FUNDAMENTALS OF MATERIALS SCIENCE AND E
5th Edition
ISBN: 9781119571803
Author: Callister
Publisher: WILEY
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Chapter 19.14, Problem 14QP
To determine
The range of wavelengths of visible light if it is transparent.
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SITUATION 1: A W250 x 131 is used as a column with an unbraced length of 8 m with respect to the x-x axis
and 4 m with respect to the y-y axis. Assume an A36 steel member, pin-connected at the top and fixed at the
bottom. Assume that the column is pin connected at mid-height. Use NSCP 2001 NSCP. Fy = 250 MPa.
Properties of W250 x 131:
A = 16,774 mm²
d=274 mm
bf=262 mm
tf=25 mm
tw = 16 mm
Ix=222.268 x 10 mm
ly = 74.505 x 10° mm*
Effective Length Factors:
Pinned at both ends, K = 1.0
Pinned at one end and fixed at the other, K = 0.8
1. What is the value of the slenderness ratio to be used for the column?
2. What is the nominal axial stress?
3. What is the design axial load?
1. 60.019
2. 206.543 MPa
3. 3118.091 kN
Use the ramp generator circuit in Fig. B2a to generate the waveform
shown in Fig. B2b.
Write four equations relating resistors R1, R2, R3, capacitor C
and voltages Vs, VR and VA.to the waveform parameters T₁, T,
Vcm and Vm-
If R = R2 = R3, R₁ = 2R, C = 1 nF, Vcm = 2 V and Vm = 1 V, T₁ =
2 μs and T = 10 μs solve for the values of R, Vs, VR and VA
using your equations from part a(i).
VR
C
+VA
R3
V₂
Vo
мат
R1
VsO+
V₁
R₂
Figure B2a
Vout
Vcm+Vm
Vcm
Vcm-Vm
0
T₁
T
2T
time
Figure B2b
CORRECT ANSWER ONLY WITH COMPLETE FBD. PREFERABLY HANDWRITTEN. I WILL UPVOTE
1. The beam shown carries the following loads:Total dead load, wDL = 36 kN/mConcentrated live load, PLL = 240 kNThe beam section is HSS16X12X3/8 with properties:Span, L = 6 mArea, A = 12,100 mm2Moment of inertia about x-axis, Ix = 292 x 106 mm4Fy = 345 MPa
1. Calculate the location of the live load, from the left support, for maximum moment to occur at the fixed support.Answer: 2.536 m2. Calculate the maximum moment. Answer: 439.128 kN-m
Chapter 19 Solutions
FUNDAMENTALS OF MATERIALS SCIENCE AND E
Ch. 19.14 - Prob. 1QPCh. 19.14 - Prob. 2QPCh. 19.14 - Prob. 3QPCh. 19.14 - Prob. 4QPCh. 19.14 - Prob. 5QPCh. 19.14 - Prob. 6QPCh. 19.14 - Prob. 7QPCh. 19.14 - Prob. 8QPCh. 19.14 - Prob. 9QPCh. 19.14 - Prob. 10QP
Ch. 19.14 - Prob. 11QPCh. 19.14 - Prob. 12QPCh. 19.14 - Prob. 13QPCh. 19.14 - Prob. 14QPCh. 19.14 - Prob. 15QPCh. 19.14 - Prob. 16QPCh. 19.14 - Prob. 17QPCh. 19.14 - Prob. 18QPCh. 19.14 - Prob. 19QPCh. 19.14 - Prob. 20QPCh. 19.14 - Prob. 21QPCh. 19.14 - Prob. 22QPCh. 19.14 - Prob. 23QPCh. 19.14 - Prob. 24QPCh. 19.14 - Prob. 25QPCh. 19.14 - Prob. 26QPCh. 19.14 - Prob. 27QPCh. 19.14 - Prob. 28QPCh. 19.14 - Prob. 1DPCh. 19.14 - Prob. 1FEQPCh. 19.14 - Prob. 2FEQP
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- The circuit in Figure B1a is a common analogue circuit block. Explain why you would need such a circuit. Draw another circuit in which you use the current flowing in this loop to bias a common source amplifier. This circuit is not ideal for standard CMOS technologies due to threshold shift. Why? Draw an improved version of this circuit to make it better. VDD (W)P MA M3. (), REF (쁜)~ M₁ M2 lout 시~ Rsarrow_forwardSITUATION 2: An 8-meter simply supported beam is to be loaded, in addition to its self-weight, a triangular distributed load that linearly increases from zero at the left support to 20 kN/m (dead) + 35 kN/m (live) at the right support. It is braced laterally at the end supports and at midspan. The details for the beam cross-section are given below. Use the LRFD provisions of NSCP 2015. W 540 mm x 150 kg/m: Area, A 19,225 mm² Depth, D = 540 mm Clear Distance between Flanges, h = 455 mm Flange width, bf=310 mm Flange thickness, tf = 20 mm Web thickness, tw 12.5 mm Elastic Section Modulus, Sx = 3.72 x 106 mm³ Plastic Section Modulus, Zx = 4.14 x 10 mm³ Torsional Constant, J = 2.04 x 10% mm* Distance between flange centroids, ho = 520 mm Radius of gyration along y-axis, ry = 72 mm Cb = 1.196 Effective radius of gyration, rts = 85 mm Yield Strength of Steel, Fy = 345 MPa Modulus of Elasticity, E=200 GPa 1. What is the ultimate moment capacity of the beam, in kN-m? 1. 1285.470 kN-marrow_forward23bcarrow_forward
- CORRECT ANSWER AND COMPLETE FBD ONLY. I PREFER HANDWRITTEN BUT ITS OKAY IF NOT. I WILL UPVOTE 2. The space truss shown is supported by ball-and-socket joints at A, B and C. Factored loads P1 and P2 areacting on joints D and E, respectively, towards the negative y-direction. 1. Calculate the stress of member CE, indicate tension or compression. Answer: 23.61 MPa Tension2. Calculate the stress of member AD, indicate tension or compression. Answer: 21.01 MPa Compression3. Calculate the stress of member CD, indicate tension or compression. Answer: 11.03 MPa Tensionarrow_forwardSITUATION 4: A steel column W 300 x 203 kg/m is subjected to an axial load of 2670 kN. Unbraced length of column is 3m, and assume that the column is pinned at both ends, side sway prevented. Show your complete solution and box only the final answer. Properties of Column: Area, A = 25,740 mm² Depth, d=340 mm Flange thickness, tf = 32 mm Flange Width, bf=315 mm Web thickness, tw = 20 mm Ix = 5.16 x 10 mm² ly = 1.65 x 10° mm* Fy = 345.6 MPa 1. Determine the design strength (kN) of the column. 2. Determine the allowable strength (kN) of the column. 3. What is the value of the slenderness ratio to be used for the column? 1. 7223.401 kN 2. 4805.988 kN 3. 37.470arrow_forwardDraw the small-signal equivalent circuit of a single transistor amplifier given in figure B1b. Assume the current source to be ideal. Determine the Open-loop transfer function, pole frequency and gain-bandwidth product all in terms of transistor parameters 9m, To and CL. If the load capacitance is 1pF and the necessary unity gain frequency is 600MHz, find the gm for this transistor. V₁ V₁ CLarrow_forward
- CORRECT ANSWER AND COMPLETE FBD ONLY. I PREFER HANDWRITTEN BUT ITS OKAY IF NOT. I WILL UPVOTE 3. The frame has pin supports at A and E, subject to a wind load. Treat joint C to be an internal hinge. Given:Dimensions, H1 = 3.0 m; H2 = 4.5 m; L = 10.0 mWind loads, wWL (AB) = 4.8 kN/m; wWL (BC) = 3.9 kN/m; wWL (CD) = 1.5 kN/m; wWL (DE) = 1.2 kN/mMembers are made of A36 steel Wide Flange Section with the following properties:Area, A = 64000 mm2Depth, d = 762 mmFlange width, bf = 371 mmThickness of web, tw = 32 mmThickness of flange, tf = 57.9 mmMoment of inertia about x-axis, Ix = 6080 x 106 mm4The wide flange is oriented so that the bending is about the x-axis1. Calculate the stress in member AB, due to the axial load it carries, indicate if tension or compression.Answer: 0.0476 MPa Tension2. Calculate the stress in member DE, due to the axial load it carries, indicate if tension or compression.Answer: 0.2351 MPa Compression3. Calculate the maximum bending stress at B. Answer: 4.282 MPaarrow_forward23baarrow_forward23caarrow_forward
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