Principles of Foundation Engineering
9th Edition
ISBN: 9780357684832
Author: Das
Publisher: Cengage Learning US
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Chapter 2, Problem 2.17P
To determine
Find the shear strength parameters peak cohesion
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Foundation: Direct Shear Test
20. A cohesionless sand sample was subjected to a triaxial shear test. Failure occurred when the normal stress is 400 KPa and the shear stress is 250 KPa. a. What is major principal stress? b. What is the minor principal stress
A triaxial shear test was performed on a well-drained sand sample. The normal stress on the failure plane and the shear stress on the failure plane, at failure were determined to be 6100 psf and 4600 psf, respectively.
a. Determine the angle of internal friction of the sand?
b. Determine the angle of the failure plane?
c. Determine the maximum principal stress?
Please answer this asap. For upvote. Thank you very much
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Principles of Foundation Engineering
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- Soil Mechanismarrow_forward2. A triaxial shear test was performed on a well-drained sand sample. The normal stress on the failure plane and the shear stress on the failure plane, at failure was determined to be 6,300 psf and 4,200 psf, respectively. a. Determine the angle of internal friction of the sand. b. Determine the angle of failure plane. c. Determine the maximum principal stress.arrow_forwardA consolidated undrained triaxial test was performed on a normally consolidated clay with a critical state friction angle of 230. After an initial isotropic consolidation at a cell pressure of 50 kPa, drainage was turned off, the cell pressure was increased to 85 kPa, and the sample was loaded to ultimate conditions. A pore pressure of 55 kPa was measured at ultimate state. What value of major principal total stress was measured at the ultimate state?arrow_forward
- A sand sample is subjected to direct shear testing. Two tests areperformed. For test 1, The sample shears at a stress of 2500 psf whenthe normal stress is 4000 psf.Test 2, The sample shears at a stress of 3500 psf when the normalstress is 6000 psf. Determine the following:a) Angle of Internal frictionb) Value of cohesionc) Compute the shear stress at a depth of 12 ft. if the unit weight ofthe soil is 150 pcfarrow_forwarda consolidated tri-axial test was conducted on a normally consolidated clay. the results were as follows: chamber confining pressure = 316 kPa, deviator stress = 424 kPa. compute for the shear stress on the failure plane in kPa.arrow_forwardTri-Axial Testsarrow_forward
- A consolidated drained (CD) triaxial test was carried out on a normally consolidated clay. The specimen was consolidated under a cell pressure of 100 kPa and back pressure of 30 kPa. The axial deviatoric stress was increased very slowly to failure, so that there was no excess pore water pressure developed during the shearing. The specimen failed under a deviatoric stress of 130 kPa. The back pressure of 30 kPa was maintained throughout the test. (i) What is the friction angle in terms of effective stresses? (ii) What are the shear stress and normal stress acting on the failure plane? Solution fast pleasearrow_forwardA consolidated drained (CD) triaxial test was carried out on a normally consolidated clay. The specimen was consolidated under a cell pressure of 100 kPa and back pressure of 30 kPa. The axial deviatoric stress was increased very slowly to failure, so that there was no excess pore water pressure developed during the shearing. The specimen failed under a deviatoric stress of 130 kPa. The back pressure of 30 kPa was maintained throughout the test. (1) What is the friction angle in terms of effective stresses? (ii) What are the shear stress and normal stress acting on the failure plane?arrow_forwardA triaxial shear test was performed on a well-drained sand sample. The normal stress on the failure plane and the shearing stress on the failure plane were determined to be 75kPa and 42kPa, respectively. Determine the angle of internal friction of the sand, in degrees.Determine the axial stress applied to the specimen, in kPa.arrow_forward
- A consolidated tri-axial test was conducted on a normally consolidated clay. The results were as follows: Chamber confining pressure = 304 kPa, Deviator stress = 419 kPa. Compute for the shear stress on the failure plane in kPa. Round off to two decimal places.arrow_forwardThree specimnens of clay having a small air-void content were tested in the shear box. Shear loading was started immediately after the application of the normal load and was completed in 8 minutes. The results are as follows: Normal Stress (kN/m2) Shear stress at failure (kN/m2) O Find the apparent cohesion of the clay. Find the angle of shearing resistance of the clay. What value of c would be obtained from an unconfined compression test on 145 241 337 103 117 131 the same soil?arrow_forwardGive me right solution according to the question... Otherwise leave it.. don't give me wrong solution I don't have time... Than youarrow_forward
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