Chapter 2, Problem 116E

Interpretation Introduction

Interpretation: From the given density and volume, the mass of the fuel is to be calculated in pounds.

Concept Introduction:

Density is defined as mass per unit volume.

$d=\frac{m}{V}$

Here, $m$ is the mass of the substance and $V$ is the volume of the substance.

The relation between liters and cubic centimeters is:

$1\text{L}=1000{\text{cm}}^3$

The relation between grams, kilograms and pounds is:

$\begin{array}{l}\text{1}\text{g}\text{=}{\text{10}}^{\text{-3}}\text{kg}\\ 1\text{kg}\text{=}\text{2}\text{.20462}\text{lb}\end{array}$

To convert a quantity, $a{u}_1$ from one unit to another i.e. $u_1\to u_2$ first write a conversion factor $\frac{u_2}{u_1}$ by the use of the relation of the given quantities.

Multiply the conversion factor with the given quantity $a{u}_1$ and cancelling units to get the quantity in desired units.

$a\cancel{u_1}\times \frac{u_2}{\cancel{u_1}}=a{u}_2$