Concept explainers
Videos
Draw a “formula” for each of the following molecules using circular symbols of your choice to represent atoms:
a. A diatomic molecule of an element
b. A diatomic molecule of a compound
c. A triatomic molecule of an element
d. A molecule of a compound containing one atom of one element and four atoms of another element
(a)
Interpretation:
The formula for the diatomic molecule of an element by using circular symbols to represent atoms is to be drawn.
Concept introduction:
A molecular formula represents the number of atoms of each element present in a molecule of a compound.
The number of atoms present in molecule is determined by the subscript written below the normal line in the molecular formula.
Answer to Problem 2.1E
The formula for the diatomic molecule of an element by using circular symbols to represent atoms is shown below.
Explanation of Solution
It is given that the molecule of an element is a diatomic which means that the compound consists of two atoms with similar identity. This can be explained with the help of one example. Considering a diatomic molecule of an element that is chlorine gas. The chemical formula of chlorine gas is
Therefore, the formula for the diatomic molecule of an element by using circular symbols to represent atoms is shown below.
Figure 1
In the given figure, white circles represent the chlorine atoms.
The formula for the diatomic molecule of an element by using circular symbols to represent atoms is shown in figure 1.
(b)
Interpretation:
The formula for the diatomic molecule of a compound by using circular symbols to represent atoms is to be drawn.
Concept introduction:
A molecular formula represents the number of atoms of each element present in a molecule of a compound.
The number of atoms present in molecule is determined by the subscript written below the normal line in the molecular formula.
Answer to Problem 2.1E
The formula for the diatomic molecule of a compound by using circular symbols to represent atoms is shown below.
Explanation of Solution
It is given that the molecule of a compound is diatomic which means that the compound consists of two different atoms. This can be explained with the help of one example. Considering an example that is hydrogen fluoride. The chemical formula of hydrogen fluoride is
Therefore, the formula for the diatomic molecule of a compound by using circular symbols to represent atoms is shown below.
Figure 2
In the given figure, grey circle represent the fluorine atom, whereas white circle represent the hydrogen atoms.
The formula for the diatomic molecule of a compound by using circular symbols to represent atoms is shown in figure 2.
(c)
Interpretation:
The formula for the triatomic molecule of an element by using circular symbols to represent atoms is to be drawn.
Concept introduction:
A molecular formula represents the number of atoms of each element present in a molecule of a compound.
The number of atoms present in molecule is determined by the subscript written below the normal line in the molecular formula.
Answer to Problem 2.1E
The formula for the triatomic molecule of an element by using circular symbols to represent atoms is shown below.
Explanation of Solution
It is given that the molecule of an element is a triatomic which means that the compound consists of three atoms with similar identity. This can be explained with the help of one example. Considering an example that is ozone. The chemical formula of ozone is
Therefore, the formula for the triatomic molecule of an element by using circular symbols to represent atoms is shown below.
Figure 3
In the given diagram, white circles represent oxygen atoms.
The formula for the triatomic molecule of an element by using circular symbols to represent atoms is shown in figure 3.
(d)
Interpretation:
The formula for a molecule of a compound containing one atom of one element and four atoms of another element by using circular symbols to represent atoms is to be drawn.
Concept introduction:
A molecular formula represents the number of atoms of each element present in a molecule of a compound.
The number of atoms present in molecule is determined by the subscript written below the normal line in the molecular formula.
Answer to Problem 2.1E
The formula for a molecule of a compound containing one atom of one element and four atoms of another element by using circular symbols to represent atoms is shown below.
Explanation of Solution
It is given that the molecule contains one atom of one element and four atoms of another element. This can be explained with the help of one example. Considering an example that is carbon tetrachloride. The chemical formula of carbon tetrachloride is
Therefore, the formula for a molecule of a compound containing one atom of one element and four atoms of another element by using circular symbols to represent atoms is shown below.
Figure 4
In the given diagram, white circle represent carbon atom, whereas grey circle represent chlorine atoms.
The formula for a molecule of a compound containing one atom of one element and four atoms of another element by using circular symbols to represent atoms is shown in figure 4.
Want to see more full solutions like this?
Chapter 2 Solutions
Chemistry for Today: General, Organic, and Biochemistry
Additional Science Textbook Solutions
Microbiology Fundamentals: A Clinical Approach
Campbell Essential Biology with Physiology (5th Edition)
Human Biology: Concepts and Current Issues (8th Edition)
Fundamentals Of Thermodynamics
Physical Science
Organic Chemistry
- 4. Determine the amount in grams of AgCl (s) formed when 2.580 g AgNO3(s) is added to 45.00 mL of a 0.1250 M CrCl3 (aq) (The other product is aqueous chromium (III) nitrate) 5. Determine the amount (in grams) of Cobalt (II) phosphate formed when an aqueous solution of 30.0 ml of 0.450 M Sodium Phosphate is mixed with 20.0 mL of 0.500 M aqueous solution of cobalt (II) nitrate. (The other product is aqueous sodium nitrate)arrow_forward7. Consider the following reaction that describes the dissolution of copper metal in nitric acid: Cu (s) + 4 HNO3 (aq) → Cu(NO3)2 (aq) + 2 H₂O (1) + 2 NO2 (g) How many mL of 3.50 M HNO3 (aq) are required to dissolve 20.00 g Cu?arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Don't used Ai solutionarrow_forward3. An unknown element, X, combines with chlorine to give a substance with the formula XC14. A chlorine analysis of the substance indicates that it contains 83.47% chlorine by mass. What element is X and what is the formula of this compound? (Hint: to identify an element or compound, identify its molar mass. Remember that Molar Mass = (grams A)/(moles A). Solve for each individually and then divide them to find molar mass.)arrow_forward1. When hydrogen sulfide (H2S, MM = 34.08 g/mol) gas is bubbled into a solution of sodium hydroxide (NaOH, 40.00 g/mol), sodium sulfide (Na2S, 78.04 g/mol) and water (18.02 g/mol) are produced according to the balanced chemical equation shown below? H2S 2 NaOH --> Na2S 2 H₂O (a) Assuming the reaction goes to completion, how many grams of sodium sulfide are formed if 2.50g of hydrogen sulfide is bubbled into a solution containing 1.85g of NaOH? (20 pts) (b) Which reactant and how much of it remains after the reaction has been completed? (15 pts) (c) If only 0.400g of sodium sulfide was recovered, what is the percent yield of this reaction (5 pts)arrow_forward
- The organic compound MTBE (methyltertiarybutylether) is used as a fuel additive that allows gasoline to burn more cleanly thus leading to a reduction in pollution. Recently, however, MTBE has been found in the drinking water of a number of communities. As a result several states are phasing out the use of MTBE as a fuel additive. A combustion experiment using 10.00 g of MTBE was found to produce 24.97g of CO2 and 12.26 g of H2O. (a) What is the empirical formula of MTBE assuming it contains C, H, and O only? (b) The molar mass of MTBE was experimentally determined to be 88.1 g/mol. Using this information what is the molecular formula of MTBEarrow_forwardPart 4: Provide a detailed retrosynthetic analysis and a plausible forward synthesis the following molecule. храдо ofarrow_forward3A: Starting with benzocyclobutene, synthesize the naphthalene derivative below.arrow_forward
- 7. The addition of HBr to 2,5-dimethyl-2,4-heptadiene gives the same product, A, at both low and high temperatures. Provide the structure of A and explain the kinetic and thermodynamic product are the same in this reaction. HBr -78°C or 60°C Aarrow_forward3B: Convert the starting material into the chiral epoxytriol below. OH OH = OH OHarrow_forward3D: Convert the aromatic triketone to the 1,3,5-triethylcyclohexane shown below. ہوئےarrow_forward
Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning