A person gets in an elevator on the ground floor and rides it to the top floor of a building. Sketch a velocity-versus-time graph for this motion.
Expert Solution & Answer
To determine
To draw: The velocity-versus-time graph.
Answer to Problem 1CQ
The velocity-versus-time graph is drawn.
Explanation of Solution
Given data:
A person gets in an elevator on the ground floor and rides it to the top floor of a building.
Explanation:
Normally when the elevator starts to function, initially the speed or velocity will be low and then gradually increases its speed. In the middle period of the elevator functioning, the speed becomes constant and at end period speed slows down and comes to rest.
The velocity-versus-time graph for the above scenario is shown in Figure 1.
Initially graph starts from zero, gradually increases. During middle period velocity remains constant showing horizontal line in the graph. During end period there will be gradual decrease and end at zero in the graph.
Conclusion:
Hence, the velocity-versus-time graph is drawn.
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4
Problem 4) A particle is being pushed up a smooth slot by a rod. At the instant when 0 = rad,
the angular speed of the arm is ė = 1 rad/sec, and the angular acceleration is = 2 rad/sec².
What is the net force acting on the 1 kg particle at this instant? Express your answer as a vector
in cylindrical coordinates. Hint: You can express the radial coordinate as a function of the angle
by observing a right triangle. (20 pts)
Ꮎ
2 m
Figure 3: Particle pushed by rod along vertical path.
4
Problem 4) A particle is being pushed up a smooth slot by a rod. At the instant when 0 = rad,
the angular speed of the arm is ė = 1 rad/sec, and the angular acceleration is = 2 rad/sec².
What is the net force acting on the 1 kg particle at this instant? Express your answer as a vector
in cylindrical coordinates. Hint: You can express the radial coordinate as a function of the angle
by observing a right triangle. (20 pts)
Ꮎ
2 m
Figure 3: Particle pushed by rod along vertical path.
please solve and answer the question correctly. Thank you!!
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