EBK PHYSICS FOR SCIENTISTS AND ENGINEER
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
1st Edition
ISBN: 9780100546714
Author: Katz
Publisher: YUZU
Question
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Chapter 19, Problem 1PQ

(a)

To determine

Convert temperature from Fahrenheit to Celsius and Kelvin.

(a)

Expert Solution
Check Mark

Answer to Problem 1PQ

The temperature in Celsius is 24°C_ and the temperature in Kelvin is 297K_.

Explanation of Solution

Write the equation of temperature in centigrade scale.

  T(°C)=59[T(°F)32]                                                                                    (I)

Here, T(°C) is the temperature in Celsius scale and T(°F) is the temperature in Fahrenheit scale.

Write the expression for the temperature in Kelvin scale.

  T(K)=T(°C)+273.15                                                                                   (II)

Here, T(°K) is the temperature in Kelvin scale.

Conclusion:

Substitute 76°F for T(°F) in equation (I) to find T(°C).

  T(°C)=59[(76°F)32]=59(44)=24°C

Thus, The temperature in Celsius is 24°C_.

Substitute 24°C for T(°C) in equation (II) to find T(°K).

  T(K)=(24°C)+273.15=297K

Thus, the temperature in Kelvin is 297K_.

(b)

To determine

Convert temperature from Fahrenheit to Celsius and Kelvin.

(b)

Expert Solution
Check Mark

Answer to Problem 1PQ

For 180°F.

The temperature in Celsius is 82°C_ and the temperature in Kelvin is 355K_.

For 190°F.

The temperature in Celsius is 88°C_ and the temperature in Kelvin is 361K_.

Explanation of Solution

Write the equation of temperature in centigrade scale.

  T(°C)=59[T(°F)32]                                                                                    (I)

Here, T(°C) is the temperature in Celsius scale and T(°F) is the temperature in Fahrenheit scale.

Write the expression for the temperature in Kelvin scale.

  T(K)=T(°C)+273.15                                                                                   (II)

Here, T(°K) is the temperature in Kelvin scale.

Conclusion:

Substitute 180°F for T(°F) in equation (I) to find T(°C).

  T(°C)=59[(180°F)32]=59(148)=82°C

Substitute 82°C for T(°C) in equation (II) to find T(°K).

  T(K)=(82°C)+273.15=355K

Thus, for 180°F.

The temperature in Celsius is 82°C_ and the temperature in Kelvin is 355K_.

Substitute 190°F for T(°F) in equation (I) to find T(°C).

  T(°C)=59[(190°F)32]=59(158)=88°C

Substitute 88°C for T(°C) in equation (II) to find T(°K).

  T(K)=(88°C)+273.15=361K

Thus, for 190°F.

The temperature in Celsius is 88°C_ and the temperature in Kelvin is 361K_.

(c)

To determine

Convert temperature from Fahrenheit to Celsius and Kelvin.

(c)

Expert Solution
Check Mark

Answer to Problem 1PQ

The temperature in Celsius is -89°C_ and the temperature in Kelvin is 184K_.

Explanation of Solution

Write the equation of temperature in centigrade scale.

  T(°C)=59[T(°F)32]                                                                                    (I)

Here, T(°C) is the temperature in Celsius scale and T(°F) is the temperature in Fahrenheit scale.

Write the expression for the temperature in Kelvin scale.

  T(K)=T(°C)+273.15                                                                                  (II)

Here, T(°K) is the temperature in Kelvin scale.

Conclusion:

Substitute -129°F for T(°F) in equation (I) to find T(°C).

  T(°C)=59[(-129°F)32]=59(161)=89°C

Thus, the temperature in Celsius is -89°C_.

Substitute 89°C for T(°C) in equation (II) to find T(°K).

  T(K)=(89°C)+273.15=184K

Thus, the temperature in Kelvin is 184K_.

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Chapter 19 Solutions

EBK PHYSICS FOR SCIENTISTS AND ENGINEER

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