Chapter 2, Problem 2.14NP

(a)

Interpretation Introduction

Interpretation: The work done needs to be calculated for an isothermal and reversible expansion of 1.25 mol of an ideal gas with initial temperature and pressure is 320 K and 3.10 bar. The final temperature is 1.00 bar and $C_{P,m}=\frac{5R}{2}$ .

Concept Introduction: For an adiabatic process, the heat involved is equal to zero. The molar heat capacity at constant volume is represented as $C_{V,m}$ and molar heat capacity at constant pressure is $C_{P,m}$ .

(b)

Interpretation Introduction

Interpretation: The work done needs to be calculated for an adiabatic and reversible expansion of 1.25 mol of an ideal gas with initial temperature and pressure is 320 K and 3.10 bar. The final temperature is 1.00 bar and $C_{P,m}=\frac{5R}{2}$ . The difference between the two results needs to be explained.

Concept Introduction: For an adiabatic process, the heat involved is equal to zero. The molar heat capacity at constant volume is represented as $C_{V,m}$ and molar heat capacity at constant pressure is $C_{P,m}$ .