The elements having the ground-state electronic configurations different from what we would expect from their positions in the periodic table are to be listed. Concept Introduction: The distribution of the electrons present in an atom in the respective atomic orbitals is known as the electronic configuration. However, some elements have different ground-state configurations than expected from their placement in the periodic table. To determine: The elements having different ground-state configurations than expected from their placement in the periodic table.
The elements having the ground-state electronic configurations different from what we would expect from their positions in the periodic table are to be listed. Concept Introduction: The distribution of the electrons present in an atom in the respective atomic orbitals is known as the electronic configuration. However, some elements have different ground-state configurations than expected from their placement in the periodic table. To determine: The elements having different ground-state configurations than expected from their placement in the periodic table.
The elements having the ground-state electronic configurations different from what we would expect from their positions in the periodic table are to be listed.
Concept Introduction:
The distribution of the electrons present in an atom in the respective atomic orbitals is known as the electronic configuration. However, some elements have different ground-state configurations than expected from their placement in the periodic table.
To determine: The elements having different ground-state configurations than expected from their placement in the periodic table.
Expert Solution & Answer
Answer to Problem 140AE
Answer
The elements
Cr,Cu,Nb,Mo,Tc,Ru,Rh,Pd,Ag,Pt,AuandRg exhibit electronic configurations different from their expected ones.
Explanation of Solution
The filling of orbitals according to their energy levels gives the expected ground-state electronic configurations for the elements. And the following elements exhibit ground-state configurations that are different from what was expected with respect to their placement in the periodic table.
In the case of Chromium and copper, the expected configuration in accordance to the Aufbau principle would be,
This happens as completely filled sub levels are more stable than the partly filled ones. Also, a half filled sub level is more stable than the partly filled one.
In the case of Niobium, the expected configuration in accordance to the Aufbau principle would be,
Nb=(1s22s22p63s23p63d104s24p65s24d3)
But the actual configuration it exhibits is,
Nb=(1s22s22p63s23p63d104s24p65s14d4)
The repulsion of two electrons within the same orbital pushes one electron from the
5s to the
4d orbital.
Some other elements that exhibit electronic configurations different from expected ones are,
The compounds that portray the
d10 systems do so in order to attain extra stability. In case of the
RuandRh, such configurations are attained by these compounds in order to attain extra stability by attaining a completely filled
T2g orbitals.
Conclusion
The elements having the ground-state electronic configurations different from what we would expect from their positions in the periodic table are
Cr,Cu,Nb,Mo,Tc,Ru,Rh,Pd,Ag,Pt,AuandRg.
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(11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the
molecule depicted below.
Bond B
Bond A
Bond C
a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in
appropriate boxes.
Weakest
Bond
Strongest
Bond
b. (4pts) Consider the relative stability of all cleavage products that form when bonds A,
B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B,
and C are all carbon radicals.
i. Which ONE cleavage product is the most stable? A condensed or bond line
representation is fine.
ii. Which ONE cleavage product is the least stable? A condensed or bond line
representation is fine.
c. (5pts) Use principles discussed in lecture, supported by relevant structures, to
succinctly explain the why your part b (i) radical is more stable than your part b(ii)
radical. Written explanation can be no more than one-two succinct sentence(s)!
.
3°C
with
TH
12. (10pts total) Provide the major product for each reaction depicted below. If no reaction
occurs write NR. Assume heat dissipation is carefully controlled in the fluorine reaction.
3H
24 total (30)
24
21
2h
• 6H total
● 8H total
34
래
Br2
hv
major product
will be most
Substituted
12
hv
Br
NR
I too weak of a
participate in P-1
F₂
hv
Statistically
most favored
product will be
major
=
most subst =
thermo favored
hydrogen atom abstractor to
LL
F
Five chemistry project topic that does not involve practical
Chapter 2 Solutions
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