
Concept explainers
Interpretation:
In
Concept introduction:
Oxidation number is the number given to each element in a molecule or a compound that gives an idea about the number of electrons.
The oxidation number is assigned to each element by following a set of rules shown below.
• In an elemental substance, the oxidation number for every atom is zero.
• For a monoatomic ion, the oxidation number is same as the charge on the ion.
• For a combined oxygen, the oxidation number is
• For a combined hydrogen, the oxidation number is
• In a molecule, the sum of the oxidation numbers of all atoms is equal to the charge on the species.

Want to see the full answer?
Check out a sample textbook solution
Chapter 19 Solutions
Bundle: Introductory Chemistry: An Active Learning Approach, 6th + LMS Integrated for OWLv2, 4 terms (24 months) Printed Access Card
- please helparrow_forwardPredict the products of the following reactions. Draw mechanism arrows for each step for a, b, and c. a.) HBr b.) HI H₂O H2SO4 d.) C12 HO H2SO4 1.) BH3 2.) H2O2, NaOHarrow_forwardK for the following reaction is 0.11 at constant temperature. If the equilibrium concentration of HCl is 0.5 M, what is the equilibrium concentration of NH3. NH4CI(s) ⇌ NH3(g) + HCI(g)arrow_forward
- please help by Draw the following structures (Lewis or line-angle drawing).arrow_forwardplease helparrow_forwardConsider the reaction: 2 A (aq) ⇌ B(aq) Given the following KC values and starting with the initial concentration of A = 4.00 M, complete ICE diagram(s)and find the equilibrium concentrations for A and B.A) KC = 4.00B) KC = 200C) KC = 8.00 x10-3arrow_forward
- 5) Consider the reaction: Cl2 (g) + F2 (g) ⟷ 2 ClF (g) KP=? The partial pressure of 203 kPa for Cl2 and a partial pressure of 405 kPa for F2. Upon reaching equilibrium, thepartial pressure of ClF is 180 kPa. Calculate the equilibrium concentrations and then find the value for KP.arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward(9 Pts) In one of the two Rare Earth element rows of the periodic table, identify an exception tothe general ionization energy (IE) trend. For the two elements involved, answer the followingquestions. Be sure to cite sources for all physical data that you use.a. (2 pts) Identify the two elements and write their electronic configurations.b. (2 pts) Based on their configurations, propose a reason for the IE trend exception.c. (5 pts) Calculate effective nuclear charges for the last electron in each element and theAllred-Rochow electronegativity values for the two elements. Can any of these valuesexplain the IE trend exception? Explain how (not) – include a description of how IErelates to electronegativity.arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningIntroductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningLiving By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning




