Essentials of MIS (13th Edition)
13th Edition
ISBN: 9780134802756
Author: Kenneth C. Laudon, Jane Laudon
Publisher: PEARSON
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Question
Chapter 2, Problem 1IQ
Program Plan Intro
Information Systems:
- An
information system denotes a system that offers the necessary material to an organization for achieving the goals. - It monitors details of transactions, provides mandatory information to decision makers, and offers required documents to customers.
- The main components in the information system are people, data, procedures, hardware, and software.
- The main function is to accept as well as process input data, storing the retrieved information and distributing it across firm.
Expert Solution
Explanation of Solution
Details of company:
- The ABC Company is a subsidiary of Tata Group, an IT consulting and business Solution Company.
- It operates in 46 countries worldwide.
- It provides a wide range of IT related products and services.
- It includes business process outsourcing, application development, and consulting, capacity planning and education services.
- The ‘Software Engineer Trainee’ role is been provided to freshers in company.
Explanation of Solution
Commitment to technology:
- The company combines tech expertise and business intelligence to catalyse change as well as deliver results.
- The technology awareness programs inspires future workforce.
- The company supports research activities in technology areas.
- It has technology adoption and transformation solutions including mobile enablement and analytics.
- It ranges from product design and development to release.
Explanation of Solution
Following trend:
- Yes, there was a following trend on company Twitter account on regular basis.
- The details of company, including technological updates are learned from this.
- The company website also provides many details regarding product and services.
- The social media accounts also helped to know more about the company.
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Students have asked these similar questions
The next problem concerns the following C code:
/copy input string x to buf */
void foo (char *x) {
char buf [8];
strcpy((char *) buf, x);
}
void callfoo() {
}
foo("ZYXWVUTSRQPONMLKJIHGFEDCBA");
Here is the corresponding machine code on a Linux/x86 machine:
0000000000400530 :
400530:
48 83 ec 18
sub
$0x18,%rsp
400534:
48 89 fe
mov
%rdi, %rsi
400537:
48 89 e7
mov
%rsp,%rdi
40053a:
e8 d1 fe ff ff
40053f:
48 83 c4 18
add
callq 400410
$0x18,%rsp
400543:
c3
retq
0000000000400544 :
400544:
48 83 ec 08
sub
$0x8,%rsp
400548:
bf 00 06 40 00
mov
$0x400600,%edi
40054d:
e8 de ff ff ff
callq 400530
400552:
48 83 c4 08
add
$0x8,%rsp
400556:
c3
This problem tests your understanding of the program stack. Here are some notes to
help you work the problem:
• strcpy(char *dst, char *src) copies the string at address src (including
the terminating '\0' character) to address dst. It does not check the size of
the destination buffer.
You will need to know the hex values of the following characters:
A ROP (Return-Oriented Programming) attack can be used to execute arbitrary
instructions by chaining together small pieces of code called "gadgets." Your goal is
to create a stack layout for a ROP attack that calls a function located at '0x4018bd3'.
Below is the assembly code for the function 'getbuf', which allocates 8 bytes of stack
space for a 'char' array. This array is then passed to the 'gets' function. Additionally,
you are provided with five useful gadgets and their addresses. Use these gadgets to
construct the stack layout.
Assembly for getbuf
1 getbuf:
2
sub
$8, %rsp
3
mov
%rsp, %rdi
4
call
gets
56
add
$8, %rsp
ret
#Allocate 8 bytes for buffer
#Load buffer address into %rdi
#Call gets with buffer
#Restore the stack pointer
#Return to caller.
Stack
Layout
(fill
in
Gadgets
each
8-byte
section)
Address
Gadget
Address
Value (8 bytes)
0x4006a7 pop %rdi; ret
0x7fffffffdfc0
Ox4006a9 pop %rsi; ret
0x7fffffffdfb8
0x4006ab pop %rax; ret
0x7fffffffdfb0
0x7fffffffdfa8
Ox4006ad mov %rax,…
In each of the following C code snippets, there are issues that can prevent the compilerfrom applying certain optimizations. For each snippet:• Circle the line number that contains compiler optimization blocker.• Select the best modification to improve optimization.1. Which line prevents compiler optimization? Circle one: 2 3 4 5 6Suggested solution:• Remove printf or move it outside the loop.• Remove the loop.• Replace arr[i] with a constant value.1 int sum( int ∗ ar r , int n) {2 int s = 0 ;3 for ( int i = 0 ; i < n ; i++) {4 s += a r r [ i ] ;5 p r i n t f ( ”%d\n” , s ) ;6 }7 return s ;8 }2. Which line prevents compiler optimization? Circle one: 2 3 4 5 6Suggested solution:• Move or eliminate do extra work() if it’s not necessary inside the loop.• Remove the loop (but what about scaling?).• Replace arr[i] *= factor; with arr[i] = 0; (why would that help?).1 void s c a l e ( int ∗ ar r , int n , int f a c t o r ) {2 for ( int i = 0 ; i < n ; i++) {3 a r r [ i ] ∗= f a c t o r…
Chapter 2 Solutions
Essentials of MIS (13th Edition)
Ch. 2.2 - What Kinds of systems are illustrated in this case...Ch. 2.2 - Prob. 2CQ1Ch. 2.2 - Prob. 3CQ1Ch. 2.2 - Prob. 4CQ1Ch. 2.3 - Prob. 1CQ2Ch. 2.3 - Prob. 2CQ2Ch. 2.3 - Prob. 3CQ2Ch. 2 - Prob. 1IQCh. 2 - Prob. 2IQCh. 2 - Prob. 3IQ
Ch. 2 - Prob. 4IQCh. 2 - Prob. 5IQCh. 2 - Prob. 6IQCh. 2 - Prob. 1RQCh. 2 - Prob. 2RQCh. 2 - Prob. 3RQCh. 2 - Prob. 4RQCh. 2 - Prob. 5DQCh. 2 - Prob. 6DQCh. 2 - Prob. 7DQCh. 2 - Prob. 8HMPCh. 2 - Prob. 9HMPCh. 2 - Prob. 12CTPCh. 2 - Prob. 13CSQCh. 2 - Prob. 14CSQCh. 2 - Prob. 15CSQCh. 2 - Prob. 16MLMCh. 2 - Prob. 17MLM
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