
Concept explainers
(a)
Interpretation:
The correct scenes that represent a mixture that fills a container is to be determined.
Concept introduction:
A mixture consists of a combination of two or more compounds or elements or compounds and elements which are physically intermingled. The components of a mixture are not
(a)

Answer to Problem 2.127P
The scenes that represent a mixture that fills a container are D and E.
Explanation of Solution
In the image D, an element and a compound are present which are not chemically bonded to each other. In the image E, a mixture of two elements is present which fills up the container.
The scenes that represent a mixture that fills a container are D and E.
(b)
Interpretation:
The scenes that represent a substance that cannot be broken down into simpler ones, are to be determined.
Concept introduction:
An element can be defined as the simplest type of matter which is composed of only one kind of atom. Hence elements can be represented by symbols. Elements cannot be broken down into simpler substances by any chemical or physical means. Examples are carbon, hydrogen, oxygen, sulfur, chlorine, etc.
(b)

Answer to Problem 2.127P
The scenes that represent a substance that cannot be broken down into simpler ones are A, C, G and I.
Explanation of Solution
A substance that cannot be broken down into simpler ones is called an element.
The scenes A and C depict polyatomic elements. In polyatomic elements, two or more atoms of the same element are bonded to each other. For example, sulfur. The element sulfur is also found in the octatomic state in which 8 atoms of sulfur are bonded to each other.
The scene G depicts a diatomic element whereas the scene I depicts a monatomic element.
The scenes that represent a substance that cannot be broken down into simpler ones are A, C, G and I.
(c)
Interpretation:
The scenes that represent an element with very high resistance to flow are to be determined.
Concept introduction:
An element can be defined as the simplest type of matter which is composed of only one kind of atom. Hence elements can be represented by symbols. Elements cannot be broken down into simpler substances by any chemical or physical means. Examples are carbon, hydrogen, oxygen, sulfur, chlorine, etc.
(c)

Answer to Problem 2.127P
The scene that represents an element with high resistance to flow is A.
Explanation of Solution
The scenes that represent elements are A, C, G and I
The resistance to flow is called viscosity. The viscosity of a matter is dependent on its state. Gases have the lowest viscosity whereas solids have the highest viscosity. Therefore, gases have the least resistance to their flow whereas solids have the highest resistance to flow.
Among A, C, G and I, C is a liquid whereas G and I are gases. In scene A, the element has a fixed shape and volume. These are the characteristics of a solid. Therefore, scene A represents an element with high resistance to flow.
The scene that represents an element with high resistance to flow is A.
(d)
Interpretation:
The scenes that represent a homogenous mixture, are to be determined
Concept introduction:
A mixture consists of a combination of two or more compounds or elements or compounds and elements which are physically intermingled. The components of a mixture are not chemically bonded to each other.
Mixtures can be classified as homogenous and heterogeneous mixtures. Homogenous mixtures are those which have a uniform composition. The components of a homogenous mixture cannot be seen separately through the eyes. Heterogeneous mixtures do not have a uniform composition. The components of a heterogeneous mixture can be seen separately and hence can be easily separated.
(d)

Answer to Problem 2.127P
The scenes that represent a homogenous mixture are E and H.
Explanation of Solution
In scene E, the two gaseous elements are a homogenous mixture. Since the phase of the mixture is the same (gaseous), hence it is impossible to see them separately through the eyes.
In scene H, the homogenous mixture is a mixture of two liquids. Since the phase of the mixture is the same (gaseous), hence it is a homogenous mixture.
The scenes that represent a homogenous mixture are E and H.
(e)
Interpretation:
The scenes that represent an element that conforms to the walls of its container and displays an upper surface are to be determined.
Concept introduction:
An element can be defined as the simplest type of matter which is composed of only one kind of atom. Hence elements can be represented by symbols. Elements cannot be broken down into simpler substances by any chemical or physical means. Examples are carbon, hydrogen, oxygen, sulfur, chlorine, etc.
(e)

Answer to Problem 2.127P
The scene that represents an element that conforms to the walls of its container and displays an upper surface is C
Explanation of Solution
An element may exist in solid, liquid and gaseous forms. Among the solids, liquids, and gases, the liquids conform to the walls of its container and display an upper surface.
The scenes that represent an element are A, C, G and I. The element in scene A is solid. The elements in scenes g and I are gases. The element in scene C is a liquid. Therefore scene C represents an element that conforms to the walls of its container and displays an upper surface.
The scene that represents an element that conforms to the walls of its container and displays an upper surface is C
(e)
Interpretation:
The scenes that represent an element that conforms to the walls of its container and displays an upper surface are to be determined.
Concept introduction:
An element can be defined as the simplest type of matter which is composed of only one kind of atom. Hence elements can be represented by symbols. Elements cannot be broken down into simpler substances by any chemical or physical means. Examples are carbon, hydrogen, oxygen, sulfur, chlorine, etc.
(e)

Answer to Problem 2.127P
The scene that represents an element that conforms to the walls of its container and displays an upper surface is C
Explanation of Solution
An element may exist in solid, liquid and gaseous forms. Among the solids, liquids, and gases, the liquids conform to the walls of its container and display an upper surface.
The scenes that represent an element are A, C, G and I. The element in scene A is solid. The elements in scenes g and I are gases. The element in scene C is a liquid. Therefore scene C represents an element that conforms to the walls of its container and displays an upper surface.
The scene that represents an element that conforms to the walls of its container and displays an upper surface is C
(f)
Interpretation:
The scenes that represent a gas that consists of diatomic particles are to be determined.
Concept introduction:
The matter is anything that has mass and occupies space. The three
Solids – Solids are those substances in which the constituent particles are tightly packed. Solids have a fixed shape and volume.
Liquids – Liquids are those substances in which the constituent particles are loosely packed compared to those of the solids but tighter than those of the gases. Liquids take the shape of the container they fill.
Gases – Gases are those substances in which the constituent particles are free to move around. Gases neither have a definite shape nor a definite volume.
(f)

Answer to Problem 2.127P
The scenes that represent a gas that consists of diatomic particles are B and G.
Explanation of Solution
The scenes that represent the gaseous states are B, D, E, F, G and I.
In the scenes D, E and I, the gases are monatomic. The gas in scene I is triatomic. The gases in scenes B and G are diatomic.
The scenes that represent a gas that consists of diatomic particles are B and G.
(g)
Interpretation:
The scenes that represent a gas that consists of diatomic particles are to be determined.
Concept introduction:
The matter is anything that has mass and occupies space. The three states of matter are as follows:
Solids – Solids are those substances in which the constituent particles are tightly packed. Solids have a fixed shape and volume.
Liquids – Liquids are those substances in which the constituent particles are loosely packed compared to those of the solids but tighter than those of the gases. Liquids take the shape of the container they fill.
Gases – Gases are those substances in which the constituent particles are free to move around. Gases neither have a definite shape nor a definite volume.
(g)

Answer to Problem 2.127P
The scenes that represent a gas that consists of diatomic particles are B and G.
Explanation of Solution
The scenes that represent the gaseous states are B, D, E, F, G and I.
In the scenes D, E and I, the gases are monatomic. The gas in scene I is triatomic. The gases in scenes B and G are diatomic.
The scenes that represent a gas that consists of diatomic particles are B and G.
(h)
Interpretation:
The scene that represents a substance with a
Concept introduction:
The law of definite composition - This law can be defined as; a particular compound maintains an exact universal proportion of elements in its composition, irrespective of the source. The proposal for this law was made by Joseph Proust.
(h)

Answer to Problem 2.127P
The scene that represents a substance with a
Explanation of Solution
In scene F, the gaseous compound is formed by the combination of two white balls representing atoms of one kind with one blue ball representing an atom of another kind. Here the ratio of the white balls to the blue ball is
The scene that represents a substance with a
(i)
Interpretation:
The scenes that represent a matter that can be separated into its component substances by physical means, are to be determined.
Concept introduction:
A mixture consists of a combination of two or more compounds or elements or compounds and elements which are physically intermingled. The components of a mixture are not chemically bonded to each other. The components of a mixture do not lose their individual identity. The components of a mixture are not chemically bonded to each other. Therefore, the mixture components can be separated using the physical methods.
(i)

Answer to Problem 2.127P
The scenes that represent a matter that can be separated into its component substances by physical means, are D, E, and H.
Explanation of Solution
The substances which can be separated into their components by physical methods are called mixtures.
The scenes A, C, Gand I represent elements in their pure forms. Scenes B and F represent compounds in their pure forms. Scene D represents a mixture of a gas and a liquid. Scene E represents, a mixture of two gases. Scene H represents a mixture of two liquids.
The scenes that represent a matter that can be separated into its component substances by physical means, are D, E, and H.
(j)
Interpretation:
The scene that represents a heterogeneous mixture is to be determined.
Concept introduction:
A mixture consists of a combination of two or more compounds or elements or compounds and elements which are physically intermingled. The components of a mixture are not chemically bonded to each other.
Mixtures can be classified as homogenous and heterogeneous mixtures. Homogenous mixtures are those which have a uniform composition. The components of a homogenous mixture cannot be seen separately through the eyes. Heterogeneous mixtures do not have a uniform composition. The components of a heterogeneous mixture can be seen separately and hence can be easily separated.
(j)

Answer to Problem 2.127P
The scene that represents a heterogeneous mixture is D.
Explanation of Solution
The scenes that represent a mixture are D, E and H. The scene E represents a homogenous mixture of two gases whereas the scene h represents a homogenous mixture of two liquids. Scene D represents a heterogeneous mixture since a boundary of distinction is visible for the two components of the mixture.
The scene that represents a heterogeneous mixture is D.
(k)
Interpretation:
The scenes that represent matter that obeys the law of definite composition are to be determined.
Concept introduction:
The law of definite composition - This law can be defined as; a particular compound maintains an exact universal proportion of elements in its composition, irrespective of the source. The proposal for this law was made by Joseph Proust.
(k)

Answer to Problem 2.127P
The scenes that represent matter that obeys the law of definite composition are B and F.
Explanation of Solution
The scenes that represent compounds are B and F. In scene B, the red and yellow balls represent two different atoms which have combined in the
The scenes that represent matter that obeys the law of definite composition are B and F.
Want to see more full solutions like this?
Chapter 2 Solutions
Loose Leaf for Chemistry: The Molecular Nature of Matter and Change
- Predict the major products of this organic reaction: OH NaBH4 H ? CH3OH Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. ☐ : Sarrow_forwardPredict the major products of this organic reaction: 1. LIAIHA 2. H₂O ? Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. X : ☐arrow_forwardFor each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forward
- As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forwardgive example for the following(by equation) a. Converting a water insoluble compound to a soluble one. b. Diazotization reaction form diazonium salt c. coupling reaction of a diazonium salt d. indacator properties of MO e. Diazotization ( diazonium salt of bromobenzene)arrow_forward
- 2-Propanone and ethyllithium are mixed and subsequently acid hydrolyzed. Draw and name the structures of the products.arrow_forward(Methanesulfinyl)methane is reacted with NaH, and then with acetophenone. Draw and name the structures of the products.arrow_forward3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forward
- What is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will its major product: 2,0° with a new C-C bond as If this reaction will work, draw the major organic product or products you would expect in the drawing aree below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and desh bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new C-C bond, just check the box under the drawing area and leave it blank.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





