Consider the reaction: H 2 ( g ) + I 2 ( g ) ⇌ 2HI ( g ) The following data show the equilibrium constant for this reaction measured at several different temperatures. Use the data to find Δ H rxn ° and Δ S rxn ° for the reaction. Temperature K p 150 K 1 .4×10 − 6 175 K 4 .6×10 − 4 200 K 3 .6×10 − 2 225 K 1.1 250 K 15.5
Consider the reaction: H 2 ( g ) + I 2 ( g ) ⇌ 2HI ( g ) The following data show the equilibrium constant for this reaction measured at several different temperatures. Use the data to find Δ H rxn ° and Δ S rxn ° for the reaction. Temperature K p 150 K 1 .4×10 − 6 175 K 4 .6×10 − 4 200 K 3 .6×10 − 2 225 K 1.1 250 K 15.5
Solution Summary: The author explains the equilibrium constant for a reaction measured at different temperatures.
The following data show the equilibrium constant for this reaction measured at several different temperatures. Use the data to find
Δ
H
rxn
°
and
Δ
S
rxn
°
for the reaction.
Part I.
a) Elucidate
the structure of compound A using the following information.
• mass spectrum: m+ = 102, m/2=57
312=29
• IR spectrum:
1002.5
% TRANSMITTANCE
Ngg
50
40
30
20
90
80
70
60
MICRONS
5
8
9 10
12
13
14 15 16
19
1740 cm
M
10
0
4000
3600
3200
2800
2400
2000
1800
1600
13
• CNMR
'H
-NMR
Peak
8
ppm (H)
Integration
multiplicity
a
1.5 (3H)
triplet
b
1.3
1.5 (3H)
triplet
C
2.3
1 (2H)
quartet
d
4.1
1 (2H)
quartet
& ppm (c)
10
15
28
60
177 (C=0)
b) Elucidate the structure of compound B using the following information
13C/DEPT NMR 150.9 MHz
IIL
1400
WAVENUMBERS (CM-1)
DEPT-90
DEPT-135
85 80 75
70
65
60
55
50
45 40
35
30 25 20
ppm
1200
1000
800
600
400
•
Part II.
a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below:
• IR spectra
% TRANSMITTANCE
1002.5
90
80
70
60
50
40
30
20
10
0
4000
3600
3200
2800
2400
2000
1800
1600
• Information from 'HAMR
MICRONS
8 9 10
11
14 15 16
19
25
1400
WAVENUMBERS (CM-1)
1200
1000
800
600
400
peak
8 ppm
Integration
multiplicity
a
2.1
1.5 (3H)
Singlet
b
3.6
1 (2H)
singlet
с
3.8
1.5 (3H)
Singlet
d
6.8
1(2H)
doublet
7.1
1(2H)
doublet
Information from 13C-nmR
Normal carbon
29ppm
Dept 135
Dept -90
+
NO peak
NO peak
50 ppm
55 ppm
+
NO peak
114 ppm
t
126 ppm
No peak
NO peak
130 ppm
t
+
159 ppm
No peak
NO peak
207 ppm
по реак
NO peak
Could you redraw these and also explain how to solve them for me pleas
Chapter 19 Solutions
Chemistry: Structures and Properties, Books a la Carte Plus MasteringChemistry with eText -- Access Card Package
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