Chapter 19, Problem 19.22P

Interpretation Introduction

Interpretation:

To calculate the mass defect for the formation of $\text{U-235}$ and the binding energy

Concept Introduction:
Nucleus of an atom consists of protons and neutrons. It has been observed that the rest mass of the nucleus is always less than the mass of the free nucleons (sum of the mass of the protons and neutrons). This difference in mass is termed as Mass defect. It is represented by the symbol $\text{ΔM}$

Binding energy is the energy required to bind the nucleons in the nucleus, i.e. , this amount of energy is supplied, the nucleus will break into free nucleons.
Binding energy and mass defect is related by:
$\text{Binding Energy (B}\text{.E) = }\Delta M\times c^2$ , where $\text{ΔM}$ is the mass defect in amu, c is the speed of light in ${\text{m s}}^{-1}$ and B.E is obtained in $\text{eV}$.
We know that, $\text{1 eV= 1}{\text{.6 × 10}}^{\text{-19}}\text{J}$ , $\text{1}\text{amu=1}{\text{.66053904 × 10}}^{\text{-27}}\text{ kg}$ and ${\text{1 J= 1 kg m}}^{\text{2}}{\text{ s}}^{\text{-2}}$

  

Given:

  $\text{Mass of }\text{U}\text{ nucleus =235}\text{.0439299 u}$

  $\text{Mass of a proton =1}\text{.00728 u}$

  $\text{Mass of a neutron =1}\text{.00867 u}$