Interpret sum of number of neutron and number of proton. Concept Introduction: The atom consist nucleus and the electron. The nucleus of an atom consist proton and neutron and the electron is revolving around the nucleus. Mass number of an atom is equal to the sum of proton and neutron. Atomic number is equal to the number of proton or in ground state it is also equal to the number of electron.

Question

Want to see the full answer?

Answer 1

Question

Chapter 19, Problem 4QAP

Interpretation Introduction

Interpretation:

Interpret sum of number of neutron and number of proton.

Concept Introduction:

The atom consist nucleus and the electron. The nucleus of an atom consist proton and neutron and the electron is revolving around the nucleus. Mass number of an atom is equal to the sum of proton and neutron. Atomic number is equal to the number of proton or in ground state it is also equal to the number of electron.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Learning Goal: This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this: 35 Cl 17 In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is: It is also correct to write symbols by leaving off the atomic number, as in the following form: atomic number mass number Symbol 35 Cl or mass number Symbol This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written. Watch this video to review the format for written symbols. In the following table each column…

need help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…