MIPS: MIPS stand for Microprocessor without Interlocked Pipeline Stages. MIPS instructions have 32-bits general purpose registers. The register preceded by “$” in assembly language instruction and it contains two formats for addressing one is register number and another is equivalent names. The result of multiplication and division can be stored in the special registers “Lo” and “Hi”. Example: Consider an example of MIPS assembly code: #add the variables and store in “a” add a, b, c Here the given instruction tell the computer to add the two variables “b” and “c” and store the result in the “a” variable.

Question

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Answer 1

Question

Chapter 2, Problem 2.1E

Program Plan Intro

MIPS:

MIPS stand for Microprocessor without Interlocked Pipeline Stages.

MIPS instructions have 32-bits general purpose registers.

The register preceded by “$” in assembly language instruction and it contains two formats for addressing one is register number and another is equivalent names.

The result of multiplication and division can be stored in the special registers “Lo” and “Hi”.

Example:

Consider an example of MIPS assembly code:

#add the variables and store in “a”

add a, b, c

Here the given instruction tell the computer to add the two variables “b” and “c” and store the result in the “a” variable.

Expert Solution & Answer

Explanation of Solution

Given statement:

#subtract the values and store in “f”

f = h – 5

#add the variables and store in “f”

f = f + g

Explanation:

Subtract the variable “h” and the value “5” and the result is store it in “f” then the variables “g” and “f” are added and store it in the “f” variable.

Corresponding MIPS assembly code:

#add the constant value with the variable and store in #“f”

addi f, h, -5

#add the variables and store in “f”

add f, f, g

Explanation:

Here, “addi” instruction is used to add constant values. The variable “h” is added to the “-5” value then store the result in “f” variable.
The second statement tells the computer to add the two variables “f” and “g” and store the result in the “f” variable.

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EXPLORER OPEN EDITORS Welcome com.py... Welcome xcom.py 2 ✓ DB com.py com.sql 6 8 9 10 11 12 13 14 15 16 17 com.py db class Rectangle: def _init_(self, length, width): self.length-length self.width-width def area(self): return self.width *self.length def perimeter(self): return 2+self.width*self.length y=Rectangle(5,1) print(y.area) Why does an error appear in the code print(y.perimeter) PROBLEMS OUTPUT TERMINAL DEBUG CONSOLE PORTS I > OUTLINE > TIMELINE 0A4 0 self.width *self.length AAAA NameError: name 'self' is not defined PS C:\Users\hp\Desktop\db> & C:/Users/hp/AppData/Local/Microsoft/WindowsApps/python3.12.exe c:/Users/hp/Desktop/db/com.py Traceback (most recent call last): File "c:\Users\hp\Desktop\db\com.py", line 1, in class Rectangle: File "c:\Users\hp\Desktop\db\com.py", line 7, in Rectangle self.width *self.length ^^^^^ NameError: name 'self' is not defined PS C:\Users\hp\Desktop\db> Ln 17, Col 1 Spaces: 4 UTF-8 CRLF (Python 3 A ENG

Refer to page 30 for problems on image edge detection. Instructions: Implement an edge detection algorithm (e.g., Sobel or Canny) for the given image. • Explain the preprocessing steps (grayscale conversion, noise reduction) and calculate gradient intensities. • Visualize and compare the results with manual edge annotations. Link: [https://drive.google.com/file/d/1wKSrun-GlxirS31Z9qoHazb9tC440 AZ F/view?usp=sharing]

Refer to page 100 for problems on 2D and 3D transformations. Instructions: Compute the result of applying a sequence of transformations (e.g., translation, rotation, scaling) to a given shape. Use homogeneous coordinates for matrix representation. • Show all intermediate matrices and verify the final position of the shape. Link: [https://drive.google.com/file/d/1wKSrun-GlxirS3IZ9qoHazb9tC440 AZF/view?usp=sharing]

Answer 2

Question

Chapter 2, Problem 2.1E

Program Plan Intro

MIPS:

MIPS stand for Microprocessor without Interlocked Pipeline Stages.

MIPS instructions have 32-bits general purpose registers.

The register preceded by “$” in assembly language instruction and it contains two formats for addressing one is register number and another is equivalent names.

The result of multiplication and division can be stored in the special registers “Lo” and “Hi”.

Example:

Consider an example of MIPS assembly code:

#add the variables and store in “a”

add a, b, c

Here the given instruction tell the computer to add the two variables “b” and “c” and store the result in the “a” variable.

Expert Solution & Answer

Explanation of Solution

Given statement:

#subtract the values and store in “f”

f = h – 5

#add the variables and store in “f”

f = f + g

Explanation:

Subtract the variable “h” and the value “5” and the result is store it in “f” then the variables “g” and “f” are added and store it in the “f” variable.

Corresponding MIPS assembly code:

#add the constant value with the variable and store in #“f”

addi f, h, -5

#add the variables and store in “f”

add f, f, g

Explanation:

Here, “addi” instruction is used to add constant values. The variable “h” is added to the “-5” value then store the result in “f” variable.
The second statement tells the computer to add the two variables “f” and “g” and store the result in the “f” variable.

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Answer 3

Question

Chapter 2, Problem 2.1E

Program Plan Intro

MIPS:

MIPS stand for Microprocessor without Interlocked Pipeline Stages.

MIPS instructions have 32-bits general purpose registers.

The register preceded by “$” in assembly language instruction and it contains two formats for addressing one is register number and another is equivalent names.

The result of multiplication and division can be stored in the special registers “Lo” and “Hi”.

Example:

Consider an example of MIPS assembly code:

#add the variables and store in “a”

add a, b, c

Here the given instruction tell the computer to add the two variables “b” and “c” and store the result in the “a” variable.

Expert Solution & Answer

Explanation of Solution

Given statement:

#subtract the values and store in “f”

f = h – 5

#add the variables and store in “f”

f = f + g

Explanation:

Subtract the variable “h” and the value “5” and the result is store it in “f” then the variables “g” and “f” are added and store it in the “f” variable.

Corresponding MIPS assembly code:

#add the constant value with the variable and store in #“f”

addi f, h, -5

#add the variables and store in “f”

add f, f, g

Explanation:

Here, “addi” instruction is used to add constant values. The variable “h” is added to the “-5” value then store the result in “f” variable.
The second statement tells the computer to add the two variables “f” and “g” and store the result in the “f” variable.

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Answer 4

Question

Chapter 2, Problem 2.1E

Program Plan Intro

MIPS:

MIPS stand for Microprocessor without Interlocked Pipeline Stages.

MIPS instructions have 32-bits general purpose registers.

The register preceded by “$” in assembly language instruction and it contains two formats for addressing one is register number and another is equivalent names.

The result of multiplication and division can be stored in the special registers “Lo” and “Hi”.

Example:

Consider an example of MIPS assembly code:

#add the variables and store in “a”

add a, b, c

Here the given instruction tell the computer to add the two variables “b” and “c” and store the result in the “a” variable.

Expert Solution & Answer

Explanation of Solution

Given statement:

#subtract the values and store in “f”

f = h – 5

#add the variables and store in “f”

f = f + g

Explanation:

Subtract the variable “h” and the value “5” and the result is store it in “f” then the variables “g” and “f” are added and store it in the “f” variable.

Corresponding MIPS assembly code:

#add the constant value with the variable and store in #“f”

addi f, h, -5

#add the variables and store in “f”

add f, f, g

Explanation:

Here, “addi” instruction is used to add constant values. The variable “h” is added to the “-5” value then store the result in “f” variable.
The second statement tells the computer to add the two variables “f” and “g” and store the result in the “f” variable.

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Answer 5

Chapter 2, Problem 2.1E

Program Plan Intro

MIPS:

MIPS stand for Microprocessor without Interlocked Pipeline Stages.

MIPS instructions have 32-bits general purpose registers.

The register preceded by “$” in assembly language instruction and it contains two formats for addressing one is register number and another is equivalent names.

The result of multiplication and division can be stored in the special registers “Lo” and “Hi”.

Example:

Consider an example of MIPS assembly code:

#add the variables and store in “a”

add a, b, c

Here the given instruction tell the computer to add the two variables “b” and “c” and store the result in the “a” variable.

Expert Solution & Answer

Explanation of Solution

Given statement:

#subtract the values and store in “f”

f = h – 5

#add the variables and store in “f”

f = f + g

Explanation:

Subtract the variable “h” and the value “5” and the result is store it in “f” then the variables “g” and “f” are added and store it in the “f” variable.

Corresponding MIPS assembly code:

#add the constant value with the variable and store in #“f”

addi f, h, -5

#add the variables and store in “f”

add f, f, g

Explanation:

Here, “addi” instruction is used to add constant values. The variable “h” is added to the “-5” value then store the result in “f” variable.
The second statement tells the computer to add the two variables “f” and “g” and store the result in the “f” variable.

Answer 6

Chapter 2, Problem 2.1E

Program Plan Intro

MIPS:

MIPS stand for Microprocessor without Interlocked Pipeline Stages.

MIPS instructions have 32-bits general purpose registers.

The register preceded by “$” in assembly language instruction and it contains two formats for addressing one is register number and another is equivalent names.

The result of multiplication and division can be stored in the special registers “Lo” and “Hi”.

Example:

Consider an example of MIPS assembly code:

#add the variables and store in “a”

add a, b, c

Here the given instruction tell the computer to add the two variables “b” and “c” and store the result in the “a” variable.

Expert Solution & Answer

Explanation of Solution

Given statement:

#subtract the values and store in “f”

f = h – 5

#add the variables and store in “f”

f = f + g

Explanation:

Subtract the variable “h” and the value “5” and the result is store it in “f” then the variables “g” and “f” are added and store it in the “f” variable.

Corresponding MIPS assembly code:

#add the constant value with the variable and store in #“f”

addi f, h, -5

#add the variables and store in “f”

add f, f, g

Explanation:

Here, “addi” instruction is used to add constant values. The variable “h” is added to the “-5” value then store the result in “f” variable.
The second statement tells the computer to add the two variables “f” and “g” and store the result in the “f” variable.

Answer 7

Chapter 2, Problem 2.1E

Program Plan Intro

MIPS:

MIPS stand for Microprocessor without Interlocked Pipeline Stages.

MIPS instructions have 32-bits general purpose registers.

The register preceded by “$” in assembly language instruction and it contains two formats for addressing one is register number and another is equivalent names.

The result of multiplication and division can be stored in the special registers “Lo” and “Hi”.

Example:

Consider an example of MIPS assembly code:

#add the variables and store in “a”

add a, b, c

Here the given instruction tell the computer to add the two variables “b” and “c” and store the result in the “a” variable.

Answer 8

Expert Solution & Answer

Explanation of Solution

Given statement:

#subtract the values and store in “f”

f = h – 5

#add the variables and store in “f”

f = f + g

Explanation:

Subtract the variable “h” and the value “5” and the result is store it in “f” then the variables “g” and “f” are added and store it in the “f” variable.

Corresponding MIPS assembly code:

#add the constant value with the variable and store in #“f”

addi f, h, -5

#add the variables and store in “f”

add f, f, g

Explanation:

Here, “addi” instruction is used to add constant values. The variable “h” is added to the “-5” value then store the result in “f” variable.
The second statement tells the computer to add the two variables “f” and “g” and store the result in the “f” variable.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Ch. 2 - Prob. 2.1E Ch. 2 - Prob. 2.2E Ch. 2 - Prob. 2.3E Ch. 2 - Prob. 2.4E Ch. 2 - Prob. 2.5E Ch. 2 - Prob. 2.6.1E Ch. 2 - Prob. 2.6.2E Ch. 2 - Prob. 2.7E Ch. 2 - Prob. 2.8E Ch. 2 - Prob. 2.9E

Explanation of Solution

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Chapter 2 Solutions