Explanation Option (c) final value minus initial value. The Greek letter delta ( Δ ) is used to represent the difference between two states of a variable. The delta is used to represent the final state of the system minus the initial state of the system. So, the correct answer is option (c). Option (a) initial value minus final value. The value that is received when the value of the final state of the system is deducted from the initial state of the system. Therefore, the initial value minus the final value, in this case, will give a negative value

9th Edition

ISBN: 9781119391777

Author: MORAN

Publisher: WILEY

See similar textbooks

Concept explainers

Properties of Pure Substances

A substance with fixed chemical composition throughout is called a pure substance like water, air, and nitrogen. A pure substance does not have to be a single element or compound. A mixture of two or more phases of a pure substance is also a pure substan…

Videos

Question

Chapter 2, Problem 2.12CU

To determine

The correct option related to the symbol delta Δ .

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 2, Problem 2.11CU

Chapter 2, Problem 2.13CU

Students have asked these similar questions

Temperature (°C) 100 4. Consider the solidification of a binary Pb-10%Sn alloy. Assume that during solidification, there is complete mixing in the liquid and no diffusion in the solid. Use the phase diagram below to answer the following question. (a) Draw (on the phase diagram) the compositions of the liquid and the solid at the interface as a function of temperature during solidification. (b) Illustrate on the phase diagram how one would calculate the volume fraction solidified at a given temperature. (c) (d) Indicate the temperature at which solidification is complete. Do you expect ẞ to be present in the as-cast microstructure? Explain 300 327°C 200 a (Pb) 20 20 a + L 18.3 183°C α + β 40 60 Composition (wt% Sn) Liquid 600 500 232°C B+L 400 B 61.9 97.8 300 808 100 (Sn) 200 100 Temperature (°F)

I tried this problem a couple of times and don't know where I'm going wrong can you help me out please

y(0)=1, Using Laplace transforms solve the following differential equations : 11) y"-4y+4y=0, 12) y+2y+2y=0, y(0)=2.1, y'(0) = 3.9 y'(0)=-3. 13) y+7y+12y=21e", y(0)=3.5, y'(0)=-10. 14) +9y=10e. y(0)=0, y'(0) = 0. 15) y+3y+2.25y=91³ +64, y(0)=1, y'(0) = 31.5 16) -6y+5y= 29 cos(21), y(0)=3.2, y'(0)=6.2 17) "+2y+2y=0, y(0)=0, y'(0)=1. 18) +2y+17y=0, y(0)=0, y'(0)=12. 19) y-4y+5y=0, y(0)=1, y'(0) = 2. 20) 9y-6y+y=0, y(0)=3, y'(0)=1. 21) -2y+10y=0, y(0)=3, y'(0)=3.

Chapter 2 Solutions

FUND OF ENG THERMODYN(LLF)+WILEYPLUS

Ch. 2 - Prob. 2.1E Ch. 2 - Prob. 2.2E Ch. 2 - Prob. 2.3E Ch. 2 - Prob. 2.4E Ch. 2 - Prob. 2.5E Ch. 2 - Prob. 2.6E Ch. 2 - Prob. 2.7E Ch. 2 - Prob. 2.8E Ch. 2 - Prob. 2.9E Ch. 2 - Prob. 2.10E

Ch. 2 - Prob. 2.11E Ch. 2 - Prob. 2.12E Ch. 2 - Prob. 2.13E Ch. 2 - Prob. 2.14E Ch. 2 - Prob. 2.15E Ch. 2 - Prob. 2.16E Ch. 2 - Prob. 2.17E Ch. 2 - Prob. 2.1CU Ch. 2 - Prob. 2.2CU Ch. 2 - Prob. 2.3CU Ch. 2 - Prob. 2.4CU Ch. 2 - Prob. 2.5CU Ch. 2 - Prob. 2.6CU Ch. 2 - Prob. 2.7CU Ch. 2 - Prob. 2.8CU Ch. 2 - Prob. 2.9CU Ch. 2 - Prob. 2.10CU Ch. 2 - Prob. 2.11CU Ch. 2 - Prob. 2.12CU Ch. 2 - Prob. 2.13CU Ch. 2 - Prob. 2.14CU Ch. 2 - Prob. 2.15CU Ch. 2 - Prob. 2.16CU Ch. 2 - Prob. 2.17CU Ch. 2 - Prob. 2.18CU Ch. 2 - Prob. 2.19CU Ch. 2 - Prob. 2.20CU Ch. 2 - Prob. 2.21CU Ch. 2 - Prob. 2.22CU Ch. 2 - Prob. 2.23CU Ch. 2 - Prob. 2.24CU Ch. 2 - Prob. 2.25CU Ch. 2 - Prob. 2.26CU Ch. 2 - Prob. 2.27CU Ch. 2 - Prob. 2.28CU Ch. 2 - Prob. 2.29CU Ch. 2 - Prob. 2.30CU Ch. 2 - Prob. 2.31CU Ch. 2 - Prob. 2.32CU Ch. 2 - Prob. 2.33CU Ch. 2 - Prob. 2.34CU Ch. 2 - Prob. 2.35CU Ch. 2 - Prob. 2.36CU Ch. 2 - Prob. 2.37CU Ch. 2 - Prob. 2.38CU Ch. 2 - Prob. 2.39CU Ch. 2 - Prob. 2.40CU Ch. 2 - Prob. 2.41CU Ch. 2 - Prob. 2.42CU Ch. 2 - Prob. 2.43CU Ch. 2 - Prob. 2.44CU Ch. 2 - Prob. 2.45CU Ch. 2 - Prob. 2.46CU Ch. 2 - Prob. 2.47CU Ch. 2 - Prob. 2.48CU Ch. 2 - Prob. 2.49CU Ch. 2 - Prob. 2.50CU Ch. 2 - Prob. 2.51CU Ch. 2 - Prob. 2.52CU Ch. 2 - Prob. 2.53CU Ch. 2 - Prob. 2.54CU Ch. 2 - Prob. 2.1P Ch. 2 - Prob. 2.2P Ch. 2 - Prob. 2.3P Ch. 2 - Prob. 2.4P Ch. 2 - Prob. 2.5P Ch. 2 - Prob. 2.6P Ch. 2 - Prob. 2.7P Ch. 2 - Prob. 2.8P Ch. 2 - Prob. 2.9P Ch. 2 - Prob. 2.10P Ch. 2 - Prob. 2.11P Ch. 2 - Prob. 2.12P Ch. 2 - Prob. 2.13P Ch. 2 - Prob. 2.14P Ch. 2 - Prob. 2.15P Ch. 2 - Prob. 2.16P Ch. 2 - Prob. 2.17P Ch. 2 - Prob. 2.18P Ch. 2 - Prob. 2.19P Ch. 2 - Prob. 2.20P Ch. 2 - Prob. 2.21P Ch. 2 - Prob. 2.22P Ch. 2 - Prob. 2.23P Ch. 2 - Prob. 2.24P Ch. 2 - Prob. 2.25P Ch. 2 - Prob. 2.26P Ch. 2 - Prob. 2.27P Ch. 2 - Prob. 2.28P Ch. 2 - Prob. 2.29P Ch. 2 - Prob. 2.30P Ch. 2 - Prob. 2.31P Ch. 2 - Prob. 2.32P Ch. 2 - Prob. 2.33P Ch. 2 - Prob. 2.34P Ch. 2 - Prob. 2.35P Ch. 2 - Prob. 2.36P Ch. 2 - Prob. 2.37P Ch. 2 - Prob. 2.38P Ch. 2 - Prob. 2.39P Ch. 2 - Prob. 2.40P Ch. 2 - Prob. 2.41P Ch. 2 - Prob. 2.42P Ch. 2 - Prob. 2.43P Ch. 2 - Prob. 2.44P Ch. 2 - Prob. 2.45P Ch. 2 - Prob. 2.46P Ch. 2 - Prob. 2.47P Ch. 2 - Prob. 2.48P Ch. 2 - Prob. 2.49P Ch. 2 - Prob. 2.50P Ch. 2 - Prob. 2.51P Ch. 2 - Prob. 2.52P Ch. 2 - Prob. 2.53P Ch. 2 - Prob. 2.54P Ch. 2 - Prob. 2.55P Ch. 2 - Prob. 2.56P Ch. 2 - Prob. 2.57P Ch. 2 - Prob. 2.58P Ch. 2 - Prob. 2.59P Ch. 2 - Prob. 2.60P Ch. 2 - Prob. 2.62P Ch. 2 - Prob. 2.63P Ch. 2 - Prob. 2.64P Ch. 2 - Prob. 2.65P Ch. 2 - Prob. 2.66P Ch. 2 - Prob. 2.67P Ch. 2 - Prob. 2.68P Ch. 2 - Prob. 2.69P Ch. 2 - Prob. 2.70P Ch. 2 - Prob. 2.71P

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

The correct option related to the symbol delta Δ .

Solution Summary: The author explains that the correct option related to the symbol delta Delta is option (c) final value minus the initial value.

Concept explainers

Videos

The correct option related to the symbol delta Δ .

Want to see the full answer?

Chapter 2 Solutions