Chapter 19, Problem 19.78SP

Interpretation Introduction

Interpretation:

“Energy released in the reaction” should be identified.

Conceptual Introduction:

The mass of an atomic nucleus is smaller than the sum of individual mass of protons and neutrons and this missing mass is known is called mass defect.

To find the mass defect following steps should be taken:

Step 1: Add mass of each proton and neutron that makes the nucleus.

Step 2: Subtract the actual mass of nucleus from the combined mass of protons and neutrons.

Given:

$\begin{array}{l}{\text{Atomic mass of}}^{\text{3}}\text{He = 3}\text{.0160u}\hfill \\ {\text{Atomic mass of }}^{\text{2}}\text{H = 2}\text{.0141u}\hfill \\ \text{Atomic mass of neutron = 1}\text{.00867u}\hfill \end{array}$

Solutions:

$\text{3}\text{.288MeV}$