Chapter 19, Problem 28QAP

Interpretation Introduction

(a)

Interpretation:

To write the balanced equation of beta decay of the given nuclide ¹³⁶ _{5 3} I.

Concept Introduction:

The radioactive decay is the decay of the alpha, beta emission etc. The decay of these type of particles produces the stable nucleus. The nuclear transformation is the chain reaction.

Chain reaction means the reaction proceed in continuity till it will form the stable nucleus.

Beta decay is the decay in which atomic number increases by 1 and no change in the mass number.

Interpretation Introduction

(b)

Interpretation:

To write the balanced equation of beta decay of the given nuclide ¹³³ _{5 1} Sb.

Concept Introduction:

The radioactive decay is the decay of the alpha, beta emission etc. The decay of these type of particles produces the stable nucleus. The nuclear transformation is the chain reaction.

Chain reaction means the reaction proceed in continuity till it will form the stable nucleus.

Beta decay is the decay in which atomic number increases by 1 and no change in the mass number.

Interpretation Introduction

(c)

Interpretation:

To write the balanced equation of beta decay of the given nuclide ¹¹⁷ _{4 9} In.

Concept Introduction:

The radioactive decay is the decay of the alpha, beta emission etc. The decay of these type of particles produces the stable nucleus. The nuclear transformation is the chain reaction.

Chain reaction means the reaction proceed in continuity till it will form the stable nucleus.

Beta decay is the decay in which atomic number increases by 1 and no change in the mass number.