(a)
Interpretation:
The target molecule should be drawn for the given statements by using its molecular structure.
Concept introduction:
The structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the hetero atoms are drawn as line segments. For acyclic, linear carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of
For
For example alkane molecule, suffix will be ‘ane’, compound presence of carbonyl group ‘one’ and presence of alcohol group suffix will be ‘ol’
Root word represents the longest continuous carbon skeleton of the organic molecule.
Two stereoisomers are there for an saturated alkane molecule. It depends upon the location of bulky group (or high molecular weight) on the triple bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.
To identify: The systematic structure for the given molecule
(a)

Explanation of Solution
The given molecule is drawn. The parent indicates three carbon atoms, and suffix ‘
Further the parent chain numbered so that the two carbonyl groups is assigned the lowest possible locate (1 indicates that the keto groups is located between C1 and C2). Hence the systematic structure for the molecule (a) is Propanediol.
(b)
Interpretation:
The target molecule should be drawn for the given statements by using its molecular structure.
Concept introduction:
The structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the hetero atoms are drawn as line segments. For acyclic, linear carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
IUPAC Nomenclature Method
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkane, alkene, alkyne, alcohol, aldehyde, carboxylic acid etc...
For alkynes molecules, suffix will be ‘yne’.
For example alkane molecule, suffix will be ‘ane’, compound presence of carbonyl group ‘one’ and presence of alcohol group suffix will be ‘ol’
Root word represents the longest continuous carbon skeleton of the organic molecule.
Two stereoisomers are there for an saturated alkane molecule. It depends upon the location of bulky group (or high molecular weight) on the triple bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.
To identify: The systematic structure for the given molecule
(b)

Explanation of Solution
The given molecule is drawn. In molecule (b) parent (butanol) indicates four carbon atoms and the suffix ‘al’ and indicates an on aldehyde group at C1 position. Another one phenyl substituent is located at C4 position. The systematic structure for the molecule (b) is 4-phenyl butanal.
(c)
Interpretation:
The target molecule should be drawn for the given statements by using its molecular structure.
Concept introduction:
The structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the hetero atoms are drawn as line segments. For acyclic, linear carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
IUPAC Nomenclature Method
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkane, alkene, alkyne, alcohol, aldehyde, carboxylic acid etc...
For alkynes molecules, suffix will be ‘yne’.
For example alkane molecule, suffix will be ‘ane’, compound presence of carbonyl group ‘one’ and presence of alcohol group suffix will be ‘ol’
Root word represents the longest continuous carbon skeleton of the organic molecule.
Two stereoisomers are there for an saturated alkane molecule. It depends upon the location of bulky group (or high molecular weight) on the triple bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.
To identify: The systematic structure for the given molecule
(c)

Explanation of Solution
The stereo chemical structure for given molecule is drawn as shown above. The parent (butanol) indicates a chain of four carbon atoms, and suffix ‘al’ indicates an aldehyde group at C1 position. In molecule presence of one phenyl substituent is located at C3, which is a chirality center with the (S) configuration. The corresponding molecule (c) is (S)-3-phenyl butanal.
(d)
Interpretation:
The target molecule should be drawn for the given statements by using its molecular structure.
Concept introduction:
The structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the hetero atoms are drawn as line segments. For acyclic, linear carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
IUPAC Nomenclature Method
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkane, alkene, alkyne, alcohol, aldehyde, carboxylic acid etc...
For alkynes molecules, suffix will be ‘yne’.
For example alkane molecule, suffix will be ‘ane’, compound presence of carbonyl group ‘one’ and presence of alcohol group suffix will be ‘ol’
Root word represents the longest continuous carbon skeleton of the organic molecule.
Two stereoisomers are there for an saturated alkane molecule. It depends upon the location of bulky group (or high molecular weight) on the triple bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.
To identify: The systematic structure for the given molecule
(d)

Explanation of Solution
The systematic structure of given molecule (d) has drawn as shown above. In the given molecule the parent carbon skeleton the chain which contains 7 carbons with one carbonyl group. Hence the root name of the molecule is ‘Heptanone’ and the suffix ‘one’ indicates a ketone.
Further the carbonyl is located at C4 position and four methyl groups are present at C3 and C5 position is 3,3,5,5-Tetramethyl-4-heptanone. So the systematic name for the molecule (d) is 3,3,5,5-Tetramethyl-4-heptanone.
(e)
Interpretation:
The target molecule should be drawn for the given statements by using its molecular structure.
Concept introduction:
The structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the hetero atoms are drawn as line segments. For acyclic, linear carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
IUPAC Nomenclature Method
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkane, alkene, alkyne, alcohol, aldehyde, carboxylic acid etc...
For alkynes molecules, suffix will be ‘yne’.
For example alkane molecule, suffix will be ‘ane’, compound presence of carbonyl group ‘one’ and presence of alcohol group suffix will be ‘ol’
Root word represents the longest continuous carbon skeleton of the organic molecule.
Two stereoisomers are there for an saturated alkane molecule. It depends upon the location of bulky group (or high molecular weight) on the triple bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.
To identify: The systematic structure for the given molecule
(e)

Explanation of Solution
The stereo chemical structure of given molecule drawn. In the parent carbon skeleton in the chain which contains five carbons with one hydroxyl, one keto group. Hence the name of the molecule is ‘Pentanal’ and the suffix ‘al’ indicates an one aldehyde group. Then the molecule one carbonyl group located at C1 place and one hydroxyl group is present at C3, which is a chirality center with the R configuration.
Hence the systematic structure for the given molecule (e) is a (R)-hydroxy pentanol.
(f)
Interpretation:
The target molecule should be drawn for the given statements by using its molecular structure.
Concept introduction:
The structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the hetero atoms are drawn as line segments. For acyclic, linear carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
IUPAC Nomenclature Method
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkane, alkene, alkyne, alcohol, aldehyde, carboxylic acid etc...
For alkynes molecules, suffix will be ‘yne’.
For example alkane molecule, suffix will be ‘ane’, compound presence of carbonyl group ‘one’ and presence of alcohol group suffix will be ‘ol’
Root word represents the longest continuous carbon skeleton of the organic molecule.
Two stereoisomers are there for an saturated alkane molecule. It depends upon the location of bulky group (or high molecular weight) on the triple bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.
To identify: The systematic structure for the given molecule
(f)

Explanation of Solution
The systematic structure of given molecule drawn. The parent is acetophenone, and there is an one hydroxyl group (OH) in the meta position at C3 place of the ring.
The systematic structure for the given molecule (f) is a Meta-Hydroxy acetophenone.
(g)
Interpretation:
The target molecule should be drawn for the given statements by using its molecular structure.
Concept introduction:
The structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the hetero atoms are drawn as line segments. For acyclic, linear carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
IUPAC Nomenclature Method
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkane, alkene, alkyne, alcohol, aldehyde, carboxylic acid etc...
For alkynes molecules, suffix will be ‘yne’.
For example alkane molecule, suffix will be ‘ane’, compound presence of carbonyl group ‘one’ and presence of alcohol group suffix will be ‘ol’
Root word represents the longest continuous carbon skeleton of the organic molecule.
Two stereoisomers are there for an saturated alkane molecule. It depends upon the location of bulky group (or high molecular weight) on the triple bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.
To identify: The systematic structure for the given molecule
(g)

Explanation of Solution
The given parent phenyl group as a benzaldehyde and there are three nitro groups located at C2, C4 and C6 place. The given structure is 2,4,6-Trinitrobenzaldehyde.
(h)
Interpretation:
The target molecule should be drawn for the given statements by using its molecular structure.
Concept introduction:
The structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the hetero atoms are drawn as line segments. For acyclic, linear carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
IUPAC Nomenclature Method
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkane, alkene, alkyne, alcohol, aldehyde, carboxylic acid etc...
For alkynes molecules, suffix will be ‘yne’.
For example alkane molecule, suffix will be ‘ane’, compound presence of carbonyl group ‘one’ and presence of alcohol group suffix will be ‘ol’
Root word represents the longest continuous carbon skeleton of the organic molecule.
Two stereoisomers are there for an saturated alkane molecule. It depends upon the location of bulky group (or high molecular weight) on the triple bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.
To identify: The systematic structure for the given molecule
(h)

Explanation of Solution
The systematic structure of given molecule drawn. In the parent carbon skeleton in the chain which contains two carbon atoms with three bromo groups. Hence the name of the molecules is ‘Ethanal’ and the suffix ‘al’ indicates a one alcohol group. Further the molecule has one aldehyde group located at C1 place and three bromine atoms present in C2 position.
Hence the systematic structure for the given molecule (h) is a Tribromo acetaldehyde.
(i)
Interpretation:
The target molecule should be drawn for the given statements by using its molecular structure.
Concept introduction:
The structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, rather the bonds in between carbon atoms and to the hetero atoms are drawn as line segments. For acyclic, linear carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a line segment and label the heteroatom at the end of their line segment.
IUPAC Nomenclature Method
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkane, alkene, alkyne, alcohol, aldehyde, carboxylic acid etc...
For alkynes molecules, suffix will be ‘yne’.
For example alkane molecule, suffix will be ‘ane’, compound presence of carbonyl group ‘one’ and presence of alcohol group suffix will be ‘ol’
Root word represents the longest continuous carbon skeleton of the organic molecule.
Two stereoisomers are there for an saturated alkane molecule. It depends upon the location of bulky group (or high molecular weight) on the triple bonded carbon atoms. If the bulky groups are in same side then it is cis-isomer. If the bulky groups are in opposite side then it is trans-isomer.
To identify: The systematic structure for the given molecule
(i)

Explanation of Solution
The simple stereo chemical structure of given molecule drawn. The given parent indicates five carbon atoms with one keto group and two hydroxyl groups, hence the name of the molecule is ‘Pentanone’ (it is a general name) and suffix ‘one’ indicates a one keto group. Further this molecule carbonyl group located at C2 position and two hydroxyl group located at C3 and C4 position, both of which are chirality with the (R) configuration.
The systematic structure and name of the compound as showed above.
Finally the systematic structure for the given molecule (i) is a (3 4R)-3,4-dihydroxy-2-pentanone.
Want to see more full solutions like this?
Chapter 19 Solutions
EBK ORGANIC CHEMISTRY-PRINT COMPANION (
- Synthesis of 1-metilbenzotriazole.arrow_forwardIndicate the formula of the compound, that is the result of the N- alquilación (nucleofílic substitution), in which an additional lateral chain was formed (NH-CH2-COOMe). F3C. CF3 NH NH2 Br о OMe K2CO3, DABCO, DMFarrow_forwardIdentify the mechanism through which the following reaction will proceed and draw the major product. Part 1 of 2 Br KOH EtOH Through which mechanism will the reaction proceed? Select the single best answer. E1 E2 neither Part: 1/2 Part 2 of 2 Draw the major product formed as a result of the reaction. Click and drag to start drawing a structure. Xarrow_forward
- What is single-point calibration? Provide an example.arrow_forwardDraw the major product formed via an E1 pathway.arrow_forwardPart 9 of 9 Consider the products for the reaction. Identify the major and minor products. HO Cl The E stereoisomer is the major product and the Z stereoisomer is the minor product ▼ S major product minor productarrow_forward
- Consider the reactants below. Answer the following questions about the reaction mechanism and products. HO Clarrow_forwardjulietteyep@gmail.com X YSCU Grades for Juliette L Turner: Orc X 199 A ALEKS - Juliette Turner - Modul X A ALEKS - Juliette Turner - Modul x G butane newman projection - Gox + www-awa.aleks.com/alekscgi/x/Isl.exe/10_u-IgNslkr7j8P3jH-IBxzaplnN4HsoQggFsejpgqKoyrQrB2dKVAN-BcZvcye0LYa6eXZ8d4vVr8Nc1GZqko5mtw-d1MkNcNzzwZsLf2Tu9_V817y?10Bw7QYjlb il Scribbr citation APA SCU email Student Portal | Main Ryker-Learning WCU-PHARM D MySCU YSCU Canvas- SCU Module 4: Homework (Ch 9-10) Question 28 of 30 (1 point) | Question Attempt: 1 of Unlimited H₂SO heat OH The mechanism of this reaction involves two carbocation intermediates, A and B. Part 1 of 2 KHSO 4 rearrangement A heat B H₂O 2 OH Draw the structure of A. Check Search #t m Save For Later Juliet Submit Assignm 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessarrow_forwardThe electrons flow from the electron-rich atoms of the nucleophile to the electrons poor atoms of the alkyl halide. Identify the electron rich in the nucleophile. Enter the element symbol only, do not include any changes.arrow_forward
- Hello, I am doing a court case analysis in my Analytical Chemistry course. The case is about a dog napping and my role is prosecution of the defendant. I am tasked in the Area of Expertise in Neutron Activation and Isotopic Analysis. Attached is the following case study reading of my area of expertise! The landscaping stone was not particularly distinctive in its decoration but matched both the color and pattern of the Fluential’s landscaping stone as well as the stone in the back of the recovered vehicle. Further analysis of the stone was done using a technique called instrumental neutron activation analysis. (Proceed to Neutron Activation data) Photo Notes: Landscaping stone recovered in vehicle. Stone at Fluential’s home is similar inappearance. Finally, the white paint on the brick was analyzed using stable isotope analysis. The brick recovered at the scene had smeared white paint on it. A couple of pieces of brick in the back of the car had white paint on them. They…arrow_forwardCite the stability criteria of an enamine..arrow_forwardCalculate the pH of a 0.01m solution of acetic acid use pka of 4.75arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





