Introductory Chemistry >IC<
8th Edition
ISBN: 9781305014534
Author: ZUMDAHL
Publisher: CENGAGE C
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Chapter 19, Problem 69AP
Interpretation Introduction
Interpretation:
The given statement should be completed.
Concept Introduction:
Periodic table consists of number of elements arranged according to their
Element consist of number of atom such as atomic number is equivalent to number of proton present in atom.
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need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Please correct answer and don't used hand raiting
need help please and thanks dont understand a-b
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal energy
Divide the…
Chapter 19 Solutions
Introductory Chemistry >IC<
Ch. 19.1 - Prob. 1CTCh. 19.1 - Prob. 19.1SCCh. 19.1 - Prob. 19.2SCCh. 19.3 - Exercise19.3Watches with numerals that glow in the...Ch. 19.8 - Prob. 1CTCh. 19 - Prob. 1ALQCh. 19 - Prob. 2ALQCh. 19 - Prob. 3ALQCh. 19 - Prob. 4ALQCh. 19 - Prob. 5ALQ
Ch. 19 - Prob. 6ALQCh. 19 - Prob. 7ALQCh. 19 - Prob. 8ALQCh. 19 - Prob. 9ALQCh. 19 - Prob. 10ALQCh. 19 - Prob. 1QAPCh. 19 - Prob. 2QAPCh. 19 - Prob. 3QAPCh. 19 - Prob. 4QAPCh. 19 - Prob. 5QAPCh. 19 - Prob. 6QAPCh. 19 - Prob. 7QAPCh. 19 - Prob. 8QAPCh. 19 - Prob. 9QAPCh. 19 - Prob. 10QAPCh. 19 - Prob. 11QAPCh. 19 - Prob. 12QAPCh. 19 - Prob. 13QAPCh. 19 - Prob. 14QAPCh. 19 - Prob. 15QAPCh. 19 - Prob. 16QAPCh. 19 - Prob. 17QAPCh. 19 - Prob. 18QAPCh. 19 - Prob. 19QAPCh. 19 - Prob. 20QAPCh. 19 - Prob. 21QAPCh. 19 - Prob. 22QAPCh. 19 - Prob. 23QAPCh. 19 - Prob. 24QAPCh. 19 - Prob. 25QAPCh. 19 - Prob. 26QAPCh. 19 - Prob. 27QAPCh. 19 - Prob. 28QAPCh. 19 - Prob. 29QAPCh. 19 - Prob. 30QAPCh. 19 - Prob. 31QAPCh. 19 - Prob. 32QAPCh. 19 - Prob. 33QAPCh. 19 - Prob. 34QAPCh. 19 - Prob. 35QAPCh. 19 - Prob. 36QAPCh. 19 - Prob. 37QAPCh. 19 - Prob. 38QAPCh. 19 - Prob. 39QAPCh. 19 - Prob. 40QAPCh. 19 - Prob. 41QAPCh. 19 - Prob. 42QAPCh. 19 - Prob. 43QAPCh. 19 - Prob. 44QAPCh. 19 - Prob. 45QAPCh. 19 - Prob. 46QAPCh. 19 - Prob. 47QAPCh. 19 - Prob. 48QAPCh. 19 - . How do the forces that hold an atomic nucleus...Ch. 19 - Prob. 50QAPCh. 19 - Prob. 51QAPCh. 19 - Prob. 52QAPCh. 19 - Prob. 53QAPCh. 19 - Prob. 54QAPCh. 19 - Prob. 55QAPCh. 19 - Prob. 56QAPCh. 19 - Prob. 57QAPCh. 19 - Prob. 58QAPCh. 19 - Prob. 59QAPCh. 19 - Prob. 60QAPCh. 19 - Prob. 61QAPCh. 19 - Prob. 62QAPCh. 19 - Prob. 63QAPCh. 19 - Prob. 64QAPCh. 19 - Prob. 65QAPCh. 19 - Prob. 66QAPCh. 19 - Prob. 67QAPCh. 19 - Prob. 68QAPCh. 19 - Prob. 69APCh. 19 - Prob. 70APCh. 19 - Prob. 71APCh. 19 - Prob. 72APCh. 19 - Prob. 73APCh. 19 - Prob. 74APCh. 19 - Prob. 75APCh. 19 - Prob. 76APCh. 19 - Prob. 77APCh. 19 - Prob. 78APCh. 19 - Prob. 79APCh. 19 - . The elements with atomic numbers of 93 or...Ch. 19 - Prob. 81APCh. 19 - Prob. 82APCh. 19 - Prob. 83APCh. 19 - Prob. 84APCh. 19 - Prob. 85APCh. 19 - Prob. 86APCh. 19 - Prob. 87APCh. 19 - Prob. 88APCh. 19 - Prob. 89APCh. 19 - Prob. 90APCh. 19 - Prob. 91APCh. 19 - Prob. 92APCh. 19 - Prob. 93APCh. 19 - Prob. 94APCh. 19 - . The element zinc in nature consists of five...Ch. 19 - . Aluminum exists in several isotopic forms,...Ch. 19 - Prob. 97APCh. 19 - Prob. 98APCh. 19 - Prob. 99APCh. 19 - Prob. 100APCh. 19 - Prob. 101APCh. 19 - Prob. 102APCh. 19 - Prob. 103APCh. 19 - Prob. 104CPCh. 19 - Prob. 105CPCh. 19 - Prob. 106CPCh. 19 - Prob. 107CP
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