SaplingPlus for Lehninger Principles of Biochemistry (Six-Month Access)
7th Edition
ISBN: 9781319108236
Author: David L. Nelson, Michael M. Cox
Publisher: W. H. Freeman
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Question
Chapter 19, Problem 23P
Summary Introduction
To explain: The difference between milder and severe form of disease caused by presence of one and two defective copies of glucokinase gene respectively.
Introduction:
One isozyme of hexokinase is glucokinase. Glucokinase is an enzyme which catalyzes phosphorylation of glucose. Phosphorylation of glucose is the first reaction in glycolysis. Glucokinase is present in pancreas and liver. When glucose is present in high amounts in the cell, it converts it into glucose-6-phosphate, which enters glycolysis.
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Balance the following equation and list of coefficients in order from left to right. SF4+H2O+—-> H2SO3+HF
Problem 15 of 15
Submit
Using the following reaction data
points, construct Lineweaver-Burk
plots for an enzyme with and without
an inhibitor by dragging the points to
their relevant coordinates on the
graph and drawing a line of best fit.
Using the information from this plot,
determine the type of inhibitor
present.
1
mM-1
1
s mM
-1
[S]'
V'
with 10 μg per
20
54
10
36
20
5
27
2.5
23
1.25
20
Answer:
|||
12:33
CO
Problem 4 of 15
4G 54%
Done
On the following Lineweaver-Burk
-1
plot, identify the by dragging the
Km
point to the appropriate value.
1/V
40
35-
30-
25
20
15
10-
T
Км
-15
10
-5
0
5
|||
10
15
№20
25
25
30
1/[S]
Г
powered by
desmos
Chapter 19 Solutions
SaplingPlus for Lehninger Principles of Biochemistry (Six-Month Access)
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- 1:30 5G 47% Problem 10 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a competitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' s mM¹ with 10 mg pe 20 V' 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forwardProblem 14 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:36 CO Problem 9 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of the catalytic efficiency (specificity constant) given that the enzyme concentration in this experiment is 5.0 μ.Μ. 1 [S] ¨‚ μM-1 1 V sμM-1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| O Гarrow_forward
- Problem 11 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a noncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forwardProblem 13 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 8 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of kcat given that the enzyme concentration in this experiment is 5.0 μM. 1 [S] , мм -1 1 V₁ s μM 1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward
- 1:33 5G. 46% Problem 12 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without an uncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 7 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of Vmax. Report your answer to three significant figures. 1 , mM-1 1 [S] V' sμM-¹ 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward12:33 CO Problem 5 of 15 4G 54% Done On the following Lineweaver-Burk 1 plot, identify the by dragging the Vmax point to the appropriate value on the line. NI 35 30- 25 20- 15- 10 5. 1 Vmax -15 10 -5 0 5 10 15 20 20 ||| で Г 25 30 1/[S]arrow_forward
- 12:20 V 0.1- 0:09. 0.08 0:07 0.06 -0.05- 0:04- -0.03- -0.02- 4G 56% Problem 1 of 15 Done On the following Michaelis-Menten plot, estimate the value of - Vmax by 1 2 dragging the line to the appropriate value on the y-axis. 0.01 V max 0 0.5 ||| 1.5 2.5 3.5 4 ISLarrow_forward12:33 CO 4G 54% Problem 6 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the Km. 1 mM-1 1 [S]' " s mM-1 V 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forwardV 0.1- 0:09 0:08 0:07- -0.06 -0.05 0:04- 0:03 0:02 0:01- Problem 2 of 15 Done On the following Michaelis-Menten plot, estimate the value of Kм by dragging the point to the appropriate value on the x-axis. I T | 0 0.5 1.5 2 KM -0:01- ||| 25 2.5 3 3.5 4 Г [S] powered by desmosarrow_forward
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