Given the mass defect of L 6 i nucleus its atomic mass has to be calculated. Concept Introduction: Atomic mass of an atom is often referred to as the sum of number of protons and number of neutrons. But the actual mass of nucleus is not equivalent to the sum of number of protons and number of neutrons. The difference between these two is called mass defect which occurs due to the loss of energy during the formation of nucleus. It is represented as, Δ m = [ Z ( m p + m e ) + ( A − Z ) m n ] − m a t o m Δ m = mass defect, Z = atomic number(number of protons), A = mass number m p = mass of proton, m e = mass of electron, m n = mass of neutron m a t o m = mass of nuclide X Z A

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Answer 1

Question

Chapter 19, Problem 47E

Interpretation Introduction

Interpretation:

Given the mass defect of L6i nucleus its atomic mass has to be calculated.

Concept Introduction:

Atomic mass of an atom is often referred to as the sum of number of protons and number of neutrons. But the actual mass of nucleus is not equivalent to the sum of number of protons and number of neutrons. The difference between these two is called mass defect which occurs due to the loss of energy during the formation of nucleus. It is represented as,

Δm = [ Z(mp + me) + (A−Z)mn ] − matomΔm = mass defect, Z = atomic number(number of protons), A = mass numbermp = mass of proton, me = mass of electron, mn = mass of neutronmatom= mass of nuclide XZA

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Answer 2

Question

Chapter 19, Problem 47E

Interpretation Introduction

Interpretation:

Given the mass defect of L6i nucleus its atomic mass has to be calculated.

Concept Introduction:

Atomic mass of an atom is often referred to as the sum of number of protons and number of neutrons. But the actual mass of nucleus is not equivalent to the sum of number of protons and number of neutrons. The difference between these two is called mass defect which occurs due to the loss of energy during the formation of nucleus. It is represented as,

Δm = [ Z(mp + me) + (A−Z)mn ] − matomΔm = mass defect, Z = atomic number(number of protons), A = mass numbermp = mass of proton, me = mass of electron, mn = mass of neutronmatom= mass of nuclide XZA

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Answer 3

Question

Chapter 19, Problem 47E

Interpretation Introduction

Interpretation:

Given the mass defect of L6i nucleus its atomic mass has to be calculated.

Concept Introduction:

Atomic mass of an atom is often referred to as the sum of number of protons and number of neutrons. But the actual mass of nucleus is not equivalent to the sum of number of protons and number of neutrons. The difference between these two is called mass defect which occurs due to the loss of energy during the formation of nucleus. It is represented as,

Δm = [ Z(mp + me) + (A−Z)mn ] − matomΔm = mass defect, Z = atomic number(number of protons), A = mass numbermp = mass of proton, me = mass of electron, mn = mass of neutronmatom= mass of nuclide XZA

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Answer 4

Question

Chapter 19, Problem 47E

Interpretation Introduction

Interpretation:

Given the mass defect of L6i nucleus its atomic mass has to be calculated.

Concept Introduction:

Atomic mass of an atom is often referred to as the sum of number of protons and number of neutrons. But the actual mass of nucleus is not equivalent to the sum of number of protons and number of neutrons. The difference between these two is called mass defect which occurs due to the loss of energy during the formation of nucleus. It is represented as,

Δm = [ Z(mp + me) + (A−Z)mn ] − matomΔm = mass defect, Z = atomic number(number of protons), A = mass numbermp = mass of proton, me = mass of electron, mn = mass of neutronmatom= mass of nuclide XZA

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Answer 5

Chapter 19, Problem 47E

Interpretation Introduction

Interpretation:

Given the mass defect of L6i nucleus its atomic mass has to be calculated.

Concept Introduction:

Atomic mass of an atom is often referred to as the sum of number of protons and number of neutrons. But the actual mass of nucleus is not equivalent to the sum of number of protons and number of neutrons. The difference between these two is called mass defect which occurs due to the loss of energy during the formation of nucleus. It is represented as,

Δm = [ Z(mp + me) + (A−Z)mn ] − matomΔm = mass defect, Z = atomic number(number of protons), A = mass numbermp = mass of proton, me = mass of electron, mn = mass of neutronmatom= mass of nuclide XZA

Answer 6

Chapter 19, Problem 47E

Interpretation Introduction

Interpretation:

Given the mass defect of L6i nucleus its atomic mass has to be calculated.

Concept Introduction:

Atomic mass of an atom is often referred to as the sum of number of protons and number of neutrons. But the actual mass of nucleus is not equivalent to the sum of number of protons and number of neutrons. The difference between these two is called mass defect which occurs due to the loss of energy during the formation of nucleus. It is represented as,

Δm = [ Z(mp + me) + (A−Z)mn ] − matomΔm = mass defect, Z = atomic number(number of protons), A = mass numbermp = mass of proton, me = mass of electron, mn = mass of neutronmatom= mass of nuclide XZA

Answer 7

Chapter 19, Problem 47E

Interpretation Introduction

Interpretation:

Given the mass defect of L6i nucleus its atomic mass has to be calculated.

Concept Introduction:

Atomic mass of an atom is often referred to as the sum of number of protons and number of neutrons. But the actual mass of nucleus is not equivalent to the sum of number of protons and number of neutrons. The difference between these two is called mass defect which occurs due to the loss of energy during the formation of nucleus. It is represented as,

Δm = [ Z(mp + me) + (A−Z)mn ] − matomΔm = mass defect, Z = atomic number(number of protons), A = mass numbermp = mass of proton, me = mass of electron, mn = mass of neutronmatom= mass of nuclide XZA

Answer 8

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Answer 11

Ch. 19 - Prob. 1RQ Ch. 19 - Prob. 2RQ Ch. 19 - Prob. 3RQ Ch. 19 - Prob. 4RQ Ch. 19 - Prob. 5RQ Ch. 19 - Prob. 6RQ Ch. 19 - Prob. 7RQ Ch. 19 - Prob. 8RQ Ch. 19 - Prob. 9RQ Ch. 19 - Prob. 10RQ

Solution Summary: The author explains that the atomic mass of 6Li is calculated due to the loss of energy during the formation of nucleus.

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Chapter 19 Solutions