ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT
ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT
2nd Edition
ISBN: 9781119288510
Author: Klein
Publisher: WILEY
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Chapter 19.12, Problem 31ATS
Interpretation Introduction

Interpretation:

The two possible reaction pathways for the synthesis of the following compound have to be described and the one which furnishes the product with higher yield has to be analyzed.

                                                 ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT, Chapter 19.12, Problem 31ATS

Concept Introduction:

  • Friedel Crafts reaction is an electrophilic substitution reaction. This reaction is useful to introduce alkyl or acyl group onto benzene ring. So this reaction is commonly known as Friedel Crafts acylation if acyl group is imparted on benzene ring or Friedel Crafts alkylation if alkyl group is imparted on benzene ring.
  • Benzene is highly stable that the mere presence of any alkyl or acyl halide is not enough to initiate the reaction. Lewis acids such as AlCl3,FeCl3,BF3etc is required to initiate the reaction. The Lewis acid catalyst assists in the formation of electrophile. Alkyl halide reacts with Lewis acid and generates a complex. The complex decomposes and forms alkyl ion which functions as electrophile.
  • The so formed alkyl ion must be highly stable in order to bond with benzene Carbon. Of all the carbocations primary, secondary and tertiary, tertiary carbocation is the most stable.
  • The order of the stability of carbocations can be represented as follows –
  • Primary carbocation < Secondary carbocation < Tertiary carbocation
  • The type of carbocation initially formed depends upon the alkyl halide. But it rearranges itself to the most stable form. This phenomenon poses some drawbacks to Friedel Crafts reaction that some compounds can’t be prepared by this reaction. 

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Chapter 19 Solutions

ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT

Ch. 19.7 - Prob. 11CCCh. 19.7 - Prob. 12CCCh. 19.8 - Prob. 13CCCh. 19.9 - Prob. 14CCCh. 19.9 - Prob. 15CCCh. 19.10 - Prob. 1LTSCh. 19.10 - Prob. 16PTSCh. 19.10 - Prob. 17ATSCh. 19.10 - Prob. 18ATSCh. 19.11 - Prob. 2LTSCh. 19.11 - Prob. 19PTSCh. 19.11 - Prob. 20ATSCh. 19.11 - Prob. 21ATSCh. 19.11 - Prob. 3LTSCh. 19.11 - Prob. 22PTSCh. 19.11 - Prob. 23ATSCh. 19.11 - Prob. 24ATSCh. 19.11 - Prob. 4LTSCh. 19.11 - Prob. 25PTSCh. 19.11 - Prob. 26ATSCh. 19.11 - Prob. 27ATSCh. 19.12 - Prob. 28CCCh. 19.12 - Prob. 29CCCh. 19.12 - Prob. 5LTSCh. 19.12 - Prob. 30PTSCh. 19.12 - Prob. 31ATSCh. 19.12 - Prob. 32ATSCh. 19.12 - Prob. 6LTSCh. 19.12 - Prob. 33PTSCh. 19.12 - Prob. 34ATSCh. 19.13 - Prob. 35CCCh. 19.13 - Prob. 36CCCh. 19.13 - Prob. 37CCCh. 19.14 - Prob. 38CCCh. 19.14 - Prob. 39CCCh. 19.15 - Prob. 7LTSCh. 19.15 - Prob. 40PTSCh. 19.15 - Prob. 41PTSCh. 19.15 - Prob. 42ATSCh. 19 - Prob. 43PPCh. 19 - Prob. 44PPCh. 19 - Prob. 45PPCh. 19 - Prob. 46PPCh. 19 - Prob. 47PPCh. 19 - Prob. 48PPCh. 19 - Prob. 49PPCh. 19 - Prob. 50PPCh. 19 - Prob. 51PPCh. 19 - Prob. 52PPCh. 19 - Prob. 53PPCh. 19 - Prob. 54PPCh. 19 - Prob. 55PPCh. 19 - Prob. 56PPCh. 19 - Prob. 57PPCh. 19 - Prob. 58PPCh. 19 - Prob. 59PPCh. 19 - Prob. 60PPCh. 19 - Prob. 61PPCh. 19 - Prob. 62PPCh. 19 - Prob. 63PPCh. 19 - Prob. 64PPCh. 19 - Prob. 65PPCh. 19 - Prob. 66PPCh. 19 - Prob. 67PPCh. 19 - Prob. 68PPCh. 19 - Prob. 69PPCh. 19 - Prob. 70PPCh. 19 - Prob. 71PPCh. 19 - Prob. 72PPCh. 19 - Prob. 73PPCh. 19 - Prob. 74IPCh. 19 - Prob. 75IPCh. 19 - Prob. 76IPCh. 19 - Prob. 77IPCh. 19 - Prob. 78IPCh. 19 - Prob. 79IPCh. 19 - Prob. 80IPCh. 19 - Prob. 81IPCh. 19 - Prob. 82IPCh. 19 - Prob. 83IP
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