Genetics: From Genes To Genomes (6th International Edition)
6th Edition
ISBN: 9781260041217
Author: Leland Hartwell Dr., ? Michael L. Goldberg Professor Dr., ? Janice Fischer, ? Leroy Hood Dr.
Publisher: Mcgraw-Hill
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 19, Problem 32P
In flies developing from eggs laid by a nanos-mother, development of the abdomen is inhibited. Flies developing from eggs that have no maternally supplied hunchback mRNA are normal. Flies developing frog eggs laid by a nanos-mother that also have no maternally supplied hunchback mRNA are normal. If too much Hunchback protein accumulates in the posterior of the egg, abdominal development is prevented.
| a. | What do these findings say about the function of the Nanos protein and of the hunchback maternally supplied mRNA? |
| b. | What do these findings say about the efficiency of biological processes that are subject to evolution? |
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
There are many differences between DNA replication happening during mitosis in a Douglas fir tree
growing in the Oregon Cascade Mountains and DNA replication happening during a PCR reaction in a
forestry research lab at Oregon State University where the laboratory is amplifying a Simple Sequence
Repeat. Complete the following table that compares the two DNA replication events in terms of the
primers, the nucleotides, the polymerase, and the target sequence. Additionally, give a general value
for the number of copies of the template DNA after one S phase in one cell and after the lab has
completed the PCR reaction.
Tree
SSR
Type your answer here:
Primers Nucleotides Polymerase Target sequence Number of copies
Describe how insulin binding to its receptor induces glucose uptake in healthy individuals. Please specifyeach step in the cascade and use a diagram to illustrate the answer.
There is a patient with breast cancer, after staining the breast tissue with H&E, state the molecular subtype of the tumour extracted.
Results of H&E staining are down below
Chapter 19 Solutions
Genetics: From Genes To Genomes (6th International Edition)
Ch. 19 - Match each of the terms in the left column to the...Ch. 19 - a. If you were interested in the role of a...Ch. 19 - Early C. elegans embryos display mosaic...Ch. 19 - Hypomorphic mutations in the wingless gene of...Ch. 19 - Prob. 5PCh. 19 - In 1932, H. J. Muller suggested a genetic test to...Ch. 19 - a. Explain how you could use worms transformed...Ch. 19 - Suppose you want to determine whether a particular...Ch. 19 - Sevenless is an unusual receptor protein in that...Ch. 19 - Suppose that you generated flies containing a...
Ch. 19 - Drosophila researchers have collected many strains...Ch. 19 - As an alternative to random mutagenesis,...Ch. 19 - A C. elegans nematode gene called par-1 helps to...Ch. 19 - The molecular identity of the fruit fly rugose...Ch. 19 - To determine the focus of action of boss,...Ch. 19 - Suppose a particular gene is required for early...Ch. 19 - Researchers have exploited Minute mutations in...Ch. 19 - Some ts alleles are temperature sensitive during...Ch. 19 - The following figure shows the temperature-shift...Ch. 19 - A temperature-sensitive allele of the gene...Ch. 19 - Hypomorphic alleles of a pleiotropic gene...Ch. 19 - In addition to the maternal effect genes that...Ch. 19 - The yan gene encodes a transcription factor that...Ch. 19 - Recall from Chapter 17 that in Drosophila, sex...Ch. 19 - a. Explain the difference between maternal...Ch. 19 - In the 1920s, Arthur Boycott, working with the...Ch. 19 - The Drosophila mutant screen shown on the...Ch. 19 - Some genes are required both zygotically and...Ch. 19 - How would a human with a mutation in a maternal...Ch. 19 - One important demonstration that Bicoid is an...Ch. 19 - The hunchback gene contains a 5 transcriptional...Ch. 19 - In flies developing from eggs laid by a...Ch. 19 - Wild-type embryos and mutant embryos lacking the...Ch. 19 - The Drosophila even-skipped eve gene has four...Ch. 19 - In Drosophila with loss-of-function mutations...Ch. 19 - It is crucial to the development of Drosophila...Ch. 19 - In the plant Arabidopsis thaliana, every flower is...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Biopharmaceutics and Pharmacokinetics:Two-Compartment Model Instant Absorption Questions Calculate these : a) B1, b) B2, c) hybrid rate constant (1) d) hybrid rate constant (2) e) t1/2,dist f) t1/2,elim g) k10 h) k12 i) k21 j) initial concentration (C0) k) central compartment volume (V1) l) steady-state volume (Vss) m) clearance (CL) AUC (0→10 min) using trapezoidal rule n) AUC (20→30 min) using trapezoidal rule o) AUCtail (AUC360→∞) p) total AUC (using short cut method) q) volume from AUC (VAUC)arrow_forwardUse the Henderson-Hasselbalch equation for a propanoic acid solution (CH₂CH₂CO₂H, pK₁ = 4.874) to calculate the quotient [A-]/[HA] at three different pH values. pH = 4.479 [A-] [HA] [A-] pH = 4.874 [HA] = pH = 5.220 [A-] = [HA]arrow_forwardIn order to establish the expiration date of perishable food, growth curve data must be collected. Once the microbial load is so high that it poses a hazard to human health, the food item is no longer considered safe (expired). Generally a load of x50,000 bacteria/gram is considered unsafe. Your task is to determine the microbial growth curves for MicroYo, a new brand of yogurt. The growth is determined by sampling the yogurt and growing the bacterial isolates in broth culture which is then serially diluted by a total of x10,000 and inoculated onto standard petri plates of nutrient agar. The following colony counts are measured: Time (days) MicroYo colony count# 1 1 4 1 12 2 16 20 4 7 What day should you recommend expiring the yogurt (the last possible date before the microbial load is unsafe). 12 4 20 16arrow_forward
- 9. Chicken combs in chickens is an example where you see interactions between genes. See potential genotypes and phenotypes below. Which genotype, when mated to a rose comb chicken, will produce progeny that are 50% walnut comb and 50% pea comb? walnut (RRPP) walnut (RrPP) pea (rrPP) walnut (RRPP) walnut (RrPp) pea (rrPp) rose rose single (RRPP) (Rrpp) (rrpp)arrow_forwardDescribe a compound light microscope and its importance in microbiology (2) examples of at least two microbes viewed under a compound light microscope and their general characteristics (note: the microbes you choose do not need to be the ones outlined in the above tutorial video) and (3) at least one source you used for the information included in your infographic.arrow_forwardPrice of visit Number of visits $700 0 $600 [1 $500 2 $400 3 $300 4 00000 The Table blow gives the demand curve for doctor visits for Elena. If the price of a doctor's visit is $600, and Elena does not have health insurance, she will visit the doctor times. If Elena obtains 50% coinsurance (the company pays 50% of the medical bill, Elena pays 50%), then Elena will visit the doctor times. 1; 2 0; 3 0; 2 1;4 2; 1arrow_forward
- P 200 150- 100 50 w/instrance/ w/insurance 2 100 Demand Assume that the white curve (labeled "Demand") represents an individual's true demand for this particular health care service. The coinsurance associated with insurance option 1 (in blue) is likely _. 0000 100% 25% 50% 0%arrow_forwardUse the figure below. Bob and Nancy have the same income and total utility.. willingness to pay for an insurance premium will be lower than because they are. risk- averse. Total utility Current utility Bob's utility Nancy's utility 0000 Bob; Nancy; less Nancy; Bob; less Nancy; Bob; more Bob; Nancy; more Current Income incomearrow_forwardConsider the figure below. Suppose the true price of a health care service is P1. Suppose further that the individual has obtained insurance that has a fixed copayment for this particular service. The copayment is represented by price P2. represents the quantity of the service the individual would consume without insurance. quantity of the service the individual would consume with the insurance. Health Care Service represents the P. P₂ a Q1;Q2 Q2; Q3 Q1; Q3 Q3; Q1 Q2; Q1 फ f Q ८ g d h Q3\D 7Q 00000arrow_forward
- The table shows the utility Jordan receives at various income levels, but they do not know what their income will be next year. There is a 15% chance their income will be $25,000, a 20% chance their income will be $35,000, and a 65% chance their income will be $45,000. We know that Jordan is Income $25,000 Utility 2,800 30,000 3,200 35,000 3,500 40,000 3,700 45,000 3,800 ☐ none of the above 0 000 risk taker (lover) because their marginal utility of income is increasing risk neutral because their marginal utility of income is constant risk averse because their marginal utility of income is decreasing risk neutral because their marginal utility of income is decreasingarrow_forwardOOOO a d+e d a+b+c Consider the figure below. Suppose the true price of a health care service is P1. Suppose further that the individual has obtained insurance that has a fixed copayment for this particular service. The copayment is represented by price P2. The social loss from moral hazard if the individual has copayment P2 is represented graphically by the area(s): Health Care Service P. a No 4 ८ e g Q2 Q3 Darrow_forwardOOO O The table shows the utility Jordan receives at various income levels, but they do not know what their income will be next year. There is a 15% chance their income will be $25,000, a 20% chance their income will be $35,000, and a 65% chance their income will be $45,000. We know that Jordan's expected income is. Their utility from their expected income is_ Income $25,000 Utility 2,800 30,000 3,200 35,000 3,500 40,000 3,700 45,000 3,800 $45,000; 3,800 $40,000; 3,700 $25,000; 2,800 $35,000; 3,500 $30,000; 3,200arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Biology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage Learning
Biology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStax
Biology Today and Tomorrow without Physiology (Mi...BiologyISBN:9781305117396Author:Cecie Starr, Christine Evers, Lisa StarrPublisher:Cengage Learning
Concepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax College
Biology: The Dynamic Science (MindTap Course List)
Biology
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Biology (MindTap Course List)
Biology
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Cengage Learning
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Biology Today and Tomorrow without Physiology (Mi...
Biology
ISBN:9781305117396
Author:Cecie Starr, Christine Evers, Lisa Starr
Publisher:Cengage Learning
Concepts of Biology
Biology
ISBN:9781938168116
Author:Samantha Fowler, Rebecca Roush, James Wise
Publisher:OpenStax College
Embryology | Fertilization, Cleavage, Blastulation; Author: Ninja Nerd;https://www.youtube.com/watch?v=8-KF0rnhKTU;License: Standard YouTube License, CC-BY