Chapter 2, Problem 115APP

(a)

Interpretation Introduction

Interpretation :

The conversion of $\text{65 mi/h}$ to $\text{ft/s}$ should be done with appropriate conversion factors.

Concept Introduction :

Various units are used to express mass, volume, length etc. These units can convert into each other with the help of equality. The fraction of any equality is called conversion factors. In conversion factor, equalities are written as numerator and denominator.

(b)

Interpretation Introduction

Interpretation : The conversion of $\text{\$ 0}\text{.75 / lb}$ to $\text{cents/kg}$ should be done with appropriate conversion factors.

Concept Introduction :

Various units are used to express mass, volume, length etc. These units can convert into each other with the help of equality. The fraction of any equality is called conversion factors. In conversion factor, equalities are written as numerator and denominator.

(c)

Interpretation Introduction

Interpretation : The conversion of $\text{1}\text{.63 g/mL}$ to $\text{lb/gal}$ should be done with appropriate conversion factors.

Concept Introduction :

Various units are used to express mass, volume, length etc. These units can convert into each other with the help of equality. The fraction of any equality is called conversion factors. In conversion factor, equalities are written as numerator and denominator.

(d)

Interpretation Introduction

Interpretation : The conversion of $\text{11 m/s}$ to $\text{mi/h}$ should be done with appropriate conversion factors.

Concept Introduction :

Various units are used to express mass, volume, length etc. These units can convert into each other with the help of equality. The fraction of any equality is called conversion factors. In conversion factor, equalities are written as numerator and denominator.