HUMAN BIOLOGY W/ACCESS
HUMAN BIOLOGY W/ACCESS
16th Edition
ISBN: 9781260997231
Author: Mader
Publisher: MCG
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Chapter 19.6, Problem 4CYP
Summary Introduction

To analyze:

The nondisjunction events that cause Turner and Jacobs’s syndromes.

Introduction:

The presence of the abnormal number of chromosomes in an individual may be the result of nondisjunction during meiosis. Nondisjunction is the failure of separation of homologous chromosomes during anaphase-I and the failure of separation of sister chromatids during anaphase-II of meiosis.

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Question #3: In the KeyGene paper, the authors state that it would be useful if pollen from an apomict would transmit apomixis-inducing genes to the female in the cross (assuming the pollen is viable). Assuming there was just one gene conferring gametophytic obligate apomixis, and that the two parents are inbreds, what would be the consequences of such a cross if: a) The apomixis was a dominant trait? Indicate the genotypes and phenotypes (apomict or non- apomict) of the parents, F1 and F2 generations. Remember to include the expected genotypic and phenotypic ratios (or percentages) in the F1 and F2 generations, and to position the female first (left side) in the parental cross. b) The apomixis was a recessive trait? Indicate the genotypes and phenotypes (apomict or non- apomict) of the parents, F1 and F2 generations. Remember to include the expected genotypic and phenotypic ratios (or percentages) in the F1 and F2 generations, and to position the female first (left side) in the…
Question #5: Assume that two genes are identified that confer gametophytic facultative apomixis in soybean. The genes show independent assortment. Recessive alleles at both loci are required for the facultative apomixis. Facultative apomixis is triggered when the temperature at pollination is above 20 degrees C. At temperatures below 20 degrees C, all reproduction is sexual, independent of genotype. A facultative apomict male, capable of producing viable pollen, was crossed with a sexually reproducing female. Assuming the parents are completely inbred, what are the predicted phenotypic ratios (apomict: non-apomict) for the F1, F2, and DH (F1-derived) generations at each of the following temperatures*: a) 15°C? b) 25°C? *for full credit, show crosses and genotypes where appropriate. Remember to position the female first (left side) in the cross. Type your answer here:

Chapter 19 Solutions

HUMAN BIOLOGY W/ACCESS

Ch. 19.2 - Prob. 2CYPCh. 19.2 - Prob. 3CYPCh. 19.2 - Summarize why external controls may be necessary...Ch. 19.3 - Prob. 1LOCh. 19.3 - Prob. 2LOCh. 19.3 - Prob. 3LOCh. 19.3 - Prob. 1CYPCh. 19.3 - Prob. 2CYPCh. 19.3 - Prob. 3CYPCh. 19.4 - Prob. 1LOCh. 19.4 - Prob. 2LOCh. 19.4 - Prob. 3LOCh. 19.4 - Prob. 1CYPCh. 19.4 - Explain how meiosis reduces the likelihood that...Ch. 19.4 - Prob. 3CYPCh. 19.4 - Compare and contrast the stages of oogenesis and...Ch. 19.5 - Prob. 1LOCh. 19.5 - Prob. 2LOCh. 19.5 - List the similarities and differences between...Ch. 19.5 - Prob. 2CYPCh. 19.5 - Prob. 3CYPCh. 19.6 - Prob. 1LOCh. 19.6 - Describe the causes and consequences of trisomy...Ch. 19.6 - Prob. 3LOCh. 19.6 - 4. Describe the effects of deletions,...Ch. 19.6 - Prob. 1BTSCh. 19.6 - Prob. 2BTSCh. 19.6 - Prob. 1CYPCh. 19.6 - Prob. 2CYPCh. 19.6 - Prob. 3CYPCh. 19.6 - Prob. 4CYPCh. 19 - Prob. 1ACh. 19 - 2. Which of the following is/are produced by the...Ch. 19 - 3. Label the drawing of the cell cycle: then list...Ch. 19 - 4. At which of the following checkpoints is the...Ch. 19 - ...Ch. 19 - ...Ch. 19 - a. metaphase b....Ch. 19 - ...Ch. 19 - metaphase prornetaphase telophase prophase c....Ch. 19 - 10. If a parent cell has a diploid number of 18...Ch. 19 - 11. If a parent cell has 22 chromosomes. the...Ch. 19 - 12. Crossing-over occurs between sister chromatids...Ch. 19 - 13. Which of these helps provide genetic...Ch. 19 - 14. Polar bodies are produced during DNA...Ch. 19 - 15. The pairing of homologous chromosomes occurs...Ch. 19 - 16. Sister chromatids separate during anaphase of...Ch. 19 - 17. Monosomy or trisomy occurs because...Ch. 19 - 18. A person with Klinefelter syndrome is and...Ch. 19 - Prob. 1TCCh. 19 - Prob. 2TCCh. 19 - Prob. 3TCCh. 19 - Prob. 4TC
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