Bundle: Physical Chemistry, 2nd + Student Solutions Manual
Bundle: Physical Chemistry, 2nd + Student Solutions Manual
2nd Edition
ISBN: 9781285257594
Author: David W. Ball
Publisher: Cengage Learning
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Chapter 19, Problem 19.70E
Interpretation Introduction

(a)

Interpretation:

Whether the diffusion of ammonia through an atmosphere of helium is faster or slower than through air in Example 19.9 is to be stated.

Concept introduction:

The mutual diffusion constant involves the three mean free paths, that is, between like gas particles and between the different gas particles. The mutual diffusion constant is given by,

D12=38RT2πμ1(r1+r2)2ρtot

Where,

D12 is the mutual diffusion constant.

μ is the reduced molar mass.

r1 and r2 are the radius of two particles 1 and 2

ρtot is the total particle density.

R is the gas constant.

T is the temperature.

The mutual diffusion constant does not depend on the mole fractions of the involved gases.

Interpretation Introduction

(b)

Interpretation:

Whether the diffusion of ammonia through an atmosphere of SF6 is faster or slower than through air in Example 19.9 is to be stated.

Concept introduction:

The mutual diffusion constant involves the three mean free paths, that is, between like gas particles and between the different gas particles. The mutual diffusion constant is given by,

D12=38RT2πμ1(r1+r2)2ρtot

Where,

D12 is the mutual diffusion constant.

μ is the reduced molar mass.

r1 and r2 are the radius of two particles 1 and 2

ρtot is the total particle density.

R is the gas constant.

T is the temperature.

The mutual diffusion constant does not depend on the mole fractions of the involved gases.

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Chapter 19 Solutions

Bundle: Physical Chemistry, 2nd + Student Solutions Manual

Ch. 19 - Prob. 19.11ECh. 19 - Interstellar space can be considered as having...Ch. 19 - Prob. 19.13ECh. 19 - SF6 is a gas at room temperature, 295K. What is...Ch. 19 - Prob. 19.15ECh. 19 - Prob. 19.16ECh. 19 - If relativistic effects were ignored, what...Ch. 19 - Prob. 19.18ECh. 19 - Prob. 19.19ECh. 19 - Prob. 19.20ECh. 19 - Prob. 19.21ECh. 19 - Prob. 19.22ECh. 19 - Prob. 19.23ECh. 19 - Prob. 19.24ECh. 19 - What is the ratio of vrms/vmostprob for any gas at...Ch. 19 - Prob. 19.26ECh. 19 - Prob. 19.27ECh. 19 - Prob. 19.28ECh. 19 - Prob. 19.29ECh. 19 - Prob. 19.30ECh. 19 - Prob. 19.31ECh. 19 - The previous exercise gives an expression for...Ch. 19 - Prob. 19.33ECh. 19 - Prob. 19.34ECh. 19 - Prob. 19.35ECh. 19 - What must the pressure be if the mean free path of...Ch. 19 - Prob. 19.37ECh. 19 - Prob. 19.38ECh. 19 - Prob. 19.39ECh. 19 - Explain why the molecular diameter for argon, at...Ch. 19 - Prob. 19.41ECh. 19 - Prob. 19.42ECh. 19 - Prob. 19.43ECh. 19 - A 1.00-mol sample of Xe gas is kept at a...Ch. 19 - Prob. 19.45ECh. 19 - Prob. 19.46ECh. 19 - Prob. 19.47ECh. 19 - Prob. 19.48ECh. 19 - Prob. 19.49ECh. 19 - Consider a gas mixture containing equal...Ch. 19 - The inverse of the collision rate, 1/z, is the...Ch. 19 - Prob. 19.52ECh. 19 - Prob. 19.53ECh. 19 - Prob. 19.54ECh. 19 - Prob. 19.55ECh. 19 - Estimate the rate at which Hg effuses out a hole...Ch. 19 - Prob. 19.57ECh. 19 - Knudsen effusion cells are used to determine vapor...Ch. 19 - Prob. 19.59ECh. 19 - Prob. 19.60ECh. 19 - Prob. 19.61ECh. 19 - Prob. 19.62ECh. 19 - Prob. 19.63ECh. 19 - Prob. 19.64ECh. 19 - Prob. 19.65ECh. 19 - Prob. 19.66ECh. 19 - Prob. 19.67ECh. 19 - Prob. 19.68ECh. 19 - Prob. 19.69ECh. 19 - Prob. 19.70ECh. 19 - Prob. 19.71ECh. 19 - Prob. 19.72ECh. 19 - Prob. 19.73E
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