Chapter 19, Problem 25A

A 4.7-kg piece of metal displaces 0.6 liter of water when submerged. Calculate its density.

To determine

Density of metal.

Answer to Problem 25A

Density $\rho =7833.33{\text{kg/m}}^3$ .

Explanation of Solution

Given:

Mass of metal, $m=4.7\text{kg}$

Volume of water displaced, $V=0.6\text{liter}$

Formula Used:

Density is given as,

  $\rho =\frac{m}{V}$

Where, $\rho$ is density, $m$ is mass and $V$ is volume.

Calculation:

As, $1{\text{m}}^3=1000\text{liter}$

So, $0.6\text{liter}=0.6\times {10}^{-3}{\text{m}}^3$

Now, the density of metal is

  $\begin{array}{l}\rho =\frac{m}{V}=\frac{4.7}{0.6\times {10}^{-3}}{\text{kg/m}}^3\\ \Rightarrow \rho =7833.33{\text{kg/m}}^3\end{array}$

Conclusion:

Therefore, the density of metal is $\rho =7833.33{\text{kg/m}}^3$ .