
BUSINESS DRIVEN TECHNOLOGY(LL)-W/ACCESS
7th Edition
ISBN: 9781260149043
Author: BALTZAN
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Question
Chapter 19, Problem 7RQ
Program Plan Intro
Outsourcing:
- An organizations arrangement to provide a service or services to another organization, that is not performed using internal resource, is called outsourcing.
- All the development phases, planning, designing, development, and maintenance may outsource for the reasons like core competencies, financial savings, and rapid growth.
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Students have asked these similar questions
Please run the following program and answer the questions.
#include
int main(void)
{
int arr[6]
=
int *pointer
pointer
*pointer
=
{10, 20, 30, 40, 50, 60};
=
&arr[0];
pointer + 2;
= 5 ;
pointer++;
*pointer
-
(*pointer) 5 ;
pointer++;
*pointer
* (pointer+1)
-
5%;
return 0;
1. [10 pts] Please list the values of elements in array arr after line 8 (*pointer
why.
=
5; ) and explain
>
Comparable
Method
- methodName: String
-priority: int
+ Method()
+ Method(methodName: String, priority: int)
+ abstract specificWay(): void
+ Getters and setters for all fields
compareTo(otherMethod: Method): int
+ toString(): String
ReadMethod
- language: String
+ ReadMethod()
+ ReadMethod(methodName: String,
priority: int, language: String)
+ specificWay(): void
+ Getters and setters for language
+ toString(): String
Part 1.1. Implement the abstract class Method implements Comparable interface according to its UML
diagram. Add comments stating where data fields, constructors, toString(), and other methods are (if
any). Neither method should have an empty body unless abstract methods.
1. two constructors (default and the constructor with all fields)
2. getters and setters for all fields (methodName and priority).
3. toString() method: modify by yourself to match the example output.
4. Abstract method void specificWay().
5. Implement compara To(Method otherMethod) to compare…
Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int ll_has_cycle (node *first)
if (first
NULL) return 0;
node *head = first%;B
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head =
head->next;B
return 0;
void test_11_has_cycle() {
int i;
node nodes [6] ;
for (i =
0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value
i;
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
&nodes [3];
nodes [3] .next
nodes [4] .next
& nodes [4];
NULL;
nodes [5] .next
&nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has %s cycle\n\n", 11_has_cycle (&nodes[0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s cycle\n\n",…
Chapter 19 Solutions
BUSINESS DRIVEN TECHNOLOGY(LL)-W/ACCESS
Ch. 19 - What are the three interdependent variables...Ch. 19 - Prob. 2OCCh. 19 - Prob. 3OCCh. 19 - Prob. 1CQCh. 19 - Prob. 2CQCh. 19 - How could more time spent in the analysis and...Ch. 19 - Prob. 4CQCh. 19 - Prob. 1RQCh. 19 - Prob. 2RQCh. 19 - Prob. 3RQ
Ch. 19 - Prob. 4RQCh. 19 - Prob. 5RQCh. 19 - Prob. 6RQCh. 19 - Prob. 7RQCh. 19 - Prob. 8RQCh. 19 - Prob. 9RQCh. 19 - Prob. 1MBDCh. 19 - Prob. 2MBDCh. 19 - Prob. 3MBDCh. 19 - Prob. 4MBDCh. 19 - Prob. 5MBDCh. 19 - Prob. 6MBDCh. 19 - Prob. 1CCOCh. 19 - Prob. 2CCOCh. 19 - Prob. 3CCOCh. 19 - Prob. 4CCOCh. 19 - Prob. 5CCOCh. 19 - Prob. 1CCTCh. 19 - Prob. 2CCTCh. 19 - Prob. 3CCTCh. 19 - Prob. 4CCTCh. 19 - Prob. 5CCTCh. 19 - Prob. 1AYKCh. 19 - Prob. 2AYKCh. 19 - Prob. 3AYKCh. 19 - Prob. 4AYKCh. 19 - Prob. 5AYKCh. 19 - Prob. 6AYKCh. 19 - Prob. 7AYK
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