Physics for Scientists and Engineers with Modern Physics
Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
bartleby

Concept explainers

Question
Book Icon
Chapter 19, Problem 1P

(a)

To determine

The energy equivalent in joules for one jelly doughnut.

(a)

Expert Solution
Check Mark

Answer to Problem 1P

The energy equivalent in joules for one jelly doughnutis 2.26×106J .

Explanation of Solution

Given information:

Mass of the woman is 55.0kg and energy in one doughnut is 540Calorie(540kcal) .

The conversion of kcal into joules is,

1kcal=4.186×103J

Therefore, the conversion of 540kcal into joules is,

540kcal=540kcal×4.186×103J1kcal=2.26×106J

Conclusion:

Therefore, the energy equivalent in joules for one jelly doughnut is 2.26×106J .

(b)

To determine

The number of steps woman must climb to change the required potential energy.

(b)

Expert Solution
Check Mark

Answer to Problem 1P

The number of steps woman must climb to change the required potential energy is 2.8×104steps .

Explanation of Solution

Given information:

Mass of the woman is 55.0kg and energy in one doughnut is 540Calorie(540kcal) . The height of a single stair is 15.0cm .

Formula to calculate the change in potential energy to climb one step is,

ΔU=mgh

  • h is the height of one step.
  • U is the gravitational potential energy.
  • m is the mass of the woman.
  • g is the acceleration due to gravity.

Formula to calculate the total change in potential energy is,

ΔUtotal=nmgh

  • n is the number of steps.

Rearrange the above equation for n .

n=ΔUtotalmgh

Substitute 2.26×106J for ΔUtotal , 55.0kg for m , 9.8m/s2 for g and 15.0cm for h to find n .

n=2.26×106J55.0kg×9.8m/s2×(15.0cm×102m1cm)=2.8×104steps

Conclusion:

Therefore, the number of steps woman must climb to change the required potential energy is 2.8×104steps .

(c)

To determine

The number of steps woman must climb to work off her breakfast.

(c)

Expert Solution
Check Mark

Answer to Problem 1P

The number of steps woman must climb to work off her breakfast is 6.99×103steps .

Explanation of Solution

Given information:

Mass of the woman is 55.0kg and energy in one doughnut is 540Calorie(540kcal) . The height of a single stair is 15.0cm . The efficiency of the human body to convert the energy into mechanical work is 25% .

Formula to calculate the mechanical work equivalent of potential energy is,

W=25%×ΔUtotal

  • W is the mechanical work equivalent of potential energy.

Formula to calculate the number of steps must climb to work off her breakfast is,

n=Wmgh

Substitute 25%×ΔUtotal for W in the above equation.

n=25%×ΔUtotalmgh

Substitute 2.26×106J for ΔUtotal , 55.0kg for m , 9.8m/s2 for g and 15.0cm for h to find n .

n=25100×2.26×106J55.0kg×9.8m/s2×(15.0cm×102m1cm)=6.99×103steps

Conclusion:

Therefore, the number of steps woman must climb to work off her breakfast is 6.99×103steps .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
You push a 33-kg table across a 6.2-m-wide room. In the process, 1.5 kJ of mechanical energy gets converted to internal energy of the table/floor system. What's the coefficient of kinetic friction between the table and floor?
A 46-kg woman eats a 522 Calorie (522 kcal) jelly doughnut for breakfast. (a) How many joules of energy are the equivalent of one jelly doughnut? 2192.4 X Your response is off by a multiple of ten. J (b) How many steps must the woman climb on a very tall stairway to change the gravitational potential energy of the woman-Earth system by a value equivalent to the food energy in one jelly doughnut? Assume the height of a single stair is 15 cm. 8.67 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. stairs (c) If the human body is only 26% efficient in converting chemical potential energy to mechanical energy, how many steps must the woman climb to work off her breakfast? 9 X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. stairs
A food calorie is a unit of energy such that 1 food calorie = 4184 J. This means that a person that burns energy with a power of 4184 W would burn one food calorie every second. A more typical human power rate is 90 W (called the basal metabolic rate). At this rate, how many calories are burned per second (or alternatively, how many seconds does it take to burn 1 calorie)?

Chapter 19 Solutions

Physics for Scientists and Engineers with Modern Physics

Ch. 19 - If water with a mass mk at temperature Tk is...Ch. 19 - Prob. 7PCh. 19 - An electric drill with a steel drill bit of mass m...Ch. 19 - Prob. 9PCh. 19 - How much energy is required to change a 40.0-g ice...Ch. 19 - Prob. 11PCh. 19 - Prob. 12PCh. 19 - In an insulated vessel, 250 g of ice at 0C is...Ch. 19 - Prob. 14PCh. 19 - One mole of an ideal gas is warmed slowly so that...Ch. 19 - (a) Determine the work done on a gas that expands...Ch. 19 - A thermodynamic system undergoes a process in...Ch. 19 - Prob. 18PCh. 19 - A 2.00-mol sample of helium gas initially at 300...Ch. 19 - (a) How much work is done on the steam when 1.00...Ch. 19 - A 1.00-kg block of aluminum is warmed at...Ch. 19 - In Figure P19.22, the change in internal energy of...Ch. 19 - Prob. 23PCh. 19 - A concrete slab is 12.0 cm thick and has an area...Ch. 19 - Two lightbulbs have cylindrical filaments much...Ch. 19 - Prob. 26PCh. 19 - (a) Calculate the R-value of a thermal window made...Ch. 19 - Prob. 28PCh. 19 - Gas in a container is at a pressure of 1.50 atm...Ch. 19 - Prob. 30APCh. 19 - You have a particular interest in automobile...Ch. 19 - Prob. 32APCh. 19 - Prob. 33APCh. 19 - Prob. 34APCh. 19 - Review. Following a collision between a large...Ch. 19 - Prob. 36APCh. 19 - An ice-cube tray is filled with 75.0 g of water....Ch. 19 - Prob. 38APCh. 19 - An iron plate is held against an iron wheel so...Ch. 19 - One mole of an ideal gas is contained in a...Ch. 19 - Prob. 41APCh. 19 - Prob. 42APCh. 19 - Prob. 43APCh. 19 - A student measures the following data in a...Ch. 19 - (a) The inside of a hollow cylinder is maintained...Ch. 19 - Prob. 46CPCh. 19 - Prob. 47CP
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College