Introductory Chemistry Plus Mastering Chemistry with Pearson eText -- Access Card Package (6th Edition) (New Chemistry Titles from Niva Tro)
6th Edition
ISBN: 9780134290812
Author: Nivaldo J. Tro
Publisher: PEARSON
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Chapter 19, Problem 7SAQ
Interpretation Introduction
Interpretation: The product of the reaction is to be determined.
Concept Introduction: The compounds having carbon and hydrogen atoms are called hydrocarbons.
The hydrocarbons with double bond are known as
The alkenes undergo addition reaction, in which the atom is added across the double bond.
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need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Please correct answer and don't used hand raiting
need help please and thanks dont understand a-b
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal energy
Divide the…
Chapter 19 Solutions
Introductory Chemistry Plus Mastering Chemistry with Pearson eText -- Access Card Package (6th Edition) (New Chemistry Titles from Niva Tro)
Ch. 19 - Prob. 1SAQCh. 19 - Prob. 2SAQCh. 19 - Which compound is an amino acid?Ch. 19 - Q4. The sequence of amino acids in a protein chain...Ch. 19 - Prob. 5SAQCh. 19 - Prob. 6SAQCh. 19 - Prob. 7SAQCh. 19 - Prob. 8SAQCh. 19 - Prob. 9SAQCh. 19 - Q10. How many nucleotides are required to code for...
Ch. 19 - Prob. 1ECh. 19 - Prob. 2ECh. 19 - Prob. 3ECh. 19 - Prob. 4ECh. 19 - Prob. 5ECh. 19 - Prob. 6ECh. 19 - Prob. 7ECh. 19 - Prob. 8ECh. 19 - Prob. 9ECh. 19 - Prob. 10ECh. 19 - Prob. 11ECh. 19 - Prob. 12ECh. 19 - Prob. 13ECh. 19 - Prob. 14ECh. 19 - Prob. 15ECh. 19 - Prob. 16ECh. 19 - What are steroids? What are some of the functions...Ch. 19 - Prob. 18ECh. 19 - What are the main functions of proteins within...Ch. 19 - Prob. 20ECh. 19 - Prob. 21ECh. 19 - Prob. 22ECh. 19 - Prob. 23ECh. 19 - Prob. 24ECh. 19 - Prob. 25ECh. 19 - Prob. 26ECh. 19 - Prob. 27ECh. 19 - Prob. 28ECh. 19 - Prob. 29ECh. 19 - Prob. 30ECh. 19 - Prob. 31ECh. 19 - Prob. 32ECh. 19 - Prob. 33ECh. 19 - Prob. 34ECh. 19 - Prob. 35ECh. 19 - Prob. 36ECh. 19 - What is a gene?Ch. 19 - Prob. 38ECh. 19 - Prob. 39ECh. 19 - Do most cells in the human body contain genes for...Ch. 19 - Prob. 41ECh. 19 - Prob. 42ECh. 19 - Prob. 43ECh. 19 - 44. Describe the process of protein synthesis.
Ch. 19 - Prob. 45ECh. 19 - Prob. 46ECh. 19 - Prob. 47ECh. 19 - Prob. 48ECh. 19 - Prob. 49ECh. 19 - Prob. 50ECh. 19 - Prob. 51ECh. 19 - Prob. 52ECh. 19 - Prob. 53ECh. 19 - 54. Determine whether each molecule is a lipid. If...Ch. 19 - 55. Sketch the block diagram for a triglyceride.
Ch. 19 - 56. Sketch the block diagram for a phospholipid....Ch. 19 - 57. Draw the structure of the triglyceride that...Ch. 19 - Prob. 58ECh. 19 - Prob. 59ECh. 19 - Prob. 60ECh. 19 - Prob. 61ECh. 19 - Prob. 62ECh. 19 - Prob. 63ECh. 19 - Prob. 64ECh. 19 - Prob. 65ECh. 19 - Prob. 66ECh. 19 - Prob. 67ECh. 19 - A particular protein is composed of two individual...Ch. 19 - Prob. 69ECh. 19 - Prob. 70ECh. 19 - Prob. 71ECh. 19 - Prob. 72ECh. 19 - Prob. 73ECh. 19 - Prob. 74ECh. 19 - Prob. 75ECh. 19 - Prob. 76ECh. 19 - Prob. 77ECh. 19 - Prob. 78ECh. 19 - 79. Match each term with its correct meaning.
...Ch. 19 - Prob. 80ECh. 19 - The amino acid glycine has this condensed...Ch. 19 - Prob. 82ECh. 19 - Since amino acids are asymmetrical, a peptide with...Ch. 19 - Prob. 84ECh. 19 - Prob. 85ECh. 19 - Prob. 86ECh. 19 - Prob. 87ECh. 19 - Prob. 88ECh. 19 - Prob. 89ECh. 19 - 90. A solution is made by dissolving 28.65 mg of a...Ch. 19 - Prob. 91ECh. 19 - 92. Sickle-cell anemia is caused by a genetic...Ch. 19 - Prob. 93QGWCh. 19 - Prob. 94QGWCh. 19 - Discuss these questions with the group and record...
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