Chapter 2, Problem 2.130CQ

Interpretation Introduction

Interpretation:

‘New volume of water’ should be identified.

Concept Introduction:

To calculate new volume of water, volume of gold and volume of silver need to be calculated from density of particular substance. And density can be shown as follows;

$\text{d}=\frac{\text{m}}{\text{v}}$

And by adding the volume of gold and silver to the total volume we will get the new volume as follows:

$\text{V}=75.5+{\text{v}}_1+{\text{v}}_2$