Concept explainers
If the contacts on a manual starter cannot be closed immediately after a motor overload has tripped them open, what is the probable reason?
Explain the probable reason for allowing the time duration to reset the starter contacts after they tripped off by the overload protection equipment of the motor.
Explanation of Solution
Discussion:
The overload protection of the motor trips off (open) the contacts of a motor starter when the load exceeds the normal range. The overload protection equipment (heater) gets heated during the overload condition.
The contacts of the starter can reset only after the overload protection equipment cools completely. If the contacts are closed immediately, the heater does not cool properly due to the insufficient time and it lead to damage the motor as the overload still exists.
Conclusion:
Thus, the contacts of the motor starter cannot close immediately when the motor overload has tripped them open.
Want to see more full solutions like this?
Chapter 2 Solutions
Electric Motor Control
- Please help mearrow_forwardPlease help mearrow_forward3.7 The AM signal s(t) = Ac[1+kam(t)] cos(2nfct) is applied to the system shown in Figure P3.7. Assuming that |kam(t) 2W, show that m(t) can be obtained from the square-rooter output U3(t). s(t) Squarer v1(t) Low-pass 12(t) Square- filter ra(t) rooter V₁ (t) = 5² (t) 13(1)=√√12 (1) Figure P3.7arrow_forward
- A communication satellite is in stationary (synchronous) orbit about the earch (assume altitude of 22.300 statute miles). Its transmitter generates 8.00 W. Assume the transmit- ting antenna is isotropic. Its signal is received by the 210-ft diameter tracking parabo- loidal antenna on the earth at the NASA tracking station at Goldstone, California. Also assume no resistive loss in either antenna, perfect polarization match, and perfect impedance match at both antennas. At a frequency of 2 GHz, determine the: (a) power density (in watts/m²) incident on the receiving antenna. (b) power received by the ground-based antenna whose gain is 60 dB.arrow_forwardDetermine VO during the Negative Half Cycle of the input voltage, Vi 12 V f = 1 kHz -12 V C ... + 0.1 με Si R 56 ΚΩ Vo Vi 2 V - 0 +arrow_forward50mV and 10kHz from the function generator to the input. The mulitmeter postive is connected to the output and negative to a ground. Is the circuit connected correctly? Yes or No. Does the reading look correct? I don't need calculations but will take them. I just need to know if the connection is right. Connect a signal generator to the input and set it for 50 mV Sine wave with a frequency of 10 kHz. Connect the output to a multimeter set to RMS voltage. Record the output voltage and frequency in the following table. Repeat the measurement for all given frequency values in the table.arrow_forward
- Electricity for Refrigeration, Heating, and Air C...Mechanical EngineeringISBN:9781337399128Author:Russell E. SmithPublisher:Cengage Learning