Interpretation Introduction Interpretation: Amongst the given metals, the best reducing agent is to be identified. Explanation From the reduction potential table, we can predict that the metal with greater reduction potential has the greater tendency to accept the electrons than the metals that are below the corresponding metal in the table. Thus, such metal easily accepts the electrons from the metals below it in the given table. Hence, the metal is to be considered as an oxidizing agent, and the electron donor metal is to be considered as reducing agent. The reduction potential values of the given metals in their aqueous solution are as follows. Mn + 2 ( aq ) + 2e - → Mn ( s ) E cell º = - 1.18 V Al + 3 ( aq ) + 3e - → Al ( s ) E cell º = - 1

Chemistry: A Molecular Approach Plus Mastering Chemistry with Pearson eText -- Access Card Package (4th Edition) (New Chemistry Titles from Niva Tro)

4th Edition

ISBN: 9780134103976

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 19, Problem 64E

Interpretation Introduction

Interpretation: Amongst the given metals, the best reducing agent is to be identified.

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Chapter 19, Problem 63E

Chapter 19, Problem 65E

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Chemistry: A Molecular Approach Plus Mastering Chemistry with Pearson eText -- Access Card Package (4th Edition) (New Chemistry Titles from Niva Tro)

Ch. 19 - Prob. 1SAQ Ch. 19 - Q2. Which statement is true for voltaic cells? a)...Ch. 19 - Prob. 3SAQ Ch. 19 - Prob. 4SAQ Ch. 19 - Prob. 5SAQ Ch. 19 - Prob. 6SAQ Ch. 19 - Prob. 7SAQ Ch. 19 - Prob. 8SAQ Ch. 19 - Prob. 9SAQ Ch. 19 - Prob. 10SAQ

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