(a) Explanation Write the expression for molar specific heat at constant volume. C V = M c V (I) Here, C V is the molar specific heat at constant volume, c V is the specific heat constant volume, and M is the molecular mass. Write the expression for molar specific heat at constant pressure. C P = M c P (II) Here, C P is the molar specific heat at constant pressure, and c P is the specific heat constant pressure. Solve equation (II) for c P . c P = C P M (III) Write the Mayer’s relation. C P − C V = R (IV) Here, R is the universal gas constant. Solve equation (IV) for C P . C P = C V + R (V) Use equation (V) in (III). c P = C V + R M (VI) Conclusion: Substitute, 0.034 kg / mol for M , and 0.182 kcal / kg ⋅ K for c V in equation (I), to find C V C V = ( 0.034 kg / mol ) ( 0.182 kcal / kg ⋅ K ) = ( 0.034 kg / mol ) ( 0.182 kcal / kg ⋅ K ) ( 1000 cal 1 kcal ) = 6 (b) To determine Molecular structure of the gas.

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ISBN: 9780134296074

Author: GIANCOLI

Publisher: VST

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First law of Thermodynamics

The word thermodynamics consists of two words: thermo- and dynamics. Dynamics means the study of motion. The field of thermodynamics is all about the study of the movement of heat. In a more meaningful way, it is stated as the study of the transfer of en…

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Chapter 19, Problem 55P

(a)

To determine

Specific heat at constant pressure.

(b)

To determine

Molecular structure of the gas.

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Chapter 19, Problem 54P

Chapter 19, Problem 56P

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