Applied Statics and Strength of Materials (6th Edition)
Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Textbook Question
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Chapter 2, Problem 2.1P

Find the resultant force for each system of forces shown.

a.

Expert Solution
Check Mark
To determine

The resultant of the given forces.

Answer to Problem 2.1P

  78.102lb .

Explanation of Solution

Given information:

Applied Statics and Strength of Materials (6th Edition), Chapter 2, Problem 2.1P , additional homework tip  1

Concept used:

Resultant force the two forces is

  R2=X2+Y2

Calculation:

In the figure the X is moving in right direction so we will take “+ sign”.

And, the Y is moving in downward direction, so we are taking Y value in “- sign”

The resultant is given by

  R2=X2+Y2

   R 2 = 50 2 + (60) 2 R= 502+ (60)2R=78.102lb

Conclusion:

Therefore, the resultant of the given forces is 78.102lb.

b.

Expert Solution
Check Mark
To determine

The resultant of the given forces.

Answer to Problem 2.1P

  284.253 N

Explanation of Solution

Given information:

The forces are

Applied Statics and Strength of Materials (6th Edition), Chapter 2, Problem 2.1P , additional homework tip  2

Concept used:

Resultant force the two forces is

  R2=X2+Y2

Calculation:

In the figure the X is moving in right direction so we will take “+ sign”.

And, the Y is moving in upward direction, so we are taking Y value in “+ sign”

The resultant is given by

   R2=X2+Y2 R 2 = 180 2 + (220) 2 R= 1802+ (220)2R=284.253N

Conclusion:

Therefore, the resultant of the given force is 284.253 N

c.

Expert Solution
Check Mark
To determine

The resultant of the given forces.

Answer to Problem 2.1P

  4.272 kips

Explanation of Solution

Given information:

The given forces are

Applied Statics and Strength of Materials (6th Edition), Chapter 2, Problem 2.1P , additional homework tip  3

Concept used:

Resultant force the two forces is

  R2=X2+Y2

Calculation:

In the figure the X is moving in left direction so we will take “- sign”.

And, the Y is moving in downward, so we are taking Y value in “- sign”

We know that the resultant is given by

  R2=X2+Y2 R 2 = (4) 2 + (1.5) 2 R= (4)2+ (1.5)2R=4.272kips

Conclusion:

Therefore, the resultant of the given force is 4.272 kips .

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Applied Statics and Strength of Materials (6th Edition)

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