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Fill in the data for a 16-ampere electric motor, single-phase, no Code letters.
- a. Branch-circuit protection, non-time-delay fuses:
Normal size _____________A Maximum size _____________A
Switch size _____________A Switch size _____________A
- b. Branch-circuit protection dual-element, time-delay fuses:
Normal size _____________A Maximum size _____________A
Switch size _____________A Switch size _____________A
- c. Branch-circuit protection instant-trip breaker:
Normal setting _____________A
Maximum setting _____________A
- d. Branch-circuit protection—inverse time breaker:
Normal rating _____________A
Maximum rating _____________A
- e. Branch-circuit conductor size, Type THHN
Ampacity _____________A
- f. Motor overload protection using dual-element time-delay fuses:
Maximum size _____________A
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Chapter 19 Solutions
ELECTRICAL WIRING:RESIDENTAL-6 PLANS
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- 3 (10pts). A Factory produces light bulbs from two different machines: Machine A and Machine B. The probability that a randomly selected light bulbs is from Machine A is 60%, and the probability that a light bulb is defective is 5%. Suppose that probability that a light bulb is defective given that it was made by Machine A is 0.05. Similarly, the probability that a light bulb is defective given that it was made by Machine B is 0.03. Are the events "the light bulb is from Machine A" and "the light bulb is defective" independent?arrow_forwardPlease see the followinggn imagearrow_forwardImage is attachedarrow_forward
- Using Carson's rule, determine the transmission bandwidth for commercial FM radio broadcasting, provided that the maximum value of frequency deviation is 75 kHz and the bandwidth of the audio signal is 15 kHzarrow_forward2. Laboratory Preliminary Discussion First-order High-pass RC Filter Analysis The first-order high-pass RC filter shown in figure 3 below represents all voltages and currents in the time domain. We will again convert the circuit to its s-domain equivalent as shown in figure 4 and apply Laplace transform techniques. ic(t) C vs(t) i₁(t) + + vc(t) R1 ww Vi(t) || 12(t) V2(t) R₂ Vout(t) VR2(t) = V2(t) Figure 3: A first-order high-pass RC filter represented in the time domain. Ic(s) C + Vs(s) I₁(s) + + Vc(s) R₁ www V₁(s) 12(s) V₂(s) R₂ Vout(S) = VR2(S) = V2(s) Figure 4: A first-order high-pass RC filter represented in the s-domain. Again, to generate the s-domain expression for the output voltage, You (S) = V2 (s), for the circuit shown in figure 4 above, we can apply voltage division in the s-domain as shown in equation 2 below. Equation 2 will be used in the prelab computations to find an expression for the output voltage, xc(t), in the time domain. equation (2) R₂ Vout(s) = V₂(s) = R₂+…arrow_forwardCan you show me the steps to get the last part after the second equal sign.arrow_forward
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