Bundle: Chemistry: The Molecular Science, 5th, Loose-Leaf + OWLv2 with Quick Prep 24-Months Printed Access Card
5th Edition
ISBN: 9781305367487
Author: John W. Moore, Conrad L. Stanitski
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 19, Problem 100QRT
(a)
Interpretation Introduction
Interpretation:
Drinking milk by babies help them to produce strong teeth has to be explained using the dissociation equation.
(b)
Interpretation Introduction
Interpretation:
Inhibition of strong teeth formation by lactic acid has to be explained.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Write the equilibrium constant expression for this reaction:
2 H(aq) +SO² (aq) → H₂SO4(ªq)
4
Propionic acid, HC3H5O2, has Ka= 1.34 x 10–5.
(a) What is the molar concentration of H3O+ in 0.15 M HC3H5O2 and the pH of the solution?
(b) What is the Kb value for the propionate ion, C3H5O2–?
(c) Calculate the pH of 0.15 M solution of sodium propionate, NaC3H5O2.
(d) Calculate the pH of solution that contains 0.12 M HC3H5O2 and 0.25 M NaC3H5O2.
Write the equilibrium constant expression for this reaction:
H;PO,(aq) - 3 H (aq)+PO (aq)
?
Chapter 19 Solutions
Bundle: Chemistry: The Molecular Science, 5th, Loose-Leaf + OWLv2 with Quick Prep 24-Months Printed Access Card
Ch. 19.1 - Prob. 19.1ECh. 19.1 - Prob. 19.2ECh. 19.2 - Prob. 19.3CECh. 19.2 - Prob. 19.4CECh. 19.3 - Prob. 19.5ECh. 19.4 - Prob. 19.1PSPCh. 19.4 - Prob. 19.6ECh. 19.4 - Prob. 19.7ECh. 19.4 - Prob. 19.2PSPCh. 19.5 - Prob. 19.8CE
Ch. 19.5 - Prob. 19.9ECh. 19.5 - Prob. 19.3PSPCh. 19.5 - Use the terms oxidation, reduction, oxidizing...Ch. 19.5 - Prob. 19.11ECh. 19.6 - Prob. 19.13ECh. 19.6 - Prob. 19.14ECh. 19.6 - Prob. 19.15CECh. 19.6 - Prob. 19.16CECh. 19.6 - Prob. 19.4PSPCh. 19.6 - Prob. 19.5PSPCh. 19.6 - Prob. 19.17ECh. 19.6 - Prob. 19.6PSPCh. 19.6 - Prob. 19.7PSPCh. 19.6 - Prob. 19.8PSPCh. 19 - Prob. 1QRTCh. 19 - Prob. 2QRTCh. 19 - Prob. 3QRTCh. 19 - Prob. 4QRTCh. 19 - Prob. 5QRTCh. 19 - Prob. 6QRTCh. 19 - Prob. 7QRTCh. 19 - Prob. 8QRTCh. 19 - Prob. 9QRTCh. 19 - Prob. 10QRTCh. 19 - Prob. 11QRTCh. 19 - Prob. 12QRTCh. 19 - Prob. 13QRTCh. 19 - Prob. 14QRTCh. 19 - Prob. 15QRTCh. 19 - Prob. 16QRTCh. 19 - Prob. 17QRTCh. 19 - Prob. 18QRTCh. 19 - Prob. 19QRTCh. 19 - Prob. 20QRTCh. 19 - Prob. 21QRTCh. 19 - Prob. 22QRTCh. 19 - Prob. 23QRTCh. 19 - Prob. 24QRTCh. 19 - Prob. 25QRTCh. 19 - Prob. 26QRTCh. 19 - Identify the substance or substances produced by...Ch. 19 - Prob. 28QRTCh. 19 - Prob. 29QRTCh. 19 - Prob. 30QRTCh. 19 - Prob. 31QRTCh. 19 - Prob. 32QRTCh. 19 - Prob. 33QRTCh. 19 - Prob. 34QRTCh. 19 - Prob. 35QRTCh. 19 - Prob. 36QRTCh. 19 - Prob. 37QRTCh. 19 - Prob. 38QRTCh. 19 - Prob. 39QRTCh. 19 - Prob. 40QRTCh. 19 - Prob. 41QRTCh. 19 - Prob. 42QRTCh. 19 - A human body contains approximately 5 L of blood....Ch. 19 - Prob. 44QRTCh. 19 - Prob. 45QRTCh. 19 - Prob. 46QRTCh. 19 - Prob. 47QRTCh. 19 - Prob. 48QRTCh. 19 - Prob. 49QRTCh. 19 - Prob. 50QRTCh. 19 - Prob. 51QRTCh. 19 - Prob. 52QRTCh. 19 - Prob. 53QRTCh. 19 - Prob. 54QRTCh. 19 - Prob. 55QRTCh. 19 - Prob. 56QRTCh. 19 - Prob. 57QRTCh. 19 - Prob. 58QRTCh. 19 - Prob. 59QRTCh. 19 - Prob. 60QRTCh. 19 - Prob. 61QRTCh. 19 - Prob. 62QRTCh. 19 - Prob. 63QRTCh. 19 - Prob. 64QRTCh. 19 - Prob. 65QRTCh. 19 - Prob. 66QRTCh. 19 - Prob. 67QRTCh. 19 - Prob. 68QRTCh. 19 - Prob. 69QRTCh. 19 - Prob. 70QRTCh. 19 - Prob. 71QRTCh. 19 - Prob. 72QRTCh. 19 - Prob. 73QRTCh. 19 - Prob. 74QRTCh. 19 - Use the phase diagram for sulfur for Question 75....Ch. 19 - Prob. 76QRTCh. 19 - Prob. 77QRTCh. 19 - Prob. 78QRTCh. 19 - Prob. 79QRTCh. 19 - Prob. 80QRTCh. 19 - A natural brine found in Arkansas has a bromide...Ch. 19 - Prob. 82QRTCh. 19 - Prob. 83QRTCh. 19 - Prob. 84QRTCh. 19 - At 20. C the vapor pressure of white phosphorus is...Ch. 19 - Prob. 86QRTCh. 19 - Assume that the radius of Earth is 6400 km, the...Ch. 19 - Prob. 88QRTCh. 19 - Prob. 89QRTCh. 19 - Prob. 90QRTCh. 19 - Prob. 91QRTCh. 19 - Prob. 92QRTCh. 19 - Prob. 93QRTCh. 19 - Prob. 94QRTCh. 19 - Prob. 95QRTCh. 19 - Use a Born-Haber cycle (Sec. 5-13) to calculate...Ch. 19 - Prob. 97QRTCh. 19 - Elemental analysis of a borane indicates this...Ch. 19 - Prob. 99QRTCh. 19 - Prob. 100QRT
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- The hydrogen phthalate ion, C8HsO4, is a weak acid with Ka = 3.91 106. C8H5O4(aq)+H2O(l)C8H4O42(aq)+H3O+(aq) What is the pH of a 0.050 M solution of potassium hydrogen phthalate. KC8H5O4? Note: To find the pH for a solution of the anion, we must take into account that the ion is amphiprotic. It can be shown that, for most cases of amphiprotic ions, the H3O+ concentration is [H3O+]=Ka1Ka2 For phthalic acid, C8H6O4 is Ka1 is 1.12 103, and Ka2 is 3.91 106.arrow_forwardWrite the chemical equation and the expression for the equilibrium constant, and calculate Kb for the reaction of each of the following ions as a base. (a) sulfate ion (b) citrate ionarrow_forwardPhenol, C6H5OH, is a weak organic acid. Suppose 0.515 g of the compound is dissolved in enough water to make 125 mL of solution. The resulting solution is titrated with 0.123 M NaOH. C6H5OH(aq) + OH(aq) C6H5O(aq) + H2O() (a) What is the pH of the original solution of phenol? (b) What are the concentrations of all of the following ions at the equivalence point: Na+, H3O+, OH, and C6H5O? (c) What is the pH of the solution at the equivalence point?arrow_forward
- Write a balanced molecular equation for the preparation of each of the following salts, using an acidbase neutralization reaction. a. LiNO3 (lithium nitrate) b. BaCl2 (barium chloride) c. K3PO4 (potassium phosphate) d. Na2SO4 (sodium sulfate)arrow_forwardA chemist wanted to determine the concentration of a solution of lactic acid, HC3H5O3. She found that the pH of the solution was 2.60. What was the concentration of the solution? The Kd of lactic acid is 1.4 104.arrow_forwardConsider the following ions: NH4+, CO32, Br, S2, and ClO4. (a) Which of these ions in water gives an acidic solution and which gives a basic solution? (b) Which of these anions will have no effect on the pH of an aqueous solution? (c) Which ion is the strong base? (d) Write a chemical equation for the reaction of each basic anion with water.arrow_forward
- Sodium bicarbonate, NaHCO3, is used in baking powder formulations and in the manufacture of plastics and ceramics, among other things. If 26.3 g of the compound is dissolved in enough water to make 200. mL of solution, what is the concentration of NaHCO3? What are the concentrations of the ions in solution?arrow_forwardThe simplest amino acid is glycine, H2NCH2CO2H. The common feature of amino acids is that they contain the functional groups: an amine group, -NH2, and a carboxylic acid group, -CO2H. An amino acid can function as either an acid or a base. For glycine, the acid strength of the carboxyl group is about the same as that of acetic acid. CH3CO2H, and the base strength of the amino group is slightly greater than that of ammonia, NH3. (a) Write the Lewis structures of the ions that form when glycine is dissolved in 1 M HCl and in 1 M KOH. (b) Write the Lewis structure of glycine when this amino acid is dissolved in water. (Hint: Consider the relative base strengths of the -NH2 and -CO2- groups.)arrow_forwardFor conjugate acidbase pairs, how are Ka and Kb related? Consider the reaction of acetic acid in water CH3CO2H(aq)+H2O(l)CH3CO2(aq)+H3O+(aq) where Ka = 1.8 105 a. Which two bases are competing for the proton? b. Which is the stronger base? c. In light of your answer to part b. why do we classify the acetate ion (CH3CO2) as a weak base? Use an appropriate reaction to justify your answer. In general, as base strength increases, conjugate acid strength decreases. Explain why the conjugate acid of the weak base NH3 is a weak acid. To summarize, the conjugate base of a weak acid is a weak base and the conjugate acid of a weak base is a weak acid (weak gives you weak). Assuming Ka for a monoprotic strong acid is 1 106, calculate Kb for the conjugate base of this strong acid. Why do conjugate bases of strong acids have no basic properties in water? List the conjugate bases of the six common strong acids. To tie it all together, some instructors have students think of Li+, K+, Rb+, Cs+, Ca2+, Sr2+, and Ba2+ as the conjugate acids of the strong bases LiOH, KOH. RbOH, CsOH, Ca(OH)2, Sr(OH)2, and Ba(OH)2. Although not technically correct, the conjugate acid strength of these cations is similar to the conjugate base strength of the strong acids. That is, these cations have no acidic properties in water; similarly, the conjugate bases of strong acids have no basic properties (strong gives you worthless). Fill in the blanks with the correct response. The conjugate base of a weak acid is a_____base. The conjugate acid of a weak base is a_____acid. The conjugate base of a strong acid is a_____base. The conjugate acid of a strong base is a_____ acid. (Hint: Weak gives you weak and strong gives you worthless.)arrow_forward
- Both ions in the salt ammonium acetate (NH4C2H3O2) hydrolyze in aqueous solution. Explain why this hydrolysis produces a neutral solution rather than an acidic or basic solution.arrow_forwardThe pigment cyanidin aglycone is one of the anthocyanin molecules that gives red cabbage (Brassica oleracea var. capitata f. rubra) its characteristic red coloration. Many chemistry students have used this red cabbage indicator to study acid-base chemistry. Estimate tire pH range at which cyanidin agly-cone shows a color change. Anth-H(aq) Anth(aq) + H+ (aq) Ka = 1.3 107arrow_forwardWrite an equation for each of the following buffering actions. a. the response of a HPO42/PO43 buffer to the addition of OH ions b. the response of a HF/F buffer to the addition of OH ions c. the response of a HCN/CN buffer to the addition of H3O+ ions d. the response of a H3PO4/H2PO4 buffer to the addition of H3O+ ionsarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningGeneral, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
General, Organic, and Biological Chemistry
Chemistry
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Chemical Equilibria and Reaction Quotients; Author: Professor Dave Explains;https://www.youtube.com/watch?v=1GiZzCzmO5Q;License: Standard YouTube License, CC-BY