Chapter 19, Problem 19.49P

(a)

Interpretation Introduction

Interpretation:

When ${\text{[SO}}_{\text{2}}\text{] = 0}\text{.40 M}$, ${\text{[O}}_{\text{2}}\text{] = 0}\text{.20 M}$ and ${\text{[SO}}_3\text{] = 0}\text{.10 M}$, the direction to which the reaction will proceed to attain equilibrium for the given reaction has to be given.

Concept Introduction:

Comparison of ${\text{Q}}_{\text{c}}{\text{ and K}}_{\text{c}}$ :

When ${\text{Q}}_{\text{c}}{\text{ < K}}_{\text{c}}$, the reaction will proceed in right direction, $\text{reactants}\stackrel{}{\to }\text{products}$

When ${\text{Q}}_{\text{c}}{\text{ > K}}_{\text{c}}$, the reaction will proceed in left direction, $\text{reactants}\stackrel{}{\leftarrow }\text{products}$

When ${\text{Q}}_{\text{c}}{\text{ = K}}_{\text{c}}$, the reaction will remain unchanged, $\text{reactants}\stackrel{}{\rightleftharpoons }\text{products}$

(b)

Interpretation Introduction

Interpretation:

When ${\text{[SO}}_{\text{2}}\text{] = 0}\text{.05 M}$, ${\text{[O}}_{\text{2}}\text{] = 0}\text{.10 M}$ and ${\text{[SO}}_3\text{] = 0}\text{.30 M}$, the direction to which the reaction will proceed to attain equilibrium for the given reaction has to be given.

Concept Introduction:

Refer part (a)