated initem [1] that can carry the same load. Limit the maximum shearing stress of the hollow circular shaft to0.09 GPa.Determine the angle of twist on the free end of the shaft. Use G = 150 x103 GPa. [3]: Use the solidcircular shaft from [1] and use the hollow circular shaft from [2].…arrow_forwardtwo closed 1 m3 chambers are filled with fluid at 25˚C and 1 atm. One is filled with pure carbon dioxide and one is filled with pure water. Only considering the weight of the fluids, which chamber is heavier?arrow_forwardCorrect answers are written below. Detailed and correct solution only with fbd. I will upvote. 1: A 3 m alloy shaft fixed at one end has a torsional shearing stress capacity of 55 MPa. Due to improper fabrication, its cross-sectionalarea has become irregularly shaped. Its effective polar moment of inertia has become 2 x10-7 m4, and the maximum torque stress acts at 7.5 cm fromthe center of the shaft.[1]: If the shaft is to be replaced by a properly manufactured solid circular shaft that has a maximumshearing stress capacity of 70 MN/m2, what is the minimum diameter required so it can withstand the sameload? [2]: Calculate the thickness of a hollow circular shaft with the same outside diameter calculated initem [1] that can carry the same load. Limit the maximum shearing stress of the hollow circular shaft to0.09 GPa.Determine the angle of twist on the free end of the shaft. Use G = 150 x103 GPa. [3]: Use the solidcircular shaft from [1] and use the hollow circular shaft from [2].…arrow_forward
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