Chapter 19, Problem 19.5P

(a)

Interpretation Introduction

Interpretation:

The equilibrium constant expression for the equation ${\text{SO}}_{\text{2}}{\text{Cl}}_{\text{2(g)}}\rightleftharpoons {\text{ SO}}_{\text{2}}{}_{\text{(g)}}{\text{ + Cl}}_{\text{2(g)}}$ has to be written and also the unit of ${\text{K}}_{\text{c}}$ has to be given.

Concept Introduction:

Equilibrium constant: At equilibrium the ratio of products to reactants (each raised to the power corresponding to its stoichiometric coefficient) has a constant value, K

For a general reaction,

  $\text{aA+bB}\rightleftarrows \text{cC+dD}$

  $\text{Equilibrium}\text{constant}\text{K}\text{=}\frac{{\left[\text{C}\right]}^{\text{c}}{\left[\text{D}\right]}^{\text{d}}}{{\left[\text{A}\right]}^{\text{a}}{\left[\text{B}\right]}^{\text{b}}}$

The concentration of solids and pure liquids do not change, so their concentration terms are not included in the equilibrium constant expression.

(b)

Interpretation Introduction

Interpretation:

The equilibrium constant expression for the equation ${\text{2H}}_{\text{2}}{\text{O}}_{\text{2(g)}}\rightleftharpoons {\text{ 2H}}_{\text{2}}{\text{O}}_{\text{(l)}}{\text{ + O}}_{\text{2(g)}}$ has to be written and also the unit of ${\text{K}}_{\text{c}}$ has to be given.

Concept Introduction:

Refer part (a)

(c)

Interpretation Introduction

Interpretation:

The equilibrium constant expression for the equation ${\text{2CaSO}}_{\text{4}}·{\text{H}}_{\text{2}}{\text{O}}_{\text{(s)}}{\text{ + 2H}}_{\text{2}}{\text{O}}_{\text{(g)}}\rightleftharpoons 2{\text{CaSO}}_{\text{4}}·{\text{2H}}_{\text{2}}{\text{O}}_{\text{(s)}}$ has to be written and also the unit of ${\text{K}}_{\text{c}}$ has to be given.

Concept Introduction:

Refer part (a).