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(a)
Interpretation: A proposed mechanism of a destruction of ozone in upper atmosphere and the first step mechanism for the chlorine catalyzed ozone destruction are given. The answers are to be stated for the given options.
Concept introduction: The substance that speeds up the
The intermediates are the transient species that is capable to produce the desired product directly.
To determine: The overall balanced equation for the destruction of ozone.
(b)
Interpretation: A proposed mechanism of a destruction of ozone in upper atmosphere and the first step mechanism for the chlorine catalyzed ozone destruction are given. The answers are to be stated for the given options.
Concept introduction: The substance that speeds up the rate of reaction without getting consumed itself in a chemical reaction is known as catalyst.
The intermediates are the transient species that is capable to produce the desired product directly.
To determine: The catalyst in the mechanism for the destruction of ozone in upper atmosphere.
(c)
Interpretation: A proposed mechanism of a destruction of ozone in upper atmosphere and the first step mechanism for the chlorine catalyzed ozone destruction are given. The answers are to be stated for the given options.
Concept introduction: The substance that speeds up the rate of reaction without getting consumed itself in a chemical reaction is known as catalyst.
The intermediates are the transient species that is capable to produce the desired product directly.
To determine: The intermediate in the mechanism of a destruction of ozone in upper atmosphere.
(d)
Interpretation: A proposed mechanism of a destruction of ozone in upper atmosphere and the first step mechanism for the chlorine catalyzed ozone destruction are given. The answers are to be stated for the given options.
Concept introduction: The substance that speeds up the rate of reaction without getting consumed itself in a chemical reaction is known as catalyst.
The intermediates are the transient species that is capable to produce the desired product directly.
To determine: The rate law, if first step is slow and second step is fast.
(e)
Interpretation: A proposed mechanism of a destruction of ozone in upper atmosphere and the first step mechanism for the chlorine catalyzed ozone destruction are given. The answers are to be stated for the given options.
Concept introduction: The substance that speeds up the rate of reaction without getting consumed itself in a chemical reaction is known as catalyst.
The intermediates are the transient species that is capable to produce the desired product directly.
To determine: The second step in the mechanism for chlorine catalyzed ozone destruction and the overall balanced equation.
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Chapter 19 Solutions
EBK CHEMISTRY: AN ATOMS FIRST APPROACH
- Could you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but (color-coded) and step by step so I can understand it better? Thank you! I want to see what they are doingarrow_forward
- Can you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.arrow_forwardPart 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answerarrow_forwardPart 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet. water and benzene. What is the formal concentration of butanoic acid in each phase when 0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene 100 mL of a) at pit 5.00 b) at pH 9.00arrow_forward
- Calculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 Group of answer choices 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 choices: 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0arrow_forward
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